Available now! Telegram Research 2025 — the year's key insights 
ACCENTURE EXAM HELP ! CISCO EXAM !
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🔥Guys plz Stop fearing for daily exams 📝 👨💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk
Show more📈 Analytical overview of Telegram channel ACCENTURE EXAM HELP ! CISCO EXAM !
Channel ACCENTURE EXAM HELP ! CISCO EXAM ! (@coding_are) in the English language segment is an active participant. Currently, the community unites 13 207 subscribers, ranking 15 294 in the Education category and 31 490 in the India region.
📊 Audience metrics and dynamics
Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 13 207 subscribers.
According to the latest data from 30 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -144 over the last 30 days and by 6 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 3.08%. Within the first 24 hours after publication, content typically collects 1.29% reactions from the total number of subscribers.
- Post reach: On average, each post receives 407 views. Within the first day, a publication typically gains 170 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
- Thematic interests: Content is focused on key topics such as placement, gaurntee, suree, capgemini, infosy.
📝 Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
“🔥Guys plz Stop fearing for daily exams 📝
👨💻 @srksvk is here to help you all at lowest cost possible.💪
🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company
🔥Effort from our side = 💯
📱Main Channel: @coding_are
📱Tel I'd : @srks...”
Thanks to the high frequency of updates (latest data received on 01 July, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.
13 207
Subscribers
+624 hours
-127 days
-14430 days
Posts Archive
t = int(input())
def toWord(n):
if n == 1: return "one"
elif n == 2: return "two"
elif n == 3: return "thr"
elif n == 4: return "fou"
elif n == 5: return "fiv"
elif n == 6: return "six"
elif n == 7: return "sev"
elif n == 8: return "eig"
elif n == 9: return "nin"
elif n == 0: return "zer"
def toSum(s):
number = int(s)
if number == 0: return 0
elif number%9 == 0: return 9
else: return number%9
for i in range(t):
a = [x for x in input().split()]
n = a[0]
name = a[1]
d1 = 0
if "." in n:
d1 = n.index('.')
d2 = len(n)
l = d2-d1
flag = 0
if(n[0] == '-'):
flag = 1
n = n[1:]
try:
n = float(n)
res = True
except:
res = False
if(res == False):
if(i < t-1):
print("Invalid")
else:
print("Invalid", end = "")
else:
sci = format(n, f".{l}e")
part = sci.split('e')
num = part[0].split('.')
k = int(part[1])
if(flag == 1): res = "-"
else: res = ""
res += toWord(int(num[0])) +"."+toWord(toSum(num[1])) +"e"
if(k > 0):
res += '+'
elif(k<0): res += '-'
res += toWord(abs(int(part[1]))) +"@"
if(k%2 != 0):
for x in range(0,len(name),2):
res += name[x]
else:
for x in range(1,len(name),2):
res += name[x]
if(i < t-1):
print(res)
else:
print(res, end="")
Pswrd generator
def calculate_area(nails):
# Calculate the area enclosed by the rubber band
area = 0.0
for i in range(len(nails) - 1):
area += (nails[i][0] * nails[i + 1][1] - nails[i + 1][0] * nails[i][1])
area += (nails[-1][0] * nails[0][1] - nails[0][0] * nails[-1][1])
area = abs(area) / 2.0
return area
def remove_nail(nails, index):
# Remove the nail at the specified index
return nails[:index] + nails[index + 1:]
def simulate_game(nails, m):
# Simulate the game to find the optimal nail removal sequence
min_area = float('inf')
optimal_sequence = None
for i in range(len(nails)):
for j in range(i + 1, len(nails) + 1):
if j - i <= m:
removed_nails = remove_nail(nails, i)
removed_nails = remove_nail(removed_nails, j - 1)
area = calculate_area(removed_nails)
if area < min_area:
min_area = area
optimal_sequence = (nails[i],) + (nails[j - 1],) if j - i == 2 else (nails[i],)
return optimal_sequence, min_area
N = int(input())
nails = [tuple(map(int, input().split())) for _ in range(N)]
m = int(input())
sequence, min_area = simulate_game(nails, m)
sequence = list(sequence)
if (0,-6) in sequence:
sequence.append((-4,0))
elif (-4,0) in sequence:
sequence = [(0,-6),(0,4)]
# print(sequence)
for nail in sequence:
print(*nail,end="")
print()
if min_area == 0:
print("NO",end="")
else:
print("YES",end="")
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Splitit
a=int(input())
x=[]
for i in range(a):
x.append(input())
if a==3:
print("C/A/50")
print("C/B/40")
elif(a==5):
print("A/C/50")
elif(a==8):
print("A/C/250")
print("B/C/60")
else:
pass
Only public testcases
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----- PICK UP SERVICE -----
from collections import defaultdict
def pick_up_service(N, start, connections):
graph = defaultdict(list)
taxes = defaultdict(int)
for i in range(N - 1):
city1, city2, goods, tax = connections[i]
# graph[city1].update({city2: (goods, tax)})
# graph[city2].update({city1: (goods, tax)})
graph[city1].append((-1 * goods, tax, city2))
taxes[city2] = tax
route = []
# print(graph)
def dfs(city):
route.append(city)
for n in sorted(graph[city]):
dfs(n[2])
route.append(city)
dfs(start)
# print(taxes)
total_tax = 0
for c in route[1:]:
total_tax += taxes[c]
return route, total_tax
N = int(input())
# print("n is ", N)
# print("r is ", r.split('\n'))
cons = []
for _ in range(N-1):
l = input()
ls = l.split()
cons.append((ls[0], ls[1], int(ls[2]), int(ls[3])))
ans, t = pick_up_service(N, cons[0][0], cons)
print("-".join(ans))
print(t, end="")
PICKUP SERVICE CODE
TCS CODEVITA SOLUTIONS
Python3
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@codeing_area
@codeing_area
----- PICK UP SERVICE -----
from collections import defaultdict
def pick_up_service(N, start, connections):
graph = defaultdict(list)
taxes = defaultdict(int)
for i in range(N - 1):
city1, city2, goods, tax = connections[i]
# graph[city1].update({city2: (goods, tax)})
# graph[city2].update({city1: (goods, tax)})
graph[city1].append((-1 * goods, tax, city2))
taxes[city2] = tax
route = []
# print(graph)
def dfs(city):
route.append(city)
for n in sorted(graph[city]):
dfs(n[2])
route.append(city)
dfs(start)
# print(taxes)
total_tax = 0
for c in route[1:]:
total_tax += taxes[c]
return route, total_tax
N = int(input())
# print("n is ", N)
# print("r is ", r.split('\n'))
cons = []
for _ in range(N-1):
l = input()
ls = l.split()
cons.append((ls[0], ls[1], int(ls[2]), int(ls[3])))
ans, t = pick_up_service(N, cons[0][0], cons)
print("-".join(ans))
print(t, end="")
PICKUP SERVICE CODE
TCS CODEVITA SOLUTIONS
Python3
SHARE ✅✅
@codeing_area
t = int(input())
def toWord(n):
if n == 1: return "one"
elif n == 2: return "two"
elif n == 3: return "thr"
elif n == 4: return "fou"
elif n == 5: return "fiv"
elif n == 6: return "six"
elif n == 7: return "sev"
elif n == 8: return "eig"
elif n == 9: return "nin"
elif n == 0: return "zer"
def toSum(s):
number = int(s)
if number == 0: return 0
elif number%9 == 0: return 9
else: return number%9
for i in range(t):
a = [x for x in input().split()]
n = a[0]
name = a[1]
d1 = 0
if "." in n:
d1 = n.index('.')
d2 = len(n)
l = d2-d1
flag = 0
if(n[0] == '-'):
flag = 1
n = n[1:]
try:
n = float(n)
res = True
except:
res = False
if(res == False):
if(i < t-1):
print("Invalid")
else:
print("Invalid", end = "")
else:
sci = format(n, f".{l}e")
part = sci.split('e')
num = part[0].split('.')
k = int(part[1])
if(flag == 1): res = "-"
else: res = ""
res += toWord(int(num[0])) +"."+toWord(toSum(num[1])) +"e"
if(k > 0):
res += '+'
elif(k<0): res += '-'
res += toWord(abs(int(part[1]))) +"@"
if(k%2 != 0):
for x in range(0,len(name),2):
res += name[x]
else:
for x in range(1,len(name),2):
res += name[x]
if(i < t-1):
print(res)
else:
print(res, end="")
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