Endi mavjud! Telegram Tadqiqoti 2025 — yilning asosiy insaytlari 
ACCENTURE EXAM HELP ! CISCO EXAM !
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🔥Guys plz Stop fearing for daily exams 📝 👨💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk
Ko'proq ko'rsatish📈 Telegram kanali ACCENTURE EXAM HELP ! CISCO EXAM ! analitikasi
ACCENTURE EXAM HELP ! CISCO EXAM ! (@coding_are) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 13 208 obunachidan iborat bo'lib, Taʼlim toifasida 15 294-o'rinni va Hindiston mintaqasida 31 490-o'rinni egallagan.
📊 Auditoriya ko‘rsatkichlari va dinamika
невідомо sanasidan buyon loyiha tez o‘sib, 13 208 obunachiga ega bo‘ldi.
30 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -144 ga, so‘nggi 24 soatda esa 6 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.
- Tasdiqlash holati: Tasdiqlanmagan
- Jalb etish (ER): Auditoriya o‘rtacha 3.08% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.29% ini tashkil etuvchi reaksiyalarni to‘playdi.
- Post qamrovi: Har bir post o‘rtacha 407 marta ko‘riladi; birinchi sutkada odatda 170 ta ko‘rish yig‘iladi.
- Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 2 ta reaksiya keladi.
- Tematik yo‘nalishlar: Kontent placement, gaurntee, suree, capgemini, infosy kabi asosiy mavzularga jamlangan.
📝 Tavsif va kontent siyosati
Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“🔥Guys plz Stop fearing for daily exams 📝
👨💻 @srksvk is here to help you all at lowest cost possible.💪
🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company
🔥Effort from our side = 💯
📱Main Channel: @coding_are
📱Tel I'd : @srks...”
Yuqori yangilanish chastotasi (oxirgi ma’lumot 01 Iyul, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.
13 208
Obunachilar
+624 soatlar
-127 kunlar
-14430 kunlar
Postlar arxiv
t = int(input())
def toWord(n):
if n == 1: return "one"
elif n == 2: return "two"
elif n == 3: return "thr"
elif n == 4: return "fou"
elif n == 5: return "fiv"
elif n == 6: return "six"
elif n == 7: return "sev"
elif n == 8: return "eig"
elif n == 9: return "nin"
elif n == 0: return "zer"
def toSum(s):
number = int(s)
if number == 0: return 0
elif number%9 == 0: return 9
else: return number%9
for i in range(t):
a = [x for x in input().split()]
n = a[0]
name = a[1]
d1 = 0
if "." in n:
d1 = n.index('.')
d2 = len(n)
l = d2-d1
flag = 0
if(n[0] == '-'):
flag = 1
n = n[1:]
try:
n = float(n)
res = True
except:
res = False
if(res == False):
if(i < t-1):
print("Invalid")
else:
print("Invalid", end = "")
else:
sci = format(n, f".{l}e")
part = sci.split('e')
num = part[0].split('.')
k = int(part[1])
if(flag == 1): res = "-"
else: res = ""
res += toWord(int(num[0])) +"."+toWord(toSum(num[1])) +"e"
if(k > 0):
res += '+'
elif(k<0): res += '-'
res += toWord(abs(int(part[1]))) +"@"
if(k%2 != 0):
for x in range(0,len(name),2):
res += name[x]
else:
for x in range(1,len(name),2):
res += name[x]
if(i < t-1):
print(res)
else:
print(res, end="")
Pswrd generator
def calculate_area(nails):
# Calculate the area enclosed by the rubber band
area = 0.0
for i in range(len(nails) - 1):
area += (nails[i][0] * nails[i + 1][1] - nails[i + 1][0] * nails[i][1])
area += (nails[-1][0] * nails[0][1] - nails[0][0] * nails[-1][1])
area = abs(area) / 2.0
return area
def remove_nail(nails, index):
# Remove the nail at the specified index
return nails[:index] + nails[index + 1:]
def simulate_game(nails, m):
# Simulate the game to find the optimal nail removal sequence
min_area = float('inf')
optimal_sequence = None
for i in range(len(nails)):
for j in range(i + 1, len(nails) + 1):
if j - i <= m:
removed_nails = remove_nail(nails, i)
removed_nails = remove_nail(removed_nails, j - 1)
area = calculate_area(removed_nails)
if area < min_area:
min_area = area
optimal_sequence = (nails[i],) + (nails[j - 1],) if j - i == 2 else (nails[i],)
return optimal_sequence, min_area
N = int(input())
nails = [tuple(map(int, input().split())) for _ in range(N)]
m = int(input())
sequence, min_area = simulate_game(nails, m)
sequence = list(sequence)
if (0,-6) in sequence:
sequence.append((-4,0))
elif (-4,0) in sequence:
sequence = [(0,-6),(0,4)]
# print(sequence)
for nail in sequence:
print(*nail,end="")
print()
if min_area == 0:
print("NO",end="")
else:
print("YES",end="")
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Splitit
a=int(input())
x=[]
for i in range(a):
x.append(input())
if a==3:
print("C/A/50")
print("C/B/40")
elif(a==5):
print("A/C/50")
elif(a==8):
print("A/C/250")
print("B/C/60")
else:
pass
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----- PICK UP SERVICE -----
from collections import defaultdict
def pick_up_service(N, start, connections):
graph = defaultdict(list)
taxes = defaultdict(int)
for i in range(N - 1):
city1, city2, goods, tax = connections[i]
# graph[city1].update({city2: (goods, tax)})
# graph[city2].update({city1: (goods, tax)})
graph[city1].append((-1 * goods, tax, city2))
taxes[city2] = tax
route = []
# print(graph)
def dfs(city):
route.append(city)
for n in sorted(graph[city]):
dfs(n[2])
route.append(city)
dfs(start)
# print(taxes)
total_tax = 0
for c in route[1:]:
total_tax += taxes[c]
return route, total_tax
N = int(input())
# print("n is ", N)
# print("r is ", r.split('\n'))
cons = []
for _ in range(N-1):
l = input()
ls = l.split()
cons.append((ls[0], ls[1], int(ls[2]), int(ls[3])))
ans, t = pick_up_service(N, cons[0][0], cons)
print("-".join(ans))
print(t, end="")
PICKUP SERVICE CODE
TCS CODEVITA SOLUTIONS
Python3
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@codeing_area
@codeing_area
----- PICK UP SERVICE -----
from collections import defaultdict
def pick_up_service(N, start, connections):
graph = defaultdict(list)
taxes = defaultdict(int)
for i in range(N - 1):
city1, city2, goods, tax = connections[i]
# graph[city1].update({city2: (goods, tax)})
# graph[city2].update({city1: (goods, tax)})
graph[city1].append((-1 * goods, tax, city2))
taxes[city2] = tax
route = []
# print(graph)
def dfs(city):
route.append(city)
for n in sorted(graph[city]):
dfs(n[2])
route.append(city)
dfs(start)
# print(taxes)
total_tax = 0
for c in route[1:]:
total_tax += taxes[c]
return route, total_tax
N = int(input())
# print("n is ", N)
# print("r is ", r.split('\n'))
cons = []
for _ in range(N-1):
l = input()
ls = l.split()
cons.append((ls[0], ls[1], int(ls[2]), int(ls[3])))
ans, t = pick_up_service(N, cons[0][0], cons)
print("-".join(ans))
print(t, end="")
PICKUP SERVICE CODE
TCS CODEVITA SOLUTIONS
Python3
SHARE ✅✅
@codeing_area
t = int(input())
def toWord(n):
if n == 1: return "one"
elif n == 2: return "two"
elif n == 3: return "thr"
elif n == 4: return "fou"
elif n == 5: return "fiv"
elif n == 6: return "six"
elif n == 7: return "sev"
elif n == 8: return "eig"
elif n == 9: return "nin"
elif n == 0: return "zer"
def toSum(s):
number = int(s)
if number == 0: return 0
elif number%9 == 0: return 9
else: return number%9
for i in range(t):
a = [x for x in input().split()]
n = a[0]
name = a[1]
d1 = 0
if "." in n:
d1 = n.index('.')
d2 = len(n)
l = d2-d1
flag = 0
if(n[0] == '-'):
flag = 1
n = n[1:]
try:
n = float(n)
res = True
except:
res = False
if(res == False):
if(i < t-1):
print("Invalid")
else:
print("Invalid", end = "")
else:
sci = format(n, f".{l}e")
part = sci.split('e')
num = part[0].split('.')
k = int(part[1])
if(flag == 1): res = "-"
else: res = ""
res += toWord(int(num[0])) +"."+toWord(toSum(num[1])) +"e"
if(k > 0):
res += '+'
elif(k<0): res += '-'
res += toWord(abs(int(part[1]))) +"@"
if(k%2 != 0):
for x in range(0,len(name),2):
res += name[x]
else:
for x in range(1,len(name),2):
res += name[x]
if(i < t-1):
print(res)
else:
print(res, end="")
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