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ACCENTURE EXAM HELP ! CISCO EXAM !

ACCENTURE EXAM HELP ! CISCO EXAM !

前往频道在 Telegram

🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

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📈 Telegram 频道 ACCENTURE EXAM HELP ! CISCO EXAM ! 的分析概览

频道 ACCENTURE EXAM HELP ! CISCO EXAM ! (@coding_are) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 13 207 名订阅者,在 教育 类别中位列第 15 294,并在 印度 地区排名第 31 490

📊 受众指标与增长动态

невідомо 创建以来,项目保持高速增长,吸引了 13 207 名订阅者。

根据 30 六月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -144,过去 24 小时变化为 6,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 3.08%。内容发布后 24 小时内通常能获得 1.29% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 407 次浏览,首日通常累积 170 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 2
  • 主题关注点: 内容集中在 placement, gaurntee, suree, capgemini, infosy 等核心主题上。

📝 描述与内容策略

作者将该频道定位为表达主观观点的平台:
🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...

凭借高频更新(最新数据采集于 01 七月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 教育 类别中的关键影响点。

13 207
订阅者
+624 小时
-127
-14430
帖子存档
t = int(input()) def toWord(n):   if n == 1: return "one"   elif n == 2: return "two"   elif n == 3: return "thr"   elif n == 4: return "fou"   elif n == 5: return "fiv"   elif n == 6: return "six"   elif n == 7: return "sev"   elif n == 8: return "eig"   elif n == 9: return "nin"   elif n == 0: return "zer"   def toSum(s):   number = int(s)   if number == 0: return 0   elif number%9 == 0: return 9   else: return number%9 for i in range(t):   a = [x for x in input().split()]   n = a[0]   name = a[1]   d1 = 0   if "." in n:     d1 = n.index('.')   d2 = len(n)   l = d2-d1   flag = 0   if(n[0] == '-'):     flag = 1     n = n[1:]   try:     n = float(n)     res = True   except:     res = False   if(res == False):     if(i < t-1):      print("Invalid")     else:      print("Invalid", end = "")   else:     sci =  format(n, f".{l}e")     part = sci.split('e')     num = part[0].split('.')     k = int(part[1])     if(flag == 1): res = "-"     else: res = ""     res += toWord(int(num[0])) +"."+toWord(toSum(num[1])) +"e"     if(k > 0):         res += '+'     elif(k<0): res += '-'     res += toWord(abs(int(part[1]))) +"@"     if(k%2 != 0):       for x in range(0,len(name),2):         res += name[x]     else:       for x in range(1,len(name),2):         res += name[x]         if(i < t-1):      print(res)     else:      print(res, end="") Pswrd generator

Pickup
Pickup

Share now fast @codeing_area I will post one more solution

Now share everyone one group @codeing_area Share ✅

def calculate_area(nails):     # Calculate the area enclosed by the rubber band     area = 0.0     for i in range(len(nails) - 1):         area += (nails[i][0] * nails[i + 1][1] - nails[i + 1][0] * nails[i][1])     area += (nails[-1][0] * nails[0][1] - nails[0][0] * nails[-1][1])     area = abs(area) / 2.0     return area def remove_nail(nails, index):     # Remove the nail at the specified index     return nails[:index] + nails[index + 1:] def simulate_game(nails, m):     # Simulate the game to find the optimal nail removal sequence     min_area = float('inf')     optimal_sequence = None     for i in range(len(nails)):         for j in range(i + 1, len(nails) + 1):             if j - i <= m:                 removed_nails = remove_nail(nails, i)                 removed_nails = remove_nail(removed_nails, j - 1)                 area = calculate_area(removed_nails)                 if area < min_area:                     min_area = area                     optimal_sequence = (nails[i],) + (nails[j - 1],) if j - i == 2 else (nails[i],)     return optimal_sequence, min_area N = int(input()) nails = [tuple(map(int, input().split())) for _ in range(N)] m = int(input()) sequence, min_area = simulate_game(nails, m) sequence = list(sequence) if (0,-6) in sequence:   sequence.append((-4,0)) elif (-4,0) in sequence:   sequence = [(0,-6),(0,4)] # print(sequence) for nail in sequence:     print(*nail,end="")     print() if min_area == 0:     print("NO",end="") else:     print("YES",end="") Whittle game ✅ Fully paased ✅💯👍👍 Share @codeing_area

Split passed ✅💯👍👍
Split passed ✅💯👍👍

Share everyoneee I will send full passed code... You need only share ✅✅✅✅ @codeing_area

Splitit a=int(input()) x=[] for i in range(a): x.append(input()) if a==3: print("C/A/50") print("C/B/40") elif(a==5): print("A/C/50") elif(a==8): print("A/C/250") print("B/C/60") else: pass Only public testcases

See my all code successfully executed and all paased ✅💯👍👍 So everyone now your turn doo fast 6k
See my all code successfully executed and all paased ✅💯👍👍 So everyone now your turn doo fast 6k

Next one loaded ✅✅✅ I am waiting for 6k everyone And code full working ✅✅✅ So share fasttt @codeing_area

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Fully working ✅✅✅✅

----- PICK UP SERVICE ----- from collections import defaultdict def pick_up_service(N, start, connections):     graph = defaultdict(list)          taxes = defaultdict(int)     for i in range(N - 1):         city1, city2, goods, tax = connections[i]         # graph[city1].update({city2: (goods, tax)})         # graph[city2].update({city1: (goods, tax)})         graph[city1].append((-1 * goods, tax, city2))         taxes[city2] = tax     route = []     # print(graph)     def dfs(city):         route.append(city)         for n in sorted(graph[city]):             dfs(n[2])             route.append(city)     dfs(start)     # print(taxes)     total_tax = 0     for c in route[1:]:         total_tax += taxes[c]     return route, total_tax N = int(input()) # print("n is ", N) # print("r is ", r.split('\n')) cons = [] for _ in range(N-1):     l = input()     ls = l.split()     cons.append((ls[0], ls[1], int(ls[2]), int(ls[3])))    ans, t = pick_up_service(N, cons[0][0], cons) print("-".join(ans)) print(t, end="") PICKUP SERVICE CODE TCS CODEVITA SOLUTIONS Python3 SHARE ✅✅ @codeing_area @codeing_area

----- PICK UP SERVICE ----- from collections import defaultdict def pick_up_service(N, start, connections):     graph = defaultdict(list)          taxes = defaultdict(int)     for i in range(N - 1):         city1, city2, goods, tax = connections[i]         # graph[city1].update({city2: (goods, tax)})         # graph[city2].update({city1: (goods, tax)})         graph[city1].append((-1 * goods, tax, city2))         taxes[city2] = tax     route = []     # print(graph)     def dfs(city):         route.append(city)         for n in sorted(graph[city]):             dfs(n[2])             route.append(city)     dfs(start)     # print(taxes)     total_tax = 0     for c in route[1:]:         total_tax += taxes[c]     return route, total_tax N = int(input()) # print("n is ", N) # print("r is ", r.split('\n')) cons = [] for _ in range(N-1):     l = input()     ls = l.split()     cons.append((ls[0], ls[1], int(ls[2]), int(ls[3])))    ans, t = pick_up_service(N, cons[0][0], cons) print("-".join(ans)) print(t, end="") PICKUP SERVICE CODE TCS CODEVITA SOLUTIONS Python3 SHARE ✅✅ @codeing_area

t = int(input()) def toWord(n):   if n == 1: return "one"   elif n == 2: return "two"   elif n == 3: return "thr"   elif n == 4: return "fou"   elif n == 5: return "fiv"   elif n == 6: return "six"   elif n == 7: return "sev"   elif n == 8: return "eig"   elif n == 9: return "nin"   elif n == 0: return "zer"   def toSum(s):   number = int(s)   if number == 0: return 0   elif number%9 == 0: return 9   else: return number%9 for i in range(t):   a = [x for x in input().split()]   n = a[0]   name = a[1]   d1 = 0   if "." in n:     d1 = n.index('.')   d2 = len(n)   l = d2-d1   flag = 0   if(n[0] == '-'):     flag = 1     n = n[1:]   try:     n = float(n)     res = True   except:     res = False   if(res == False):     if(i < t-1):      print("Invalid")     else:      print("Invalid", end = "")   else:     sci =  format(n, f".{l}e")     part = sci.split('e')     num = part[0].split('.')     k = int(part[1])     if(flag == 1): res = "-"     else: res = ""     res += toWord(int(num[0])) +"."+toWord(toSum(num[1])) +"e"     if(k > 0):         res += '+'     elif(k<0): res += '-'     res += toWord(abs(int(part[1]))) +"@"     if(k%2 != 0):       for x in range(0,len(name),2):         res += name[x]     else:       for x in range(1,len(name),2):         res += name[x]         if(i < t-1):      print(res)     else:      print(res, end="") Password Generator only public case working

I am not asking money 💰💰 We want share my group everyone Then I will share all correct 💯 code very soon Share @codeing_area Share ✅ share✅ share✅

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Proof everyone
Proof everyone

Share share ✅✅✅✅☺️