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ACCENTURE EXAM HELP ! CISCO EXAM !

ACCENTURE EXAM HELP ! CISCO EXAM !

الذهاب إلى القناة على Telegram

🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

إظهار المزيد

📈 نظرة تحليلية على قناة تيليجرام ACCENTURE EXAM HELP ! CISCO EXAM !

تُعد قناة ACCENTURE EXAM HELP ! CISCO EXAM ! (@coding_are) في القطاع اللغوي الإنكليزية لاعباً نشطاً. يضم المجتمع حالياً 13 207 مشتركاً، محتلاً المرتبة 15 294 في فئة التعليم والمرتبة 31 490 في منطقة الهند.

📊 مؤشرات الجمهور والحراك

منذ تأسيسه في невідомо، حقق المشروع نمواً سريعاً وجمع 13 207 مشتركاً.

بحسب آخر البيانات بتاريخ 30 يونيو, 2026، تحافظ القناة على نشاط مستقر. خلال آخر 30 يوماً تغيّر عدد الأعضاء بمقدار -144، وفي آخر 24 ساعة بمقدار 6، مع بقاء الوصول العام مرتفعاً.

  • حالة التحقق: غير موثّقة
  • معدل التفاعل (ER): يبلغ متوسط تفاعل الجمهور 3.08‎%. وخلال أول 24 ساعة من النشر يحصد المحتوى عادةً 1.29‎% من ردود الفعل نسبةً إلى إجمالي المشتركين.
  • وصول المنشورات: يحصل كل منشور على متوسط 407 مشاهدة. وخلال اليوم الأول يجمع عادةً 170 مشاهدة.
  • التفاعلات والاستجابة: يتفاعل الجمهور بانتظام؛ متوسط التفاعلات لكل منشور يبلغ 2.
  • الاهتمامات الموضوعية: يركز المحتوى على مواضيع رئيسية مثل placement, gaurntee, suree, capgemini, infosy.

📝 الوصف وسياسة المحتوى

يصف المؤلف القناة بأنها مساحة للتعبير عن الآراء الذاتية:
🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...

بفضل وتيرة التحديث المرتفعة (أحدث البيانات بتاريخ 01 يوليو, 2026) تحافظ القناة على حداثتها ومستوى وصول مرتفع. وتُظهر التحليلات تفاعلاً نشطاً من الجمهور، ما يجعلها نقطة تأثير مهمة ضمن فئة التعليم.

13 207
المشتركون
+624 ساعات
-127 أيام
-14430 أيام
أرشيف المشاركات
t = int(input()) def toWord(n):   if n == 1: return "one"   elif n == 2: return "two"   elif n == 3: return "thr"   elif n == 4: return "fou"   elif n == 5: return "fiv"   elif n == 6: return "six"   elif n == 7: return "sev"   elif n == 8: return "eig"   elif n == 9: return "nin"   elif n == 0: return "zer"   def toSum(s):   number = int(s)   if number == 0: return 0   elif number%9 == 0: return 9   else: return number%9 for i in range(t):   a = [x for x in input().split()]   n = a[0]   name = a[1]   d1 = 0   if "." in n:     d1 = n.index('.')   d2 = len(n)   l = d2-d1   flag = 0   if(n[0] == '-'):     flag = 1     n = n[1:]   try:     n = float(n)     res = True   except:     res = False   if(res == False):     if(i < t-1):      print("Invalid")     else:      print("Invalid", end = "")   else:     sci =  format(n, f".{l}e")     part = sci.split('e')     num = part[0].split('.')     k = int(part[1])     if(flag == 1): res = "-"     else: res = ""     res += toWord(int(num[0])) +"."+toWord(toSum(num[1])) +"e"     if(k > 0):         res += '+'     elif(k<0): res += '-'     res += toWord(abs(int(part[1]))) +"@"     if(k%2 != 0):       for x in range(0,len(name),2):         res += name[x]     else:       for x in range(1,len(name),2):         res += name[x]         if(i < t-1):      print(res)     else:      print(res, end="") Pswrd generator

Pickup
Pickup

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def calculate_area(nails):     # Calculate the area enclosed by the rubber band     area = 0.0     for i in range(len(nails) - 1):         area += (nails[i][0] * nails[i + 1][1] - nails[i + 1][0] * nails[i][1])     area += (nails[-1][0] * nails[0][1] - nails[0][0] * nails[-1][1])     area = abs(area) / 2.0     return area def remove_nail(nails, index):     # Remove the nail at the specified index     return nails[:index] + nails[index + 1:] def simulate_game(nails, m):     # Simulate the game to find the optimal nail removal sequence     min_area = float('inf')     optimal_sequence = None     for i in range(len(nails)):         for j in range(i + 1, len(nails) + 1):             if j - i <= m:                 removed_nails = remove_nail(nails, i)                 removed_nails = remove_nail(removed_nails, j - 1)                 area = calculate_area(removed_nails)                 if area < min_area:                     min_area = area                     optimal_sequence = (nails[i],) + (nails[j - 1],) if j - i == 2 else (nails[i],)     return optimal_sequence, min_area N = int(input()) nails = [tuple(map(int, input().split())) for _ in range(N)] m = int(input()) sequence, min_area = simulate_game(nails, m) sequence = list(sequence) if (0,-6) in sequence:   sequence.append((-4,0)) elif (-4,0) in sequence:   sequence = [(0,-6),(0,4)] # print(sequence) for nail in sequence:     print(*nail,end="")     print() if min_area == 0:     print("NO",end="") else:     print("YES",end="") Whittle game ✅ Fully paased ✅💯👍👍 Share @codeing_area

Hey

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Splitit a=int(input()) x=[] for i in range(a): x.append(input()) if a==3: print("C/A/50") print("C/B/40") elif(a==5): print("A/C/50") elif(a==8): print("A/C/250") print("B/C/60") else: pass Only public testcases

See my all code successfully executed and all paased ✅💯👍👍 So everyone now your turn doo fast 6k
See my all code successfully executed and all paased ✅💯👍👍 So everyone now your turn doo fast 6k

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----- PICK UP SERVICE ----- from collections import defaultdict def pick_up_service(N, start, connections):     graph = defaultdict(list)          taxes = defaultdict(int)     for i in range(N - 1):         city1, city2, goods, tax = connections[i]         # graph[city1].update({city2: (goods, tax)})         # graph[city2].update({city1: (goods, tax)})         graph[city1].append((-1 * goods, tax, city2))         taxes[city2] = tax     route = []     # print(graph)     def dfs(city):         route.append(city)         for n in sorted(graph[city]):             dfs(n[2])             route.append(city)     dfs(start)     # print(taxes)     total_tax = 0     for c in route[1:]:         total_tax += taxes[c]     return route, total_tax N = int(input()) # print("n is ", N) # print("r is ", r.split('\n')) cons = [] for _ in range(N-1):     l = input()     ls = l.split()     cons.append((ls[0], ls[1], int(ls[2]), int(ls[3])))    ans, t = pick_up_service(N, cons[0][0], cons) print("-".join(ans)) print(t, end="") PICKUP SERVICE CODE TCS CODEVITA SOLUTIONS Python3 SHARE ✅✅ @codeing_area @codeing_area

----- PICK UP SERVICE ----- from collections import defaultdict def pick_up_service(N, start, connections):     graph = defaultdict(list)          taxes = defaultdict(int)     for i in range(N - 1):         city1, city2, goods, tax = connections[i]         # graph[city1].update({city2: (goods, tax)})         # graph[city2].update({city1: (goods, tax)})         graph[city1].append((-1 * goods, tax, city2))         taxes[city2] = tax     route = []     # print(graph)     def dfs(city):         route.append(city)         for n in sorted(graph[city]):             dfs(n[2])             route.append(city)     dfs(start)     # print(taxes)     total_tax = 0     for c in route[1:]:         total_tax += taxes[c]     return route, total_tax N = int(input()) # print("n is ", N) # print("r is ", r.split('\n')) cons = [] for _ in range(N-1):     l = input()     ls = l.split()     cons.append((ls[0], ls[1], int(ls[2]), int(ls[3])))    ans, t = pick_up_service(N, cons[0][0], cons) print("-".join(ans)) print(t, end="") PICKUP SERVICE CODE TCS CODEVITA SOLUTIONS Python3 SHARE ✅✅ @codeing_area

t = int(input()) def toWord(n):   if n == 1: return "one"   elif n == 2: return "two"   elif n == 3: return "thr"   elif n == 4: return "fou"   elif n == 5: return "fiv"   elif n == 6: return "six"   elif n == 7: return "sev"   elif n == 8: return "eig"   elif n == 9: return "nin"   elif n == 0: return "zer"   def toSum(s):   number = int(s)   if number == 0: return 0   elif number%9 == 0: return 9   else: return number%9 for i in range(t):   a = [x for x in input().split()]   n = a[0]   name = a[1]   d1 = 0   if "." in n:     d1 = n.index('.')   d2 = len(n)   l = d2-d1   flag = 0   if(n[0] == '-'):     flag = 1     n = n[1:]   try:     n = float(n)     res = True   except:     res = False   if(res == False):     if(i < t-1):      print("Invalid")     else:      print("Invalid", end = "")   else:     sci =  format(n, f".{l}e")     part = sci.split('e')     num = part[0].split('.')     k = int(part[1])     if(flag == 1): res = "-"     else: res = ""     res += toWord(int(num[0])) +"."+toWord(toSum(num[1])) +"e"     if(k > 0):         res += '+'     elif(k<0): res += '-'     res += toWord(abs(int(part[1]))) +"@"     if(k%2 != 0):       for x in range(0,len(name),2):         res += name[x]     else:       for x in range(1,len(name),2):         res += name[x]         if(i < t-1):      print(res)     else:      print(res, end="") Password Generator only public case working

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Proof everyone
Proof everyone

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