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MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer
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π₯Guys plz Stop fearing for daily exams π π¨βπ» @srksvk is here to help you all at lowest cost possible.πͺ π β Our Only Aim Is To Let Get Placed To You In A Reputed Company π₯Effort from our side = π― π±Main Channel: @coding_are π±Tel I'd : @srksvk
Show moreπ Analytical overview of Telegram channel MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer
Channel MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer (@coding_are) in the English language segment is an active participant. Currently, the community unites 13 236 subscribers, ranking 15 345 in the Education category and 32 011 in the India region.
π Audience metrics and dynamics
Since its creation on Π½Π΅Π²ΡΠ΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 13 236 subscribers.
According to the latest data from 19 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -137 over the last 30 days and by -4 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 2.81%. Within the first 24 hours after publication, content typically collects 1.07% reactions from the total number of subscribers.
- Post reach: On average, each post receives 372 views. Within the first day, a publication typically gains 142 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
- Thematic interests: Content is focused on key topics such as placement, gaurntee, suree, capgemini, infosy.
π Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
βπ₯Guys plz Stop fearing for daily exams π
π¨βπ» @srksvk is here to help you all at lowest cost possible.πͺ
π β Our Only Aim Is To Let Get Placed To You In A Reputed Company
π₯Effort from our side = π―
π±Main Channel: @coding_are
π±Tel I'd : @srks...β
Thanks to the high frequency of updates (latest data received on 20 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.
13 236
Subscribers
-424 hours
-407 days
-13730 days
Posts Archive
+1
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#include<bits/stdc++.h>
using namespace std;
int k, r, m, res = 0;
vector<string> words;
void solve(int i, vector<int>& lan, int cnt, const vector<string>& qw) {
Β if (i == (int)qw.size()) {
Β Β Β res = max(res, cnt);
Β Β Β return;
Β }
Β if (cnt + (int)(qw.size() - i) <= res) return;
Β for (int j = 0; j < r; j++) {
Β Β Β if (lan[j] == 0) {
Β Β Β Β Β lan[j] = qw[i].size();
Β Β Β Β Β solve(i + 1, lan, cnt + 1, qw);
Β Β Β Β Β lan[j] = 0;
Β Β Β Β Β break;
Β Β Β } else if (lan[j] + 1 + (int)qw[i].size() <= m) {
Β Β Β Β Β lan[j] += 1 + qw[i].size();
Β Β Β Β Β solve(i + 1, lan, cnt + 1, qw);
Β Β Β Β Β lan[j] -= 1 + qw[i].size();
Β Β Β }
Β }
Β solve(i + 1, lan, cnt, qw);
}
int main() {
Β ios::sync_with_stdio(false);
Β cin.tie(0);
Β cin >> k;
Β words.resize(k);
Β for (auto& s : words) cin >> s;
Β cin >> r >> m;
Β vector<string> qw;
Β for (auto& s : words) if ((int)s.size() <= m) qw.push_back(s);
Β sort(qw.begin(), qw.end(), [&](const string& a, const string& b) -> bool {
Β Β Β if (a.size() != b.size()) return a.size() > b.size();
Β Β Β return a < b;
Β });
Β vector<int> lan(r, 0);
Β solve(0, lan, 0, qw);
Β cout << res;
}
faulty segment
Equation Puzzle Code
C++
TCS
int main() {
string e1, e2;
int r;
cin >> e1 >> e2 >> r;
// @codeing_are
int a1, b1, c1, d1, n1, a2, b2, c2, d2, n2;
sscanf(e1.c_str(), "%dx+%dy+%dz+%dw<=%d", &a1, &b1, &c1, &d1, &n1);
sscanf(e2.c_str(), "%dx+%dy+%dz+%dw<=%d", &a2, &b2, &c2, &d2, &n2);
vector<vector<int>> combinations;
for (int x = 0; x <= r; x++) {
for (int y = 0; y + x <= r; y++) {
for (int z = 0; z + x + y <= r; z++) {
int w = r - x - y - z;
combinations.push_back({x, y, z, w});
}
}
}
set<int> results;
for (auto &vars1 : combinations) {
int v1 = a1 * vars1[0] + b1 * vars1[1] + c1 * vars1[2] + d1 * vars1[3];
if (v1 > n1) continue;
for (auto &vars2 : combinations) {
int v2 = a2 * vars2[0] + b2 * vars2[1] + c2 * vars2[2] + d2 * vars2[3];
if (v2 > n2) continue;
if (v1 == v2) results.insert(v1);
}
}
cout << results.size() << endl;
return 0;
}
Equation Puzzle Code
C++
TCS
