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MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer
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🔥Guys plz Stop fearing for daily exams 📝 👨💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk
Больше📈 Аналитический обзор Telegram-канала MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer
Канал MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer (@coding_are) языкового сегмента Английский является активным участником. Сейчас сообщество объединяет 13 236 подписчиков, занимая 15 345 место в категории Образование и 32 011 место в регионе Индия.
📊 Показатели аудитории и динамика
С момента создания невідомо проект демонстрирует стремительный рост, собрав аудиторию из 13 236 подписчиков.
Согласно последним данным от 19 июня, 2026, канал показывает стабильную активность. За последние 30 дней изменение числа участников составило -137, а за последние 24 часа — -4, при этом общий охват остаётся высоким.
- Статус верификации: Не верифицирован
- Уровень вовлечённости (ER): Средний показатель вовлечённости аудитории составляет 2.81%. В первые 24 часа после публикации контент обычно набирает 1.07% реакций от общего числа подписчиков.
- Охват публикаций: В среднем каждый пост получает 372 просмотров. В течение первых суток публикация набирает 142 просмотров.
- Реакции и взаимодействия: Аудитория активно поддерживает контент: среднее количество реакций на один пост — 2.
- Тематические интересы: Контент сосредоточен на ключевых темах, таких как placement, gaurntee, suree, capgemini, infosy.
📝 Описание и контентная политика
Автор описывает ресурс как площадку для выражения субъективного мнения:
“🔥Guys plz Stop fearing for daily exams 📝
👨💻 @srksvk is here to help you all at lowest cost possible.💪
🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company
🔥Effort from our side = 💯
📱Main Channel: @coding_are
📱Tel I'd : @srks...”
Благодаря высокой частоте обновлений (последние данные получены 20 июня, 2026) канал поддерживает актуальность и высокий уровень охвата публикаций. Аналитика показывает, что аудитория активно взаимодействует с контентом, что делает его важной точкой влияния в категории Образование.
13 236
Подписчики
-424 часа
-407 дней
-13730 день
Архив постов
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#include<bits/stdc++.h>
using namespace std;
int k, r, m, res = 0;
vector<string> words;
void solve(int i, vector<int>& lan, int cnt, const vector<string>& qw) {
if (i == (int)qw.size()) {
res = max(res, cnt);
return;
}
if (cnt + (int)(qw.size() - i) <= res) return;
for (int j = 0; j < r; j++) {
if (lan[j] == 0) {
lan[j] = qw[i].size();
solve(i + 1, lan, cnt + 1, qw);
lan[j] = 0;
break;
} else if (lan[j] + 1 + (int)qw[i].size() <= m) {
lan[j] += 1 + qw[i].size();
solve(i + 1, lan, cnt + 1, qw);
lan[j] -= 1 + qw[i].size();
}
}
solve(i + 1, lan, cnt, qw);
}
int main() {
ios::sync_with_stdio(false);
cin.tie(0);
cin >> k;
words.resize(k);
for (auto& s : words) cin >> s;
cin >> r >> m;
vector<string> qw;
for (auto& s : words) if ((int)s.size() <= m) qw.push_back(s);
sort(qw.begin(), qw.end(), [&](const string& a, const string& b) -> bool {
if (a.size() != b.size()) return a.size() > b.size();
return a < b;
});
vector<int> lan(r, 0);
solve(0, lan, 0, qw);
cout << res;
}
faulty segment
Equation Puzzle Code
C++
TCS
int main() {
string e1, e2;
int r;
cin >> e1 >> e2 >> r;
// @codeing_are
int a1, b1, c1, d1, n1, a2, b2, c2, d2, n2;
sscanf(e1.c_str(), "%dx+%dy+%dz+%dw<=%d", &a1, &b1, &c1, &d1, &n1);
sscanf(e2.c_str(), "%dx+%dy+%dz+%dw<=%d", &a2, &b2, &c2, &d2, &n2);
vector<vector<int>> combinations;
for (int x = 0; x <= r; x++) {
for (int y = 0; y + x <= r; y++) {
for (int z = 0; z + x + y <= r; z++) {
int w = r - x - y - z;
combinations.push_back({x, y, z, w});
}
}
}
set<int> results;
for (auto &vars1 : combinations) {
int v1 = a1 * vars1[0] + b1 * vars1[1] + c1 * vars1[2] + d1 * vars1[3];
if (v1 > n1) continue;
for (auto &vars2 : combinations) {
int v2 = a2 * vars2[0] + b2 * vars2[1] + c2 * vars2[2] + d2 * vars2[3];
if (v2 > n2) continue;
if (v1 == v2) results.insert(v1);
}
}
cout << results.size() << endl;
return 0;
}
Equation Puzzle Code
C++
TCS
