MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

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India32 092 Educación15 362...

📈 Análisis del canal de Telegram MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

El canal MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer (@coding_are) en el segmento lingüístico de Inglés es un actor destacado. Actualmente la comunidad reúne a 13 242 suscriptores, ocupando la posición 15 362 en la categoría Educación y el puesto 32 092 en la región India.

📊 Métricas de audiencia y dinámica

Desde su creación el невідомо, el proyecto ha mostrado un crecimiento acelerado, reuniendo a 13 242 suscriptores.

Según los últimos datos del 18 junio, 2026, el canal mantiene una actividad estable. En los últimos 30 días la variación de miembros fue de -138, y en las últimas 24 horas de -2, conservando un alto alcance.

Estado de verificación: No verificado
Tasa de interacción (ER): El promedio de interacción de la audiencia es 2.93%. Durante las primeras 24 horas tras publicar, el contenido suele obtener 1.11% de reacciones respecto al total de suscriptores.
Alcance de las publicaciones: Cada publicación recibe en promedio 388 visualizaciones. En el primer día suele acumular 147 visualizaciones.
Reacciones e interacción: La audiencia responde de forma activa: el promedio de reacciones por publicación es 2.
Intereses temáticos: El contenido se centra en temas clave como placement, gaurntee, suree, capgemini, infosy.

📝 Descripción y política de contenido

El autor describe el recurso como un espacio para expresar opiniones subjetivas:
“🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...”

Gracias a la alta frecuencia de actualizaciones (últimos datos recibidos el 19 junio, 2026), el canal mantiene la vigencia y un amplio alcance. La analítica demuestra que la audiencia interactúa activamente con el contenido, lo que lo convierte en un punto de referencia dentro de la categoría Educación.

13 242

Suscriptores

-224 horas

-457 días

-13830 días

388

Visitas de la publicación

~ 14724 horas

~ 19648 horas

2.93%

Tasa de compromiso

~ 3

Mensajes por día

Ads index

beta

Archivo de publicaciones

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#include<bits/stdc++.h> using namespace std; int k, r, m, res = 0; vector<string> words; void solve(int i, vector<int>& lan, int cnt, const vector<string>& qw) { if (i == (int)qw.size()) { res = max(res, cnt); return; } if (cnt + (int)(qw.size() - i) <= res) return; for (int j = 0; j < r; j++) { if (lan[j] == 0) { lan[j] = qw[i].size(); solve(i + 1, lan, cnt + 1, qw); lan[j] = 0; break; } else if (lan[j] + 1 + (int)qw[i].size() <= m) { lan[j] += 1 + qw[i].size(); solve(i + 1, lan, cnt + 1, qw); lan[j] -= 1 + qw[i].size(); } } solve(i + 1, lan, cnt, qw); } int main() { ios::sync_with_stdio(false); cin.tie(0); cin >> k; words.resize(k); for (auto& s : words) cin >> s; cin >> r >> m; vector<string> qw; for (auto& s : words) if ((int)s.size() <= m) qw.push_back(s); sort(qw.begin(), qw.end(), [&](const string& a, const string& b) -> bool { if (a.size() != b.size()) return a.size() > b.size(); return a < b; }); vector<int> lan(r, 0); solve(0, lan, 0, qw); cout << res; } faulty segment

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