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MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

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🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

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📈 Analytical overview of Telegram channel MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

Channel MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer (@coding_are) in the English language segment is an active participant. Currently, the community unites 13 236 subscribers, ranking 15 345 in the Education category and 32 011 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 13 236 subscribers.

According to the latest data from 19 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -137 over the last 30 days and by -4 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 2.81%. Within the first 24 hours after publication, content typically collects 1.07% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 372 views. Within the first day, a publication typically gains 142 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
  • Thematic interests: Content is focused on key topics such as placement, gaurntee, suree, capgemini, infosy.

📝 Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...

Thanks to the high frequency of updates (latest data received on 20 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

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#include<bits/stdc++.h> using namespace std; using ll = long long; vector<string> read(){     vector<string> strs;     string line;     getline(cin , line);     istringstream iss(line);     copy(istream_iterator<string>(iss), istream_iterator<string>(), back_inserter(strs));     return strs; } map<string , vector<string>> graph; map<string , ll> mask , id; map<string , string> open; ll ans = 0; ll dfs1(string &u){     ll curr = id.count(u) ? 1LL << id[u] : 0;     for(string &v : graph[u]) curr |= dfs1(v);     return mask[u] = curr; } void dfs2(string &u , int bit){     if(id[u] == bit){         open[u] = u;         return;     }     for(string &v : graph[u]){         if(mask[v] >> bit & 1){             if(open[u] != v) ans++ , open[u] = v;             return dfs2(v , bit);         }     } } int main(){     ll N ; cin >> N;     cin.ignore();     while(N--){         vector<string> children = read();         reverse(children.begin() , children.end());         string parent = children.back();         children.pop_back();         graph[parent] = children;     }     ll cid = 0;     vector<string> colors = read();     for(string &color : colors) if(!id.count(color)) id[color] = ++cid;     string u = "source";     dfs1(u);     for(string &color : colors) dfs2(u , id[color]);     cout << ans;     return 0; } Route the balls

Next code uploaded sooon with proofs 👇👇👇👇👇

JustifyWords def max_words_fitted(k, words, n, m): words = [word for word in words if len(word) <= m] def backtrack(index, lines): if index == len(words): return sum(len(line.split()) for line in lines) max_words = 0 word = words[index] for i in range(len(lines)): if len(lines[i]) + len(word) + (1 if lines[i] else 0) <= m: original_line = lines[i] lines[i] = lines[i] + (' ' if lines[i] else '') + word max_words = max(max_words, backtrack(index + 1, lines)) lines[i] = original_line if len(lines) < n: lines.append(word) max_words = max(max_words, backtrack(index + 1, lines)) lines.pop() return max_words return backtrack(0, []) # Input k = int(input().strip()) words = [input().strip() for _ in range(k)] n, m = map(int, input().strip().split()) print(max_words_fitted(k, words, n, m))

1)Flight Optimization TCS CodeVita accepted 2)magic stars intensity ac 3)Sofa problem done with private 4)Faulty sankes and ladders 5)Frenkitsen wala Codevita These code are Allredy uploaded with 💯 correct answer Dance rev 100% Working

https://t.me/codeing_are Share the group ✅✅✅✅✅✅✅✅✅✅✅✅

// Flight Optimization TCS CodeVita accepted

#include <bits/stdc++.h> using namespace std; #define loop(i, a, n) for (lli i = (a); i < (n); ++i) #define loopD(i, a, n) for (lli i = (a); i >= (n); --i) #define all(c) (c).begin(), (c).end() #define rall(c) (c).rbegin(), (c).rend() #define sz(a) ((int)a.size()) #define YES cout << "YES" << endl; #define NO cout << "NO" << endl; #define endl '\n' #define fastio std::ios::sync_with_stdio(false), cin.tie(NULL), cout.tie(NULL); #define pb push_back #define pp pop_back() #define fi first #define si second #define v(a) vector<int>(a) #define vv(a) vector<vector<int>>(a) #define present(c, x) ((c).find(x) != (c).end()) #define set_bits __builtin_popcountll #define MOD 1000000007 #define int long long typedef long long lli; typedef vector<int> vi; typedef vector<vi> vvi; typedef pair<lli, lli> pll; typedef pair<int, int> pii; typedef unordered_map<int, int> umpi; typedef map<int, int> mpi; typedef vector<pii> vp; typedef vector<lli> vll; typedef vector<vll> vvll; struct Flight { string src; string to; int dt; int at; int cost; }; int parse_time(const string& time_str) { int hour = stoi(time_str.substr(0, 2)); int minute = stoi(time_str.substr(3, 2)); string am_pm = time_str.substr(5, 2); if (am_pm == "Am") { if (hour == 12) hour = 0; } else if (am_pm == "Pm") { if (hour != 12) hour += 12; } return hour * 60 + minute; } void solve() { int N; cin >> N; vector<Flight> fff(N); unordered_map<string, vector<Flight>> mp; for (int i = 0; i < N; ++i) { string src, to, des, arrival_str; int cost; cin >> src >> to >> des >> arrival_str >> cost; int dt = parse_time(des); int at = parse_time(arrival_str); Flight ff = {src, to, dt, at, cost}; fff[i] = ff; mp[src].push_back(ff); } string src, des; cin >> src >> des; string edes, last; cin >> edes >> last; int earliest_dt = parse_time(edes); int latest_at = parse_time(last); typedef tuple<int, int, string> State; priority_queue<State, vector<State>, greater<State>> pq; for (const auto& ff : mp[src]) { if (ff.dt >= earliest_dt) { if (ff.at <= latest_at) { pq.emplace(ff.cost, ff.at, ff.to); } } } unordered_map<string, int> ans; unordered_map<string, int> at; while (!pq.empty()) { int cost_so_far, current_at; string current_city; tie(cost_so_far, current_at, current_city) = pq.top(); pq.pop(); if (ans.find(current_city) != ans.end()) { if (cost_so_far > ans[current_city]) continue; if (cost_so_far == ans[current_city] && current_at >= at[current_city]) continue; } ans[current_city] = cost_so_far; at[current_city] = current_at; if (current_city == des) { cout << cost_so_far; return ; } for (const auto& ff : mp[current_city]) { if (ff.dt >= current_at) { if (ff.dt >= earliest_dt && ff.at <= latest_at) { int new_cost = cost_so_far + ff.cost; pq.emplace(new_cost, ff.at, ff.to); } } } } cout << "Impossible"; return ; } int32_t main() { int tc = 1; // cin >> tc; while (tc--) { solve(); } return 0; }

#include <bits/stdc++.h> using namespace std; #define loop(i, a, n) for (lli i = (a); i < (n); ++i) #define loopD(i, a, n) for (lli i = (a); i >= (n); --i) #define all(c) (c).begin(), (c).end() #define rall(c) (c).rbegin(), (c).rend() #define sz(a) ((lli)a.size()) #define YES cout << "YES" << endl; #define NO cout << "NO" << endl; #define endl '\n' #define fastio std::ios::sync_with_stdio(false), cin.tie(NULL), cout.tie(NULL); #define pb push_back #define pp pop_back() #define fi first #define si second #define v(a) vector<int>(a) #define vv(a) vector<vector<int>>(a) #define present(c, x) ((c).find(x) != (c).end()) #define set_bits __builtin_popcountll #define MOD 1000000007 #define int long long typedef long long lli; typedef vector<int> vi; typedef vector<vi> vvi; typedef pair<lli, lli> pll; typedef pair<int, int> pii; typedef unordered_map<int, int> umpi; typedef map<int, int> mpi; typedef vector<pii> vp; typedef vector<lli> vll; typedef vector<vll> vvll; struct Line { int x1, y1, x2, y2; bool vertical() const { return x1 == x2; } bool horizontal() const { return y1 == y2; } bool diagonal() const { return abs(x2 - x1) == abs(y2 - y1); } }; int N, K; vector<Line> lines; map<pair<int, int>, vector<int>> ptsMap; void add(const Line& line, int idx) { int x1 = line.x1, y1 = line.y1; int x2 = line.x2, y2 = line.y2; if (line.vertical()) { int yStart = min(y1, y2); int yEnd = max(y1, y2); for(int y = yStart; y <= yEnd; y++) { ptsMap[{x1, y}].push_back(idx); } } else if (line.horizontal()) { int xStart = min(x1, x2); int xEnd = max(x1, x2); for(int x = xStart; x <= xEnd; x++) { ptsMap[{x, y1}].push_back(idx); } } else if (line.diagonal()) { int steps = abs(x2 - x1); int dx = (x2 - x1) / steps; int dy = (y2 - y1) / steps; for(int i = 0; i <= steps; i++) { int x = x1 + i * dx; int y = y1 + i * dy; ptsMap[{x, y}].push_back(idx); } } } int ff(int x1, int y1, int x2, int y2) { if(x1 == x2) return abs(y1 - y2); if(y1 == y2) return abs(x1 - x2); if(abs(x1 - x2) == abs(y1 - y2)) return abs(x1 - x2); return 0; } int solve(const pair<int, int>& pt, const vector<int>& lst) { vector<int> d; for(auto lIdx : lst) { const Line& ln = lines[lIdx]; bool oneSided = (pt.first == ln.x1 && pt.second == ln.y1) || (pt.first == ln.x2 && pt.second == ln.y2); if(oneSided) { int ex = (pt.first == ln.x1 && pt.second == ln.y1) ? ln.x2 : ln.x1; int ey = (pt.first == ln.x1 && pt.second == ln.y1) ? ln.y2 : ln.y1; d.push_back(ff(pt.first, pt.second, ex, ey)); } else { d.push_back(ff(pt.first, pt.second, ln.x1, ln.y1)); d.push_back(ff(pt.first, pt.second, ln.x2, ln.y2)); } } return d.empty() ? 0 : *min_element(d.begin(), d.end()); } void solve() { cin >> N; lines.resize(N); for(int i = 0; i < N; i++) { cin >> lines[i].x1 >> lines[i].y1 >> lines[i].x2 >> lines[i].y2; add(lines[i], i); } cin >> K; int total = 0; for(auto &[pt, lst] : ptsMap) { if(sz(lst) == K) { total += solve(pt, lst); } } cout << total; } int32_t main() { solve(); return 0; } // magic stars intensity ac Full accepted ☺️

Hiii every I will share today also TCS codevitaa exam code in my channel
So please share the group for your frd and family and big group
https://t.me/codeing_are Join the group I will upload each every answer in free

Magic Star Intensity Code TCS CodeVita Zone 1 #include <iostream> #include <vector> #include <map> #include <set> #include <cmath> #include <algorithm> using namespace std; struct Line {     int x1, y1, x2, y2; }; int countCells(Line line, pair<int, int> star, bool split) {     if (line.x1 == line.x2) {         if (split) {             return min(abs(star.second - line.y1), abs(star.second - line.y2)) + 1;         }         else {             return abs(line.y1 - line.y2) + 1;         }     }     else {         if (split) {             return min(abs(star.first - line.x1), abs(star.first - line.x2)) + 1;         }         else {             return abs(line.x1 - line.x2) + 1;         }     } } bool intersects(Line a, Line b, pair<int, int>& intersection) {     if (a.x1 == a.x2 && b.y1 == b.y2) {         if (b.x1 <= a.x1 && a.x1 <= b.x2 && a.y1 <= b.y1 && b.y1 <= a.y2) {             intersection = {a.x1, b.y1};             return true;         }     }     if (a.y1 == a.y2 && b.x1 == b.x2) {         if (a.x1 <= b.x1 && b.x1 <= a.x2 && b.y1 <= a.y1 && a.y1 <= b.y2) {             intersection = {b.x1, a.y1};             return true;         }     }     return false; } int main() {     int N, K;     cin >> N;     vector<Line> lines(N);     for (int i = 0; i < N; ++i) {         cin >> lines[i].x1 >> lines[i].y1 >> lines[i].x2 >> lines[i].y2;         if (lines[i].x1 > lines[i].x2 || (lines[i].x1 == lines[i].x2 && lines[i].y1 > lines[i].y2)) {             swap(lines[i].x1, lines[i].x2);             swap(lines[i].y1, lines[i].y2);         }     }     cin >> K;     map<pair<int, int>, vector<Line>> stars;     for (int i = 0; i < N; ++i) {         for (int j = i + 1; j < N; ++j) {             pair<int, int> intersection;             if (intersects(lines[i], lines[j], intersection)) {                 stars[intersection].push_back(lines[i]);                 stars[intersection].push_back(lines[j]);             }         }     }     int placementlelo = 0;     for (auto& star : stars) {         if (star.second.size() / 2 == K) {             vector<int> intensities;             for (auto& line : star.second) {                 intensities.push_back(countCells(line, star.first, true));             }             placementlelo += *min_element(intensities.begin(), intensities.end());         }     }     cout << placementlelo << endl;     return 0; } Magic Star Intensity Code C++ TCS CodeVita Zone 1

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MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer - Statistics & analytics of Telegram channel @coding_are