Available now! Telegram Research 2025 — the year's key insights 
allcoding1_official
Open in Telegram
📈 Analytical overview of Telegram channel allcoding1_official
Channel allcoding1_official (@allcoding1_official) in the English language segment is an active participant. Currently, the community unites 85 678 subscribers, ranking 1 508 in the Technologies & Applications category and 3 501 in the India region.
📊 Audience metrics and dynamics
Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 85 678 subscribers.
According to the latest data from 21 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -1 434 over the last 30 days and by -33 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 3.09%. Within the first 24 hours after publication, content typically collects 0.73% reactions from the total number of subscribers.
- Post reach: On average, each post receives 2 645 views. Within the first day, a publication typically gains 625 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 1.
- Thematic interests: Content is focused on key topics such as dsa, stack, namaste, javascript, dev.
📝 Description and content policy
Channel description not provided.
Thanks to the high frequency of updates (latest data received on 22 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.
85 678
Subscribers
-3324 hours
-3007 days
-1 43430 days
Posts Archive
85 678
Date science full course (record classes)
50 rupees
👇👇
@meterials_available
85 678
In response to your demand, we now offer Instant Data Analytics Certificate Recognized by Google and Amazon
- 🕑 Take 5 minutes Quiz
- 📜Pay & Unlock Instant Certificate
- ✅ show it off on your CV & LinkedIn
Get your instant certificate @Rs.199 only and level up your CV & increase chance of getting job by 133%.
Limited period offer 🥵. Click below
https://tinyurl.com/DataAnalyticsXCertificateAC1
85 678
Many of you have been asking for SQL course that covers everything you need and is budget friendly. Well, I’m excited to introduce you to this course by LearnTube!
Highlights :-
📃Personalised SQL Course
📰Verified SQL Certificate recognised by Google and amazon .
🏅5+ Industry projects.
All of these in just Rs. 399 with Life Time access
Limited time period offer. Click Below 👇
https://tinyurl.com/SQLXCourseAC1
85 678
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int n = scanner.nextInt();
int[] left = new int[n];
int[] right = new int[n];
for (int i = 0; i < n; i++) {
left[i] = scanner.nextInt();
right[i] = scanner.nextInt();
}
int sumLeft = 0;
int sumRight = 0;
for (int i = 0; i < n; i++) {
sumLeft += left[i];
sumRight += right[i];
}
if (sumLeft % 2 == 0 && sumRight % 2 == 0) {
System.out.println(0);
return;
}
boolean possible = false;
for (int i = 0; i < n; i++) {
int newSumLeft = sumLeft - left[i] + right[i];
int newSumRight = sumRight - right[i] + left[i];
if (newSumLeft % 2 == 0 && newSumRight % 2 == 0) {
possible = true;
break;
}
}
if (possible) {
System.out.println(1);
} else {
System.out.println(-1);
}
}
}
85 678
AWS COURSE Classes BY NARESH IT
Google drive Link for 50 rupees
Contact:- @meterials_available
85 678
+8
📌IT learning courses
📌All programing courses
📌Abdul bari courses
📌Ashok IT
📌Linux
📌Networking
📌Design patterns
📌Donet
📌Docker
📌Entity framework
📌Node.js
📌ASP. Net
📌Aps. Net cro
📌java
📌JavaScript
📌full stack developer
Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
🔹Python
🔹Artificial Intelligence
🔹AWS Certified
🔹Cloud
🔹BIG DATA
🔹Data Analytics
🔹BI
🔹Google Cloud Platform
🔹IT Training
🔹MBA
🔹Machine Learning
🔹Deep Learning
🔹Ethical Hacking
🔹SPSS
🔹Statistics
🔹Data Base
🔹Learning language resources English , 🇫🇷
All courses (100 rupees)
Contact:- @meterials_available
85 678
AWS COURSE Classes BY NARESH IT
Google drive Link for 50 rupees
Contact:- @meterials_available
85 678
AP election results
https://results.eci.gov.in/AcResultGenJune2024/partywiseleadresult-1745S01.htm
85 678
+8
📌IT learning courses
📌All programing courses
📌Abdul bari courses
📌Ashok IT
📌Linux
📌Networking
📌Design patterns
📌Donet
📌Docker
📌Entity framework
📌Node.js
📌ASP. Net
📌Aps. Net cro
📌java
📌JavaScript
📌full stack developer
Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
🔹Python
🔹Artificial Intelligence
🔹AWS Certified
🔹Cloud
🔹BIG DATA
🔹Data Analytics
🔹BI
🔹Google Cloud Platform
🔹IT Training
🔹MBA
🔹Machine Learning
🔹Deep Learning
🔹Ethical Hacking
🔹SPSS
🔹Statistics
🔹Data Base
🔹Learning language resources English , 🇫🇷
All courses (100 rupees)
Contact:- @meterials_available
85 678
+8
📌IT learning courses
📌All programing courses
📌Abdul bari courses
📌Ashok IT
📌Linux
📌Networking
📌Design patterns
📌Donet
📌Docker
📌Entity framework
📌Node.js
📌ASP. Net
📌Aps. Net cro
📌java
📌JavaScript
📌full stack developer
Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
🔹Python
🔹Artificial Intelligence
🔹AWS Certified
🔹Cloud
🔹BIG DATA
🔹Data Analytics
🔹BI
🔹Google Cloud Platform
🔹IT Training
🔹MBA
🔹Machine Learning
🔹Deep Learning
🔹Ethical Hacking
🔹SPSS
🔹Statistics
🔹Data Base
🔹Learning language resources English , 🇫🇷
All courses (100 rupees)
Contact:- @meterials_available
85 678
import math
AC
def is_nprime(x): if x <2: return False for i in range(2, int(math.sqrt(x)) + 1): if x % i == 0: return x == i*i return True
def count_nearly_primes(L, R): nPrimes = 0 for x in range(L+1, R): if is_nprime(x): nPrimes += 1 return nPrimes
L = int(input()) R = int(input()) result = count_nearly..primes(L, R) print(result)
Count of Nearly Primes
Python3
85 678
def count_arrays(N, K, X):
MOD = 1000000007
if N == 1:
return 1 if X == 1 else 0
a = [0] * (N + 1)
b = [0] * (N + 1)
a[1] = 1
b[1] = 0
for i in range(2, N + 1):
a[i] = (a[i - 1] * (K - 2) + b[i - 1] * (K - 1)) % MOD
b[i] = a[i - 1] % MOD
return b[N]
N = int(input())
K = int(input())
X = int(input())
print(count_arrays(N, K, X))
Number Of Array code
Thoughtwork exam
Python3
Telegram:- @allcoding1_official
