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allcoding1_official

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تُعد قناة allcoding1_official (@allcoding1_official) في القطاع اللغوي الإنكليزية لاعباً نشطاً. يضم المجتمع حالياً 85 678 مشتركاً، محتلاً المرتبة 1 508 في فئة التكنولوجيات والتطبيقات والمرتبة 3 501 في منطقة الهند.

📊 مؤشرات الجمهور والحراك

منذ تأسيسه في невідомо، حقق المشروع نمواً سريعاً وجمع 85 678 مشتركاً.

بحسب آخر البيانات بتاريخ 21 يونيو, 2026، تحافظ القناة على نشاط مستقر. خلال آخر 30 يوماً تغيّر عدد الأعضاء بمقدار -1 434، وفي آخر 24 ساعة بمقدار -33، مع بقاء الوصول العام مرتفعاً.

  • حالة التحقق: غير موثّقة
  • معدل التفاعل (ER): يبلغ متوسط تفاعل الجمهور 3.09‎%. وخلال أول 24 ساعة من النشر يحصد المحتوى عادةً 0.73‎% من ردود الفعل نسبةً إلى إجمالي المشتركين.
  • وصول المنشورات: يحصل كل منشور على متوسط 2 645 مشاهدة. وخلال اليوم الأول يجمع عادةً 625 مشاهدة.
  • التفاعلات والاستجابة: يتفاعل الجمهور بانتظام؛ متوسط التفاعلات لكل منشور يبلغ 1.
  • الاهتمامات الموضوعية: يركز المحتوى على مواضيع رئيسية مثل dsa, stack, namaste, javascript, dev.

📝 الوصف وسياسة المحتوى

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بفضل وتيرة التحديث المرتفعة (أحدث البيانات بتاريخ 22 يونيو, 2026) تحافظ القناة على حداثتها ومستوى وصول مرتفع. وتُظهر التحليلات تفاعلاً نشطاً من الجمهور، ما يجعلها نقطة تأثير مهمة ضمن فئة التكنولوجيات والتطبيقات.

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import java.util.Scanner; public class Main {     public static void main(String[] args) {         Scanner scanner = new Scanner(System.in);                 int n = scanner.nextInt();         int[] left = new int[n];         int[] right = new int[n];                 for (int i = 0; i < n; i++) {             left[i] = scanner.nextInt();             right[i] = scanner.nextInt();         }                 int sumLeft = 0;         int sumRight = 0;                 for (int i = 0; i < n; i++) {             sumLeft += left[i];             sumRight += right[i];         }                 if (sumLeft % 2 == 0 && sumRight % 2 == 0) {             System.out.println(0);             return;         }                 boolean possible = false;         for (int i = 0; i < n; i++) {             int newSumLeft = sumLeft - left[i] + right[i];             int newSumRight = sumRight - right[i] + left[i];             if (newSumLeft % 2 == 0 && newSumRight % 2 == 0) {                 possible = true;                 break;             }         }                 if (possible) {             System.out.println(1);         } else {             System.out.println(-1);         }     } }

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Count children Thoughtwork exam Python3 Telegram:-
Count children Thoughtwork exam Python3 Telegram:-

Prime partition
Prime partition

Well growing crops Thoughtwork exam Python3 Telegram:- @allcoding1
Well growing crops Thoughtwork exam Python3 Telegram:- @allcoding1

Dark lane
Dark lane

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import math AC def is_nprime(x): if x <2: return False for i in range(2, int(math.sqrt(x)) + 1): if x % i == 0: return x == i*i return True def count_nearly_primes(L, R): nPrimes = 0 for x in range(L+1, R): if is_nprime(x): nPrimes += 1 return nPrimes L = int(input()) R = int(input()) result = count_nearly..primes(L, R) print(result) Count of Nearly Primes Python3

def count_arrays(N, K, X):     MOD = 1000000007         if N == 1:         return 1 if X == 1 else 0     a = [0] * (N + 1)     b = [0] * (N + 1)         a[1] = 1     b[1] = 0         for i in range(2, N + 1):         a[i] = (a[i - 1] * (K - 2) + b[i - 1] * (K - 1)) % MOD         b[i] = a[i - 1] % MOD         return b[N] N = int(input()) K = int(input()) X = int(input()) print(count_arrays(N, K, X)) Number Of Array code Thoughtwork exam Python3 Telegram:- @allcoding1_official