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allcoding1_official
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📈 Analytical overview of Telegram channel allcoding1_official
Channel allcoding1_official (@allcoding1_official) in the English language segment is an active participant. Currently, the community unites 85 467 subscribers, ranking 1 502 in the Technologies & Applications category and 3 471 in the India region.
📊 Audience metrics and dynamics
Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 85 467 subscribers.
According to the latest data from 25 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -1 422 over the last 30 days and by -71 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 2.42%. Within the first 24 hours after publication, content typically collects 0.88% reactions from the total number of subscribers.
- Post reach: On average, each post receives 2 071 views. Within the first day, a publication typically gains 749 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 4.
- Thematic interests: Content is focused on key topics such as dsa, stack, namaste, javascript, dev.
📝 Description and content policy
Channel description not provided.
Thanks to the high frequency of updates (latest data received on 26 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.
85 467
Subscribers
-7124 hours
-3077 days
-1 42230 days
Posts Archive
85 463
import math
AC
def is_nprime(x): if x <2: return False for i in range(2, int(math.sqrt(x)) + 1): if x % i == 0: return x == i*i return True
def count_nearly_primes(L, R): nPrimes = 0 for x in range(L+1, R): if is_nprime(x): nPrimes += 1 return nPrimes
L = int(input()) R = int(input()) result = count_nearly..primes(L, R) print(result)
Count of Nearly Primes
Python3
85 463
def count_arrays(N, K, X):
MOD = 1000000007
if N == 1:
return 1 if X == 1 else 0
a = [0] * (N + 1)
b = [0] * (N + 1)
a[1] = 1
b[1] = 0
for i in range(2, N + 1):
a[i] = (a[i - 1] * (K - 2) + b[i - 1] * (K - 1)) % MOD
b[i] = a[i - 1] % MOD
return b[N]
N = int(input())
K = int(input())
X = int(input())
print(count_arrays(N, K, X))
Number Of Array code
Thoughtwork exam
Python3
Telegram:- @allcoding1_official
85 463
+8
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Repost from allcoding1
+8
📌IT learning courses
📌All programing courses
📌Abdul bari courses
📌Ashok IT
📌Linux
📌Networking
📌Design patterns
📌Donet
📌Docker
📌Entity framework
📌Node.js
📌ASP. Net
📌Aps. Net cro
📌java
📌JavaScript
📌full stack developer
Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
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🔹Learning language resources English , 🇫🇷
All courses (100 rupees)
Contact:- @meterials_available
proof:- https://t.me/+mP2YTsMihZozNWQ1
85 463
Repost from allcoding1
+8
📌IT learning courses
📌All programing courses
📌Abdul bari courses
📌Ashok IT
📌Linux
📌Networking
📌Design patterns
📌Donet
📌Docker
📌Entity framework
📌Node.js
📌ASP. Net
📌Aps. Net cro
📌java
📌JavaScript
📌full stack developer
Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
🔹Python
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🔹AWS Certified
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Contact:- @meterials_available
proof:- https://t.me/+mP2YTsMihZozNWQ1
85 463
Banking Name : RESHMA DEVI V
Upi id : onlyrashmi8930@cnrb
Don't send money
It's fake
85 463
Repost from allcoding1
+8
📌IT learning courses
📌All programing courses
📌Abdul bari courses
📌Ashok IT
📌Linux
📌Networking
📌Design patterns
📌Donet
📌Docker
📌Entity framework
📌Node.js
📌ASP. Net
📌Aps. Net cro
📌java
📌JavaScript
📌full stack developer
Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
🔹Python
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🔹Learning language resources English , 🇫🇷
All courses (100 rupees)
Contact:- @meterials_available
proof:- https://t.me/+mP2YTsMihZozNWQ1
85 463
This my telegram I'D official
Don't send money anybody
I do help personal exam help i can post only on my telegram channels and groups
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85 463
+8
📌IT learning courses
📌All programing courses
📌Abdul bari courses
📌Ashok IT
📌Linux
📌Networking
📌Design patterns
📌Donet
📌Docker
📌Entity framework
📌Node.js
📌ASP. Net
📌Aps. Net cro
📌java
📌JavaScript
📌full stack developer
Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
🔹Python
🔹Artificial Intelligence
🔹AWS Certified
🔹Cloud
🔹BIG DATA
🔹Data Analytics
🔹BI
🔹Google Cloud Platform
🔹IT Training
🔹MBA
🔹Machine Learning
🔹Deep Learning
🔹Ethical Hacking
🔹SPSS
🔹Statistics
🔹Data Base
🔹Learning language resources English , 🇫🇷
All courses (100 rupees)
Contact:- @meterials_available
proof:- https://t.me/+mP2YTsMihZozNWQ1
85 463
📌IT learning courses
📌All programing courses
📌Abdul bari courses
📌Ashok IT
📌
Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
🔹Python
🔹Artificial Intelligence
🔹AWS Certified
🔹Cloud
🔹BIG DATA
🔹Data Analytics
🔹BI
🔹Google Cloud Platform
🔹IT Training
🔹MBA
🔹Machine Learning
🔹Deep Learning
🔹Ethical Hacking
🔹SPSS
🔹Statistics
🔹Data Base
🔹Learning language resources English , 🇫🇷
All courses (100 rupees)
Contact:- @meterials_available
85 463
+8
📌IT learning courses
📌All programing courses
📌Abdul bari courses
📌Ashok IT
Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
🔹Python
🔹Artificial Intelligence
🔹AWS Certified
🔹Cloud
🔹BIG DATA
🔹Data Analytics
🔹BI
🔹Google Cloud Platform
🔹IT Training
🔹MBA
🔹Machine Learning
🔹Deep Learning
🔹Ethical Hacking
🔹SPSS
🔹Statistics
🔹Data Base
🔹Learning language resources English , 🇫🇷
All courses (100 rupees)
Contact:- @meterials_available
85 463
#include <iostream>
#include <vector>
#include <climits>
#include <algorithm>
using namespace std;
int minimum_energy_cost_recursive(int index,int idxy, int left_consecutive, int right_consecutive, int N, int X, int Y, int El, int Er, vector<int>& weights) {
// Base case: if we have reached the end of bags
if (index > idxy) {
return 0;
}
// Calculate the cost of picking from the left and the right
int cost_left = weights[index] * X + (left_consecutive ? El : 0) +
minimum_energy_cost_recursive(index + 1,idxy, 1, 0, N, X, Y, El, Er, weights);
int cost_right = weights[idxy] * Y + (right_consecutive ? Er : 0) +
minimum_energy_cost_recursive(index ,idxy-1, 0, 1, N, X, Y, El, Er, weights);
// Return the minimum of both choices
return min(cost_left, cost_right);
}
int main() {
int N, X, Y, El, Er;
cin >> N >> X >> Y >> El >> Er;
vector<int> weights(N);
for (int i = 0; i < N; ++i) {
cin >> weights[i];
}
cout << minimum_energy_cost_recursive(0,N-1, 0, 0, N, X, Y, El, Er, weights) << endl;
return 0;
}
Amazon Hackon exam
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