SQL Programming Resources
前往频道在 Telegram
Find top SQL resources from global universities, cool projects, and learning materials for data analytics. Admin: @coderfun Useful links: heylink.me/DataAnalytics Promotions: @love_data
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网络:📈 Telegram 频道 SQL Programming Resources 的分析概览
频道 SQL Programming Resources (@sqlanalyst) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 76 536 名订阅者，在 技术与应用 类别中位列第 1 677，并在 印度 地区排名第 4 007 位。
📊 受众指标与增长动态
自 невідомо 创建以来，项目保持高速增长，吸引了 76 536 名订阅者。
根据 25 十月, 2026 的最新数据，频道保持稳定运转。过去 30 天订阅人数变化为 -171，过去 24 小时变化为 -10，整体触达仍然可观。
- 认证状态： 未认证
- 互动率 (ER)： 平均受众互动率为 2.69%。内容发布后 24 小时内通常能获得 1.02% 的反应，占订阅者总量。
- 帖子覆盖： 每篇帖子平均可获得 2 062 次浏览，首日通常累积 779 次浏览。
- 互动与反馈： 受众积极参与，单帖平均反应数为 5。
- 主题关注点： 内容集中在 row, sql, customer_id, logic, desc 等核心主题上。
📝 描述与内容策略
作者将该频道定位为表达主观观点的平台：
“Find top SQL resources from global universities, cool projects, and learning materials for data analytics.
Admin: @coderfun
Useful links: heylink.me/DataAnalytics
Promotions: @love_data”
凭借高频更新（最新数据采集于 26 十月, 2026），频道始终保持新鲜度与高覆盖。分析显示受众积极互动，使其成为 技术与应用 类别中的关键影响点。
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频道帖子
| 2 | Which window function gives the previous row's value? | 1 165 |
| 3 | Which clause is evaluated to filter rows before GROUP BY? | 1 111 |
| 4 | What does DISTINCT do? | 959 |
| 5 | What does COUNT(*) count? | 961 |
| 6 |  🚀𝗠𝗔𝗦𝗧𝗘𝗥 𝗘𝗫𝗖𝗘𝗟 𝗙𝗢𝗥 𝗙𝗥𝗘𝗘 𝗜𝗡 𝟮𝟬𝟮𝟲! 📊
Discover 4 FREE Websites to learn Microsoft Excel from beginner to advanced level! 🎓
🔥 FREE Learning Resources
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🔥 Practical Examples & Exercises
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⚡ One powerful skill can open doors to multiple career opportunities! | 1 140 |
| 7 | What is the key difference between UNION and UNION ALL? | 1 278 |
| 8 | Which clause is evaluated to filter rows before GROUP BY? | 1 143 |
| 9 | What does DISTINCT do? | 1 148 |
| 10 | What will this query return?
SELECT COUNT(salary)
FROM Employee; If the table has 10 rows and 3 employees have NULL salary: | 1 145 |
| 11 | What does COUNT(*) count? | 1 134 |
| 12 |  𝗗𝗮𝘁𝗮 𝗦𝗰𝗶𝗲𝗻𝗰𝗲 & 𝗠𝗮𝗰𝗵𝗶𝗻𝗲 𝗟𝗲𝗮𝗿𝗻𝗶𝗻𝗴 𝗙𝗥𝗘𝗘 𝗢𝗻𝗹𝗶𝗻𝗲 𝗠𝗮𝘀𝘁𝗲𝗿𝗰𝗹𝗮𝘀𝘀 📊
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| 14 | SQL Interview Series — Part 13
📌 Question 13: Find Employees Earning More Than the Company Average
Suppose you have an Employee table:
employee_id | employee_name | department | salary
------------|---------------|------------|-------
1 | Amit | IT | 50000
2 | Rahul | IT | 80000
3 | Priya | HR | 60000
4 | Neha | HR | 90000
5 | Raj | Finance | 70000
❓ Find all employees whose salary is greater than the average salary of the entire company.
💡 Approach
First, calculate the average salary across all employees.
Then compare every employee's salary with that average.
Company average:
(50000 + 80000 + 60000 + 90000 + 70000) / 5
= 70000
Employees earning more than 70000:
Rahul → 80000
Neha → 90000
📌 SQL Solution
SELECT
employee_id,
employee_name,
department,
salary
FROM Employee
WHERE salary > (
SELECT AVG(salary)
FROM Employee
);
🔎 How does it work?
The subquery:
SELECT AVG(salary)
FROM Employee;
calculates the company-wide average:
70000
The outer query then checks:
WHERE salary > 70000
and returns only employees earning above that amount.
📌 Expected Result:
employee_name | department | salary
--------------|------------|-------
Rahul | IT | 80000
Neha | HR | 90000
Double Tap ❤️ For More
-----
1.33 ₽ · /balance_help | 1 778 |
| 15 |  𝗧𝗔𝗧𝗔 𝗙𝗥𝗘𝗘 𝗠𝗜𝗖𝗥𝗢-𝗜𝗡𝗧𝗘𝗥𝗡𝗦𝗛𝗜𝗣𝗦 𝟮𝟬𝟮𝟲! 🎓
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| 17 | SQL Interview Series — Part 12
📌 Question 12: Find the Department with the Highest Average Salary
Suppose you have an Employee table:
employee_id | employee_name | department | salary
------------|---------------|------------|-------
1 | Amit | IT | 60000
2 | Rahul | IT | 80000
3 | Priya | HR | 70000
4 | Neha | HR | 90000
5 | Raj | Finance | 85000
6 | Karan | Finance | 95000
❓ Find the department that has the highest average salary.
💡 Approach
First, calculate the average salary for every department.
Then, find the department with the highest average.
Department averages:
IT → (60000 + 80000) / 2 = 70000
HR → (70000 + 90000) / 2 = 80000
Finance → (85000 + 95000) / 2 = 90000
Therefore:
Finance → 90000
📌 SQL Solution
SELECT
department,
AVG(salary) AS avg_salary
FROM Employee
GROUP BY department
ORDER BY avg_salary DESC
LIMIT 1;
Expected result:
department | avg_salary
-----------|-----------
Finance | 90000
🔎 How does it work?
1️⃣ "GROUP BY department"
Creates one group for each department.
2️⃣ "AVG(salary)"
Calculates the average salary within each department.
3️⃣ "ORDER BY avg_salary DESC"
Places the department with the highest average first.
4️⃣ "LIMIT 1"
Returns only the top department.
⚠️ Interview Trap
What if two departments have the same highest average salary?
For example:
IT → 80000
HR → 80000
Finance → 75000
"LIMIT 1" would return only one department.
If the interviewer asks:
👉 "Find all departments having the highest average salary"
then use a ranking approach:
SELECT department, avg_salary
FROM (
SELECT
department,
AVG(salary) AS avg_salary,
DENSE_RANK() OVER (
ORDER BY AVG(salary) DESC
) AS rnk
FROM Employee
GROUP BY department
) d
WHERE rnk = 1;
Now both IT and HR would be returned.
🎯 Double Tap ❤️ For More
-----
1.3 ₽ · /balance_help | 1 894 |
| 18 |  𝗜𝗕𝗠 𝗙𝗥𝗘𝗘 𝗧𝗘𝗖𝗛 𝗖𝗢𝗨𝗥𝗦𝗘𝗦 𝟮𝟬𝟮𝟲! 🎓
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📲 Save & Share with Friends Preparing for Data Science & AI Jobs! | 1 714 |
| 20 | SQL Interview Series — Part 11
📌 Question 11: Calculate a Running Total of Sales
Suppose you have a Sales table:
sale_id | sale_date | amount
--------|------------|-------
1 | 2026-01-01 | 1000
2 | 2026-01-02 | 1500
3 | 2026-01-03 | 800
4 | 2026-01-04 | 1200
❓ Calculate the cumulative (running) sales amount for each day.
💡 Approach
A running total means:
Current day's sales + all previous sales
For example:
1000
1000 + 1500 = 2500
2500 + 800 = 3300
3300 + 1200 = 4500
The easiest approach is to use the "SUM()" window function.
📌 SQL Solution
SELECT
sale_date,
amount,
SUM(amount) OVER (
ORDER BY sale_date
ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW
) AS running_total
FROM Sales
ORDER BY sale_date;
🔎 How does it work?
1️⃣ "ORDER BY sale_date"
Determines the order in which the running total is calculated.
2️⃣ "SUM(amount) OVER(...)"
Calculates the sum without collapsing the rows like a normal "GROUP BY".
3️⃣ "UNBOUNDED PRECEDING"
Means:
Start from the first row.
4️⃣ "CURRENT ROW"
Means:
Include the current row in the total.
So the calculation becomes:
Date Amount Running Total
---------- -------- -------------
Jan 01 1000 1000
Jan 02 1500 2500
Jan 03 800 3300
Jan 04 1200 4500
⚠️ Interview Trap
Don't use:
GROUP BY sale_date
for a running total.
"GROUP BY" collapses rows into groups.
A window function allows us to calculate an aggregate while keeping individual rows.
Also, if multiple rows can have the same "sale_date", be careful about the ordering. A unique column such as "sale_id" may need to be included:
SUM(amount) OVER (
ORDER BY sale_date, sale_id
ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW
)
🎯 Double Tap ❤️ For More
-----
1.31 ₽ · /balance_help | 1 792 |
