C Programming Language || Hands On Coding

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Hands-on C programming language challenges for beginners. Learn building logic by solving programs. Owner: @Pradeep_saii

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印度30 933 技术与应用9 558...

📈 Telegram 频道 C Programming Language || Hands On Coding 的分析概览

频道 C Programming Language || Hands On Coding (@c_programming_language_coding) 英语语言赛道中的是活跃参与者。目前社区聚集了 12 809 名订阅者，在 技术与应用 类别中位列第 9 558，并在印度地区排名第 30 933 位。

📊 受众指标与增长动态

自 невідомо 创建以来，项目保持高速增长，吸引了 12 809 名订阅者。

根据 29 八月, 2026 的最新数据，频道保持稳定运转。过去 30 天订阅人数变化为 -215，过去 24 小时变化为 -7，整体触达仍然可观。

认证状态： 未认证
互动率 (ER)： 平均受众互动率为 7.22%。内容发布后 24 小时内通常能获得 2.42% 的反应，占订阅者总量。
帖子覆盖： 每篇帖子平均可获得 925 次浏览，首日通常累积 310 次浏览。
互动与反馈： 受众积极参与，单帖平均反应数为 2。
主题关注点： 内容集中在 input, string, scanf("%d, array, element 等核心主题上。

📝 描述与内容策略

作者将该频道定位为表达主观观点的平台：
“Hands-on C programming language challenges for beginners. Learn building logic by solving programs. Owner: @Pradeep_saii”

凭借高频更新（最新数据采集于 30 八月, 2026），频道始终保持新鲜度与高覆盖。分析显示受众积极互动，使其成为 技术与应用 类别中的关键影响点。

12 809

订阅者

-724 小时

-317 天

-21530 天

925

帖子浏览量

~ 31024 小时

~ 40048 小时

7.22%

参与率

无数据

每日帖子数

Ads index

beta

帖子存档

12 809

#CProgramming #Pointers #ArrayReverse

12 809

Reverse Array using Pointers

#include <stdio.h>

void reverseArray(int *arr, int size) {
    int *start = arr;
    int *end = arr + size - 1;
    int temp;

    while (start < end) {
        temp = *start;
        *start = *end;
        *end = temp;
        start++;
        end--;
    }
}

int main() {
    int arr[] = {1, 2, 3, 4, 5};
    int size = sizeof(arr) / sizeof(arr[0]);

    reverseArray(arr, size);

    printf("Reversed array: ");
    for (int i = 0; i < size; i++) {
        printf("%d ", arr[i]);
    }
    printf("\n");

    return 0;
}

12 809

#CProgramming #BitwiseOperators #AdditionWithoutPlus

12 809

Add Two Numbers Without + Operator

#include <stdio.h>

int add(int x, int y) {
    while (y != 0) {
        int carry = x & y;
        x = x ^ y;
        y = carry << 1;
    }
    return x;
}

int main() {
    int num1 = 5;
    int num2 = 10;
    int sum = add(num1, num2);
    printf("Sum of %d and %d is %d\n", num1, num2, sum);
    return 0;
}

12 809

#CProgramming #Bitwise #OddEven

12 809

Odd or Even using Bitwise Operator

#include <stdio.h>

int main() {
    int num = 7;
    if (num & 1) {
        printf("%d is odd.\n", num);
    } else {
        printf("%d is even.\n", num);
    }
    return 0;
}

12 809

#CProgramming #SetBits #LookupTable

12 809

Count Set Bits using Lookup Table

#include <stdio.h>
#include <stdint.h>

unsigned char setBits[256] = {
    0, 1, 1, 2, 1, 2, 2, 3, 1, 2, 2, 3, 2, 3, 3, 4,
    1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5,
    1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5,
    2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6,
    1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5,
    2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6,
    2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6,
    3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7,
    1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5,
    2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6,
    2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6,
    3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7,
    2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6,
    3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7,
    3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7,
    4, 5, 5, 6, 5, 6, 6, 7, 5, 6, 6, 7, 6, 7, 7, 8
};

int countSetBits(int n) {
    int count = 0;
    count += setBits[n & 0xFF];
    n >>= 8;
    count += setBits[n & 0xFF];
    n >>= 8;
    count += setBits[n & 0xFF];
    n >>= 8;
    count += setBits[n & 0xFF];
    return count;
}

int main() {
    int num = 0b10110011101011001101010111100010;
    printf("Number of set bits in %d is %d\n", num, countSetBits(num));
    return 0;
}

12 809

#CProgramming #BitManipulation #RightmostBit

12 809

Isolate Rightmost Set Bit

#include <stdio.h>

int isolateRightmostSetBit(int n) {
    return n & -n;
}

int main() {
    int num = 20; // Example number (binary 10100)
    int isolatedBit = isolateRightmostSetBit(num);
    printf("Original number: %d\n", num);
    printf("Rightmost set bit: %d\n", isolatedBit);
    return 0;
}

12 809

#CProgramming #BitwiseOperations #InterviewQuestion

12 809

Turn Off Rightmost Set Bit

#include <stdio.h>

int turnOffRightmostSetBit(int n) {
    return n & (n - 1);
}

int main() {
    int num = 12; 
    int result = turnOffRightmostSetBit(num);
    printf("Original number: %d\n", num);
    printf("Number with rightmost set bit turned off: %d\n", result);
    return 0;
}

12 809

#CProgramming #BitManipulation #RightmostBit

12 809

Find Position of Rightmost Set Bit

#include <stdio.h>

int findRightmostSetBit(unsigned int n) {
    if (n == 0) {
        return 0; 
    }
    int pos = 1;
    while ((n & 1) == 0) {
        n = n >> 1;
        pos++;
    }
    return pos;
}

int main() {
    unsigned int num = 12;  // Example number (1100 in binary)
    int position = findRightmostSetBit(num);
    printf("Rightmost set bit is at position: %d\n", position);
    return 0;
}

12 809

#CProgramming #BitManipulation #RightmostBit

12 809

Find Position of Rightmost Set Bit

#include <stdio.h>

int findRightmostSetBit(unsigned int n) {
    if (n == 0)
        return 0;
    int pos = 1;
    while ((n & 1) == 0) {
        n = n >> 1;
        pos++;
    }
    return pos;
}

int main() {
    unsigned int num = 12; // Example: 1100 in binary
    int position = findRightmostSetBit(num);
    printf("Rightmost set bit is at position: %d\n", position);
    return 0;
}

12 809

#CProgramming #BitManipulation

12 809

Check if Number has Only One Bit Set

#include <stdio.h>
#include <stdbool.h>

bool isOnlyOneBitSet(int n) {
    if (n <= 0) {
        return false;
    }
    return (n & (n - 1)) == 0;
}

int main() {
    int num = 8;
    if (isOnlyOneBitSet(num)) {
        printf("%d has only one bit set.\n", num);
    } else {
        printf("%d does not have only one bit set.\n", num);
    }
    return 0;
}

12 809

#CProgramming #BitwiseOperators #Optimization

12 809

Divide/Multiply by 2 using Bit Shift

#include <stdio.h>

int main() {
    int num = 16;
    int multiplyBy2 = num << 1;
    int divideBy2 = num >> 1;

    printf("Original number: %d\n", num);
    printf("Multiplied by 2: %d\n", multiplyBy2);
    printf("Divided by 2: %d\n", divideBy2);

    return 0;
}