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allcoding1

allcoding1

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allcoding1 (@allcoding1) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 21 545 obunachidan iborat bo'lib, Taʼlim toifasida 9 078-o'rinni va Hindiston mintaqasida 18 983-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 21 545 obunachiga ega bo‘ldi.

31 Avgust, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -369 ga, so‘nggi 24 soatda esa -5 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 6.77% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining N/A% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 1 460 marta ko‘riladi; birinchi sutkada odatda 0 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 0 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, learning kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Kanal uchun tavsif kiritilmagan.

Yuqori yangilanish chastotasi (oxirgi ma’lumot 01 Sentabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

21 545
Obunachilar
-524 soatlar
-817 kun
-36930 kun
Postlar arxiv
500 TB Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intel
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500 TB Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources ( English🏴󐁧󐁢󐁥󐁮󐁧󐁿 , French🇨🇵 , German🇩🇪 ) ₹300 Contact:- @meterials_available #paid promotion

Repost from allcoding1
🎯SAS Off Campus Drive 2024 – Associate Software Engineer – Freshers | Rs 4-8 LPA Job Role : Associate Software Developer Qualification : B.E/B/Tech/M.E. / M.Tech Experience : Freshers Job Location : Pune Package : Rs 4-8 LPA Apply Now:- https://www.allcoding1.com/2024/02/sas-off-campus-drive-2024-associate_9.html?m=1 Telegram:- @allcoding1

Repost from allcoding1
🎯Atos Is Hiring Degree:- Any Graduate Batch:- 2019, 2020, 2021, 2022, 2023 & 2024 Apply Now:-  https://www.allcoding1.com/2024/02/atos-off-campus-drive-for-any-graduate.html Telegram:- @allcoding1

Repost from allcoding1
500 TB Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intel
+2
500 TB Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources ( English🏴󐁧󐁢󐁥󐁮󐁧󐁿 , French🇨🇵 , German🇩🇪 ) ₹300 Contact:- @meterials_available #paid promotion

Circle code IBM
Circle code IBM

Minimum Moves IBM
Minimum Moves IBM

Virtual Machine Wissen
Virtual Machine Wissen

BST code IBM
BST code IBM

Minimum moves Wissen
Minimum moves Wissen

🎯SAS Off Campus Drive 2024 – Associate Software Engineer – Freshers | Rs 4-8 LPA Job Role : Associate Software Developer Qualification : B.E/B/Tech/M.E. / M.Tech Experience : Freshers Job Location : Pune Package : Rs 4-8 LPA Apply Now:- https://www.allcoding1.com/2024/02/sas-off-campus-drive-2024-associate_9.html?m=1 Telegram:- @allcoding1

🎯Atos Is Hiring Degree:- Any Graduate Batch:- 2019, 2020, 2021, 2022, 2023 & 2024 Apply Now:-  https://www.allcoding1.com/2024/02/atos-off-campus-drive-for-any-graduate.html Telegram:- @allcoding1

500 TB Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intel
+2
500 TB Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources ( English🏴󐁧󐁢󐁥󐁮󐁧󐁿 , French🇨🇵 , German🇩🇪 ) ₹300 Contact:- @meterials_available #paid promotion

🎯Atos Is Hiring Degree:- Any Graduate Batch:- 2019, 2020, 2021, 2022, 2023 & 2024 Apply Now:- https://www.allcoding1.com/2024/02/atos-off-campus-drive-for-any-graduate.html Telegram:- @allcoding1

def helper(reward): nums = [] for i in reward: heappush(nums, -i) ans = -heappop(nums) i = 1 while nums: temp = -heappop(nums
def helper(reward): nums = [] for i in reward: heappush(nums, -i) ans = -heappop(nums) i = 1 while nums: temp = -heappop(nums) if temp - i <= 0: break ans += temp - i i += 1 return ans @allcoding1

int getMinlength(vector<int>a,int k) { int ans=1; long long mul=1; for(int i=0;i<a.size();i++){ if(mul*a[i]>k){ ans++; mul=a[i]; } else{ mul*=a[i]; } } return ans; } L&T @allcoding1 Q) compressing array

any paid promotion DM :- @Priya_i

🎯Atos Is Hiring Degree:- Any Graduate Batch:- 2019, 2020, 2021, 2022, 2023 & 2024 Apply Now:- https://www.allcoding1.com/2024/02/atos-off-campus-drive-for-any-graduate.html Telegram:- @allcoding1

sticker.webp0.13 KB

public class Solution {     public static int longestArraySegment(int array_length, List<Integer> arr) {         int maxLength = 1;         int currentLength = 1;         for (int i = 1; i < array_length; i++) {             if (arr.get(i) > arr.get(i - 1)) {                 currentLength++;             } else {                 currentLength = 1;             }             maxLength = Math.max(maxLength, currentLength);         }         currentLength = 1;         for (int i = 1; i < array_length; i++) {             if (arr.get(i) < arr.get(i - 1)) {                 currentLength++;             } else {                 currentLength = 1;             }             maxLength = Math.max(maxLength, currentLength);         }         return maxLength;     } Ever increasing and ever decreasing - L&T Java Telegram:- @allcoding1