allcoding1
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allcoding1 (@allcoding1) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 21 533 obunachidan iborat bo'lib, Taʼlim toifasida 9 159-o'rinni va Hindiston mintaqasida 19 101-o'rinni egallagan.
📊 Auditoriya ko‘rsatkichlari va dinamika
невідомо sanasidan buyon loyiha tez o‘sib, 21 533 obunachiga ega bo‘ldi.
01 Sentabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -367 ga, so‘nggi 24 soatda esa -14 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.
- Tasdiqlash holati: Tasdiqlanmagan
- Jalb etish (ER): Auditoriya o‘rtacha 7.16% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.25% ini tashkil etuvchi reaksiyalarni to‘playdi.
- Post qamrovi: Har bir post o‘rtacha 1 543 marta ko‘riladi; birinchi sutkada odatda 270 ta ko‘rish yig‘iladi.
- Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 0 ta reaksiya keladi.
- Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, learning kabi asosiy mavzularga jamlangan.
📝 Tavsif va kontent siyosati
Kanal uchun tavsif kiritilmagan.
Yuqori yangilanish chastotasi (oxirgi ma’lumot 02 Sentabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.
21 533
Obunachilar
-1424 soatlar
-797 kun
-36730 kun
Postlar arxiv
21 533
+1int solve(vector<int>& arr) { int n = arr.size(); if (n == 0) return 0;
int maxLen = 1; int currLen = 1; bool f = true;
for (int i = 1; i < n; ++i) { if ((arr[i] > arr[i-1] && f) II (arr[i] < arr[i-1] && !f)) { ++currLen; } else {
maxLen = max(maxLen, currLen); currLen = 2; f = arr[i] > arr[i-1]; }
maxLen = max(maxLen, currLen); return maxLen; }
C++
Telegram:- @allcoding1
L&T
21 533
int solve(vector<int>& arr) { int narr.size(); if (n == 0) return 0;
int maxLen = 1;
int currLen = 1;
bool f = true;
for (int i = 1; i < n; ++i) { if ((arr[i] > arr[i-1] && f) || (arr[i] < arr[i-1] && !f)) { ++currLen; } else { maxLen = max(maxLen, currLen); currLen = 2;
f = arr[i] > arr[i-1]
}
}
maxLen = max(maxLen, currLen); return maxLen;
}
C++
Telegram:- @allcoding1
L&t
Q) Ever - increasing & ever decreasing array segments
21 533
int solve(vector<int>& A) { int s = 0; for (const auto&n: A) { string sn = to_string(n); char md = *max_element(sn.begin().
sn.end());
s += md-'0';
}
return s;
}
C++
Telegram:- @allcoding1
L&t
Q) Encryption by digits
21 533
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21 533
21 533
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Job Position:- IT Software Developer (UX/UI/Fullstack)
Job ID: 3058496
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Job Location:- Hyderabad, India
Department: Software Engineering
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21 533
def check_first_and_last_char(Str):
if Str[0].isdigit() and not Str[-1].isdigit():
print("Yes")
elif Str[-1].isdigit() and not Str[0].isdigit():
print("No")
else:
print("Invalid input")
Str = input()
check_first_and_last_char(Str)
@allcoding1
21 533
def check_digit_position(s):
if s[0].isdigit() and not s[-1].isdigit():
return "Yes"
elif not s[0].isdigit() and s[-1].isdigit():
return "No"
else:
return "Invalid input"
input_str = input().strip()
print(check_digit_position(input_str))
@allcoding1
21 533
def check_digit_position(s):
if s[0].isdigit() and not s[-1].isdigit():
return "Yes"
elif not s[0].isdigit() and s[-1].isdigit():
return "No"
else:
return "Invalid input"
input_str = input().strip()
print(check_digit_position(input_str))
Telegram:- @allcoding1
21 533
🎯Qualcomm Off Campus Recruitment
Job Position:- IT Software Developer (UX/UI/Fullstack)
Job ID: 3058496
Qualification:- B.Tech
Batch:- 2019/2020/2021
Job Location:- Hyderabad, India
Department: Software Engineering
Salary Package:- As per Company Standards
Job Type:- Full-time
Last Date:- ASAP
Apply Now:- https://www.allcoding1.com/2024/02/qualcomm-off-campus-recruitment-2024.html?m=1
Telegram:- @allcoding1
21 533
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Telegram:- @allcoding1
21 533
🎯HCLTech Is Hiring
Degree:- Any Graduate
Batch:- 2020, 2021, 2022, 2023
WWW.allcoding1.com
@allcoding1_official
21 533
Meesho is hiring SDE
Apply link 👇
https://jobs.lever.co/meesho/b4bfd213-f69f-4dff-a51b-9816c27d4343
Telegram:- @allcoding1
