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allcoding1

allcoding1

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📈 Analytical overview of Telegram channel allcoding1

Channel allcoding1 (@allcoding1) in the English language segment is an active participant. Currently, the community unites 22 543 subscribers, ranking 8 854 in the Education category and 19 507 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 22 543 subscribers.

According to the latest data from 14 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -445 over the last 30 days and by -14 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 6.31%. Within the first 24 hours after publication, content typically collects 1.25% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 1 423 views. Within the first day, a publication typically gains 282 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
  • Thematic interests: Content is focused on key topics such as dsa, stack, namaste, javascript, learning.

📝 Description and content policy

Channel description not provided.

Thanks to the high frequency of updates (latest data received on 16 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

22 543
Subscribers
-1424 hours
-947 days
-44530 days
Posts Archive

Company Name: Upstox Role: SDE Intern Batch eligible: 2023 and 2024 passouts Apply: https://docs.google.com/forms/d/e/1FAIpQLSebiXUKhTEoHvCnZFPDCGPqart5Qt3X48ToLgHBY7caw2CFLA/viewform

Company Name : Freshworks INC Role : 1. Application Developer            2. Software Developer Package Freshers: 5LPA Package Experience (1-2 yrs) : 7.5 LPA Skills Needed : Java , Python , HTML, CSS, Java Script,  SQL and DBMS. Location: Bangalore and Chennai (currently remote) Passed out : 2021 - 2025 Round 1 : Coding Assessment Live in Google meet with interviewer (30 mins) Round 2 : Technical Interview (30 mins) Round 3 : HR Interview (20 mins) https://docs.google.com/forms/d/e/1FAIpQLScSh9qPFBce3XvlCUbm4ZpIKuqTcN6IIsdTLPh2WXhAC4XRfQ/viewform?usp=sf_link

Repost from allcoding1
500 TB Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intel
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500 TB Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources ( English🏴󐁧󐁢󐁥󐁮󐁧󐁿 , French🇨🇵 , German🇩🇪 ) ₹300 Contact:- @meterials_available

Nvidia answer 1)011 2)16 3)64 4)i) 100W ii)OW iii)20W iv)0.357 5)8 and 16 6)z=0 7)2:1 8)9 9)0.44 10)200 11)40 12)3.0 13)16 14)750 and 50 15)500 16)60 17)5 18)657 19)250 and 96 20)24 @allcoding1

Nvidia exam Ans

Long term Vs short term investment analysis ✅
Long term Vs short term investment analysis ✅

Monthly job postings and freelancer registrations report ✅
Monthly job postings and freelancer registrations report ✅

Send a Questions

Repost from allcoding1
500 TB Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intel
+1
500 TB Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources ( English🏴󐁧󐁢󐁥󐁮󐁧󐁿 , French🇨🇵 , German🇩🇪 ) ₹300 Contact:- @meterials_available

struct Request {     string id;     string start_time;     string end_time; }; b
struct Request {     string id;     string start_time;     string end_time; }; bool compare(Request a, Request b) {     return a.start_time < b.start_time; } int solve(vector<Request> requests) {     sort(requests.begin(), requests.end(), compare);     int max_concurrent = 0;     int current_concurrent = 0;     string current_end_time = "00:00:00";     for (Request request : requests) {         if (request.start_time >= current_end_time) {             current_concurrent--;         } else {             current_concurrent++;             if (current_concurrent > max_concurrent) {                 max_concurrent = current_concurrent;             }         }         if (request.end_time > current_end_time) {             current_end_time = request.end_time;         }     }     return max_concurrent; } @allcoding1_official

sticker.webp0.05 KB

#define vv(a) vector<vector<int>>(a) int solve(int n, int m, vector<vector<int>> &a) { vv(right)(n, vector<int>(m, 0)); vv(down)(n, vector<int>(m, 0)); vv(left)(n, vector<int>(m, 0)); for (int i = 0; i < n; i++) { int cnt = 0; for (int j = m - 1; j >= 0; j--) { right[i][j] = cnt; if (a[i][j] == 1) cnt++; } } for (int i = 0; i < n; i++) { int cnt = 0; for (int j = 0; j < m; j++) { left[i][j] = cnt; if (a[i][j] == 1) cnt++; } } for (int j = 0; j < m; j++) { int cnt = 0; for (int i = n - 1; i >= 0; i--) { down[i][j] = cnt; if (a[i][j] == 1) cnt++; } } int ans = 0; for (int i = 0; i < n; i++) { for (int j = 0; j < m; j++) { if (a[i][j] == 1) { ans += (right[i][j] * down[i][j]); ans += (left[i][j] * down[i][j]); } } } return ans; } C++ Telegram:- @allcoding1

photo content

URL Hashing Telegram:- @allcoding1
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URL Hashing Telegram:- @allcoding1

Telegram:- @allcoding1
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Telegram:- @allcoding1

int solve(int n, vector&amp; arr) { &nbsp;&nbsp;&nbsp; while (arr.size() &gt; 1) { &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;
int solve(int n, vector<int>& arr) {     while (arr.size() > 1) {         int len = INT_MAX;         int idx = -1;         for (int i = 0; i < arr.size() - 1; ++i) {             int d = arr[i + 1];             if (d == 0 || arr[i] == 0) {                 continue;             }             int r = min(arr[i] % d, d % arr[i]);             if (r < len) {                 len = r;                 idx = i;             }         }         if (idx == -1) {             break;         }         int d = arr[idx + 1];         if (d != 0) {             arr[idx] = min(arr[idx] % d, d % arr[idx]);         }         arr.erase(arr.begin() + idx + 1);     }     return arr.size(); } Women Day Mathematics Challenge Telegram:- @allcoding1