现已上线！2025 年 Telegram 研究 — 年度关键洞察 
allcoding1
前往频道在 Telegram
📈 Telegram 频道 allcoding1 的分析概览
频道 allcoding1 (@allcoding1) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 22 543 名订阅者，在 教育 类别中位列第 8 854，并在 印度 地区排名第 19 507 位。
📊 受众指标与增长动态
自 невідомо 创建以来，项目保持高速增长，吸引了 22 543 名订阅者。
根据 14 六月, 2026 的最新数据，频道保持稳定运转。过去 30 天订阅人数变化为 -445，过去 24 小时变化为 -14，整体触达仍然可观。
- 认证状态： 未认证
- 互动率 (ER)： 平均受众互动率为 6.31%。内容发布后 24 小时内通常能获得 1.25% 的反应，占订阅者总量。
- 帖子覆盖： 每篇帖子平均可获得 1 423 次浏览，首日通常累积 282 次浏览。
- 互动与反馈： 受众积极参与，单帖平均反应数为 2。
- 主题关注点： 内容集中在 dsa, stack, namaste, javascript, learning 等核心主题上。
📝 描述与内容策略
尚未提供频道描述。
凭借高频更新（最新数据采集于 16 六月, 2026），频道始终保持新鲜度与高覆盖。分析显示受众积极互动，使其成为 教育 类别中的关键影响点。
22 543
订阅者
-1424 小时
-947 天
-44530 天
帖子存档
22 543
https://app.joinsuperset.com/join/#/signup/student?jp=38d74885-556d-43a9-b493-4dcbd0f4af73
2024 batch eligible only
22 543
Genpact Hiring
Role: Business Analyst
Apply Link:
https://genpact.taleo.net/careersection/sgy_external_career_section/jobdetail.ftl?job=BFS033345
22 543
Company Name: Upstox
Role: SDE Intern
Batch eligible: 2023 and 2024 passouts
Apply: https://docs.google.com/forms/d/e/1FAIpQLSebiXUKhTEoHvCnZFPDCGPqart5Qt3X48ToLgHBY7caw2CFLA/viewform
22 543
Company Name : Freshworks INC
Role : 1. Application Developer
2. Software Developer
Package Freshers: 5LPA
Package Experience (1-2 yrs) : 7.5 LPA
Skills Needed : Java , Python , HTML, CSS, Java Script, SQL and DBMS.
Location: Bangalore and Chennai (currently remote)
Passed out : 2021 - 2025
Round 1 : Coding Assessment Live in Google meet with interviewer (30 mins)
Round 2 : Technical Interview (30 mins)
Round 3 : HR Interview (20 mins)
https://docs.google.com/forms/d/e/1FAIpQLScSh9qPFBce3XvlCUbm4ZpIKuqTcN6IIsdTLPh2WXhAC4XRfQ/viewform?usp=sf_link
22 543
Repost from allcoding1
+1500 TB Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
🔹Python
🔹Artificial Intelligence
🔹AWS Certified
🔹Cloud
🔹BIG DATA
🔹Data Analytics
🔹BI
🔹Google Cloud Platform
🔹IT Training
🔹MBA
🔹Machine Learning
🔹Deep Learning
🔹Ethical Hacking
🔹SPSS
🔹Statistics
🔹Data Base
🔹Learning language resources ( English🏴 , French🇨🇵 , German🇩🇪 )
₹300
Contact:- @meterials_available
22 543
Nvidia answer
1)011
2)16
3)64 4)i) 100W
ii)OW iii)20W
iv)0.357
5)8 and 16
6)z=0
7)2:1
8)9
9)0.44
10)200
11)40
12)3.0
13)16
14)750 and 50
15)500
16)60
17)5
18)657
19)250 and 96
20)24
@allcoding1
22 543
Repost from allcoding1
+1500 TB Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
🔹Python
🔹Artificial Intelligence
🔹AWS Certified
🔹Cloud
🔹BIG DATA
🔹Data Analytics
🔹BI
🔹Google Cloud Platform
🔹IT Training
🔹MBA
🔹Machine Learning
🔹Deep Learning
🔹Ethical Hacking
🔹SPSS
🔹Statistics
🔹Data Base
🔹Learning language resources ( English🏴 , French🇨🇵 , German🇩🇪 )
₹300
Contact:- @meterials_available
22 543
struct Request {
string id;
string start_time;
string end_time;
};
bool compare(Request a, Request b) {
return a.start_time < b.start_time;
}
int solve(vector<Request> requests) {
sort(requests.begin(), requests.end(), compare);
int max_concurrent = 0;
int current_concurrent = 0;
string current_end_time = "00:00:00";
for (Request request : requests) {
if (request.start_time >= current_end_time) {
current_concurrent--;
} else {
current_concurrent++;
if (current_concurrent > max_concurrent) {
max_concurrent = current_concurrent;
}
}
if (request.end_time > current_end_time) {
current_end_time = request.end_time;
}
}
return max_concurrent;
}
@allcoding1_official
22 543
#define vv(a) vector<vector<int>>(a)
int solve(int n, int m, vector<vector<int>> &a)
{
vv(right)(n, vector<int>(m, 0));
vv(down)(n, vector<int>(m, 0));
vv(left)(n, vector<int>(m, 0));
for (int i = 0; i < n; i++)
{
int cnt = 0;
for (int j = m - 1; j >= 0; j--)
{
right[i][j] = cnt;
if (a[i][j] == 1)
cnt++;
}
}
for (int i = 0; i < n; i++)
{
int cnt = 0;
for (int j = 0; j < m; j++)
{
left[i][j] = cnt;
if (a[i][j] == 1)
cnt++;
}
}
for (int j = 0; j < m; j++)
{
int cnt = 0;
for (int i = n - 1; i >= 0; i--)
{
down[i][j] = cnt;
if (a[i][j] == 1)
cnt++;
}
}
int ans = 0;
for (int i = 0; i < n; i++)
{
for (int j = 0; j < m; j++)
{
if (a[i][j] == 1)
{
ans += (right[i][j] * down[i][j]);
ans += (left[i][j] * down[i][j]);
}
}
}
return ans;
}
C++
Telegram:- @allcoding1
22 543
int solve(int n, vector<int>& arr) {
while (arr.size() > 1) {
int len = INT_MAX;
int idx = -1;
for (int i = 0; i < arr.size() - 1; ++i) {
int d = arr[i + 1];
if (d == 0 || arr[i] == 0) {
continue;
}
int r = min(arr[i] % d, d % arr[i]);
if (r < len) {
len = r;
idx = i;
}
}
if (idx == -1) {
break;
}
int d = arr[idx + 1];
if (d != 0) {
arr[idx] = min(arr[idx] % d, d % arr[idx]);
}
arr.erase(arr.begin() + idx + 1);
}
return arr.size();
}
Women Day Mathematics Challenge
Telegram:- @allcoding1
