Learn Python Coding
Learn Python through simple, practical examples and real coding ideas. Clear explanations, useful snippets, and hands-on learning for anyone starting or improving their programming skills. Admin: @HusseinSheikho || @Hussein_Sheikho
نمایش بیشتر📈 تحلیل کانال تلگرام Learn Python Coding
کانال Learn Python Coding (@pythonre) در بخش زبانی انگلیسی بازیگری فعال است. در حال حاضر جامعه شامل 40 348 مشترک است و جایگاه 3 227 را در دسته فناوری و برنامهها و رتبه 9 434 را در منطقه الهند دارد.
📊 شاخصهای مخاطب و پویایی
از زمان ایجاد در невідомо، پروژه رشد سریعی داشته و 40 348 مشترک جذب کرده است.
بر اساس آخرین دادهها در تاریخ 14 سپتامبر, 2026، کانال فعالیت پایداری دارد. در ۳۰ روز گذشته تغییر اعضا برابر 244 و در ۲۴ ساعت گذشته برابر 19 بوده و همچنان دسترسی گستردهای حفظ شده است.
- وضعیت تأیید: تأیید نشده
- نرخ تعامل (ER): میانگین تعامل مخاطب 3.04% است و در ۲۴ ساعت نخست پس از انتشار، محتوا معمولاً 1.21% واکنش نسبت به کل مشترکان کسب میکند.
- دسترسی پستها: هر پست به طور میانگین 1 226 بازدید دریافت میکند. در اولین روز معمولاً 488 بازدید جمعآوری میشود.
- واکنشها و تعامل: مخاطبان بهطور فعال حمایت میکنند؛ میانگین واکنش به هر پست 3 است.
- علایق موضوعی: محتوا بر موضوعات کلیدی مانند math, harvard, oxford, supervision, waybienad تمرکز دارد.
📝 توضیح و سیاست محتوایی
نویسنده این فضا را محل بیان دیدگاههای شخصی توصیف میکند:
“Learn Python through simple, practical examples and real coding ideas. Clear explanations, useful snippets, and hands-on learning for anyone starting or improving their programming skills.
Admin: @HusseinSheikho || @Hussein_Sheikho”
به لطف بهروزرسانیهای پرتکرار (آخرین داده در تاریخ 15 سپتامبر, 2026)، کانال همواره بهروز و دارای دسترسی بالاست. تحلیلها نشان میدهد مخاطبان بهطور فعال با محتوا تعامل دارند و آن را به نقطه اثرگذاری مهم در دسته فناوری و برنامهها تبدیل کردهاند.
در حال بارگیری داده...
| تاریخ | رشد مشترکین | اشارات | کانالها | |
| 15 سپتامبر | 0 | |||
| 14 سپتامبر | +21 | |||
| 13 سپتامبر | +57 | |||
| 12 سپتامبر | +32 | |||
| 11 سپتامبر | +10 | |||
| 10 سپتامبر | +12 | |||
| 09 سپتامبر | +13 | |||
| 08 سپتامبر | +12 | |||
| 07 سپتامبر | +19 | |||
| 06 سپتامبر | +7 | |||
| 05 سپتامبر | +22 | |||
| 04 سپتامبر | +23 | |||
| 03 سپتامبر | +14 | |||
| 02 سپتامبر | +17 | |||
| 01 سپتامبر | +13 |
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| 5 | Creating Nested Dictionary Values using `setdefault()` 🔥
When grouping data, it's often necessary to check if a key exists, create a container for it, and then add a value.
For example, distributing users by role. Without special methods, this usually involves a separate key check.
users = [
("admin", "alex"),
("user", "max"),
("admin", "kate"),
]
groups = {}
for role, name in users:
if role not in groups:
groups[role] = []
groups[role].append(name)
The setdefault() method allows you to perform this operation directly when accessing the dictionary. If the key exists, it returns its current value. If the key is missing, the provided value is written to the dictionary and then returned:
groups = {}
for role, name in users:
groups.setdefault(
role,
[],
).append(name)
The result is the same structure without a separate key existence check:
print(groups)
# {
# 'admin': ['alex', 'kate'],
# 'user': ['max']
# }
It's important to note that the expression of the second argument is evaluated every time setdefault() is called, even if the key already exists. Therefore, you should avoid creating expensive objects or performing functions with side effects there:
value = cache.setdefault(
key,
build_value(),
)
In this code, build_value() will be called before the method itself is executed. If the value creation should only happen when the key is missing, it's better to use an explicit check or a suitable data structure, such as defaultdict.
🔥 setdefault() is well-suited for compactly initializing simple mutable containers when grouping and aggregating data. However, it's important to remember that the provided value is evaluated regardless of whether the key exists.
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| 18 | Why identical arguments can create different entries in `lru_cache`? 🤔
The lru_cache creates a key not only from the values of the arguments, but also from the way they are passed.
load(True)
load(debug=True)
Although both calls pass the same value, for the cache, these are different keys, so the function will be executed twice.
print(load.cache_info())
# CacheInfo(hits=0, misses=2, ...)
The order of named arguments can also affect how an entry is created in the cache.
func(a=1, b=2)
func(b=2, a=1)
Therefore, it is best to call cached functions in a consistent style: either by position or by name, in the same order.
load(debug=True)
load(debug=True)
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