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AddMath Spmnetic!™⚡️

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Tarmoq: Sejarah spmnetic!™Hindiston9 910Taʼlim4 922...

📈 Telegram kanali AddMath Spmnetic!™⚡️ analitikasi

AddMath Spmnetic!™⚡️ (@addmathspmnotes) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 38 215 obunachidan iborat bo'lib, Taʼlim toifasida 4 922-o'rinni va Hindiston mintaqasida 9 910-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 38 215 obunachiga ega bo‘ldi.

01 Noyabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni 939 ga, so‘nggi 24 soatda esa 28 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

Tasdiqlash holati: Tasdiqlanmagan
Jalb etish (ER): Auditoriya o‘rtacha 12.94% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 6.07% ini tashkil etuvchi reaksiyalarni to‘playdi.
Post qamrovi: Har bir post o‘rtacha 4 942 marta ko‘riladi; birinchi sutkada odatda 2 318 ta ko‘rish yig‘iladi.
Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 14 ta reaksiya keladi.
Tematik yo‘nalishlar: Kontent addmath, untuk, 629/4, math, eqn kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨”

Yuqori yangilanish chastotasi (oxirgi ma’lumot 02 Noyabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

38 215

Obunachilar

+2824 soatlar

+1907 kun

+93930 kun

4 942

Post ko'rishlar

~ 2 31824 soatlar

~ 3 24348 soatlar

12.94%

Muloqot nisbati

~ 5

Kuniga postlar

Ads index

Postlar arxiv

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If you're still confused, check out this video: https://www.youtube.com/watch?v=CmskSlStE6Y&t=8s

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Just guna Thales theorem

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Haha seorang je betul, yg ni Kalau U guna Pythagoras, u akan dapat imaginary roots sbb triangle ni tak boleh exist

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Guys it's not 30

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Find the area

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Repost from Thespmnetic™ 🕵🏻🕵🏻‍♀

Link all subjects under spmnetic! https://spmnetic.carrd.co

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Finally, we multiply both numbers to gather to get the total paths. 15×35 = 525

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Now we focus on this part. You'll love to the right 4 times and 3 times upward. Which gives 7 moves in total. Out of these 7 moves, you'll have to choose 3 moves to be upward and the rest to the right. Hence, the number of path is just 7C3 = 35

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There will be 4 moves to the right and 2 moves upwards. 6 moves total. Out of these six moves, you'll have to choose 2 moves to be moving upwards and the rest will be moving to the right. Hence, the total number of ways is just 6C2 = 15.

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Let's focus here first.

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First step is the same, in which I divided the path into two different sections. I denote the point where the rectangles join as point M.

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Thanks to TonyCWX... Here is the explanation..

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Hi guys, do join to master this chapter!!!

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SEMINAR SIRI 2 - LEARN 2 GET A 📖 CLASS 4 : CONSUMER MATHEMATICS : SAVINGS AND INVESTMENTS, CREDIT AND DEBT (FORM 3) & CONSUMER MATHEMATICS : FINANCIAL MANANGEMENT (FORM 4) (4-8 MARKS) 📖 Date : 21/11/2025 Time : 8:30 - 10:30 PM Link : meet.google.com/gtz-qmyj-vsp Or dial: (US) +1 252-365-5026 PIN: 449 770 748# ✨ Please join the meetings before 5 minutes seminar start. ✨ Recording will be provided incase you are not able to join. ✨ Material will be given before seminar start. Please DO NOT SHARE any material that given from tutor to anyone. ✨ If you have any question, kindly “raise hand” first before you asking. This will help the seminar can be ongoing without disturbance. ✨ Kindly INFORM me earlier if you are not able to join. Please cooperate with us. Thank you.

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Guys kalau nak soalan biasa, mmg Ada Banyak Kat buku teks..so Cuba Tu dulu, Dan kuasai basic Dulu, pastu Cuba buat soalan macam ni

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