AI Coding & CSE Fundamentals
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🚀 Explore AI, Coding & Computer Science Fundamentals. 💻 Programming • DSA • DBMS • OS • Networks 🤖 AI & Emerging Technologies 🛠️ Projects • Tutorials • Learning Resources 📚 Your freedom to gain knowledge for free.
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Канал AI Coding & CSE Fundamentals (@aicoding_csefundamentals) у мовному сегменті Англійська є активним учасником. На даний момент спільнота об'єднує 12 324 підписників, посідаючи 10 232 місце в категорії Технології та додатки та 31 271 місце у регіоні Індія.
📊 Показники аудиторії та динаміка
З моменту свого створення невідомо, проект продемонстрував стрімке зростання, зібравши аудиторію у 12 324 підписників.
За останніми даними від 12 листопада, 2026, канал демонструє стабільну активність. Хоча за останні 30 днів спостерігається зміна кількості учасників на -238, а за останні 24 години на -8, загальне охоплення залишається високим.
- Статус верифікації: Не верифікований
- Рівень залученості (ER): Середній показник залученості аудиторії становить 10.45%. Протягом перших 24 годин після публікації контент зазвичай збирає N/A% реакцій від загальної кількості підписників.
- Охоплення публікацій: В середньому кожен допис отримує 1 288 переглядів. Протягом першої доби публікація в середньому набирає 0 переглядів.
- Реакції та взаємодія: Аудиторія активно підтримує контент: середня кількість реакцій на один пост – 11.
- Тематичні інтереси: Контент зосереджений навколо ключових тем, таких як input, string, scanf("%d, array, element.
📝 Опис та контентна політика
Автор описує ресурс як майданчик для висловлення суб'єктивної думки:
“🚀 Explore AI, Coding & Computer Science Fundamentals.
💻 Programming • DSA • DBMS • OS • Networks
🤖 AI & Emerging Technologies
🛠️ Projects • Tutorials • Learning Resources
📚 Your freedom to gain knowledge for free.”
Завдяки високій частоті оновлень (останні дані отримано 13 листопада, 2026), канал підтримує актуальність та високий рівень охоплення публікацій. Аналітика показує, що аудиторія активно взаємодіє з контентом, що робить його важливою точкою впливу в категорії Технології та додатки.
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📝 Check operator precedence and associativity with an expression
Write a C program that evaluates a given arithmetic expression containing multiple operators (+, -, *, /, %) and parentheses. The program should correctly apply operator precedence and associativity rules to calculate and print the final result of the expression.
Calculate compound assignment operations
#include <stdio.h>
int main() {
int initialValue = 10;
int additionValue = 5;
int subtractionValue = 3;
int multiplicationValue = 2;
float divisionValue = 2.0;
int modulusValue = 3;
int result = initialValue;
printf("Initial value: %dn", result);
result += additionValue;
printf("After addition: %dn", result);
result -= subtractionValue;
printf("After subtraction: %dn", result);
result *= multiplicationValue;
printf("After multiplication: %dn", result);
result /= (int)divisionValue;
printf("After division: %dn", result);
result %= modulusValue;
printf("After modulus: %dn", result);
return 0;
}💡 Approach
Step 1: Declare variables: Declare the variables you'll be using, including the initial values for the operands involved in the compound assignment operations. Make sure to select appropriate data types (e.g., `int`, `float`) based on the expected values.
Step 2: Perform compound assignment operations: Use the compound assignment operators (+=, -=, =, /=, %=) on the variables. For example, `x += y` is equivalent to `x = x + y`. Perform the calculations sequentially as required by the problem.
Step 3: Print the results:* After each compound assignment, or at the end of all operations, print the final values of the variables that were modified. Use `printf` with appropriate format specifiers (e.g., `%d` for integers, `%f` for floats) to display the values correctly.
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📝 Calculate compound assignment operations
Write a C program that takes two integer inputs,
x and y. Perform and print the result of the following compound assignment operations on x: addition assignment (+= y), subtraction assignment (-= y), multiplication assignment (*= y), division assignment (/= y), and modulo assignment (%= y).Use ternary operator (conditional operator)
#include <stdio.h>
int main() {
int number = 10;
int abs_value;
abs_value = (number >= 0) ? number : -number;
printf("The absolute value of %d is %d\n", number, abs_value);
int age = 20;
const char *status;
status = (age >= 18) ? "Adult" : "Minor";
printf("Age: %d, Status: %s\n", age, status);
int a = 5, b = 10, max;
max = (a > b) ? a : b;
printf("The maximum of %d and %d is %d\n", a, b, max);
return 0;
}
💡 Approach
Here's a step-by-step approach to using the ternary operator in C:
Step 1: Identify the Condition: Determine the condition you want to evaluate. This is the expression that will be tested for truthiness.
Step 2: Define the 'True' Result: Decide what value or expression should be executed/returned if the condition is true (non-zero).
Step 3: Define the 'False' Result: Decide what value or expression should be executed/returned if the condition is false (zero).
Step 4: Construct the Ternary Operator: Use the following structure:
(condition) ? (result_if_true) : (result_if_false);
Step 5: Assign or Use the Result: Assign the result of the ternary operation to a variable, use it in a print statement, or in any other way you need to utilize the conditional outcome.
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❤️ Understood | 👎 Not Understood📝 Use ternary operator (conditional operator)
Write a C program that takes two integers as input and uses the ternary operator to determine the larger of the two. Print the larger number to the console.
Demonstrate increment (++) and decrement (--) operators (pre and post)
#include <stdio.h>
int main() {
int x = 10;
int y = 20;
printf("Demonstrating Post-Increment:\n");
printf("Value of x before post-increment: %d\n", x);
printf("Value of x after post-increment: %d\n", x++);
printf("Value of x now: %d\n", x);
x = 10;
printf("\nDemonstrating Pre-Increment:\n");
printf("Value of x before pre-increment: %d\n", x);
printf("Value of x after pre-increment: %d\n", ++x);
printf("Value of x now: %d\n", x);
printf("\nDemonstrating Post-Decrement:\n");
printf("Value of y before post-decrement: %d\n", y);
printf("Value of y after post-decrement: %d\n", y--);
printf("Value of y now: %d\n", y);
y = 20;
printf("\nDemonstrating Pre-Decrement:\n");
printf("Value of y before pre-decrement: %d\n", y);
printf("Value of y after pre-decrement: %d\n", --y);
printf("Value of y now: %d\n", y);
return 0;
}
💡 Approach
Step 1: Declare integer variables: Declare two integer variables,
x and y, and initialize x with a starting value (e.g., 10).
Step 2: Demonstrate post-increment: Print the current value of x. Then, use the post-increment operator (x++) and print the value of x again. Explain the observed change in value.
Step 3: Demonstrate pre-increment: Reset x to its original value (e.g., 10). Then, use the pre-increment operator (++x) and print the value of x. Explain the observed change in value.
Step 4: Demonstrate post-decrement: Initialize another integer variable y (e.g., with 20). Print the current value of y. Then, use the post-decrement operator (y--) and print the value of y again. Explain the observed change in value.
Step 5: Demonstrate pre-decrement: Reset y to its original value (e.g., 20). Then, use the pre-decrement operator (--y) and print the value of y. Explain the observed change in value.
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❤️ Understood | 👎 Not Understood📝 Demonstrate increment (++) and decrement (--) operators (pre and post)
Write a C program that showcases the pre-increment, post-increment, pre-decrement, and post-decrement operators. The program should declare an integer variable, demonstrate each operator on it, and print the value of the variable and the result of the operation after each use to illustrate the difference between pre and post versions.
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Demonstrate assignment operators (=, +=, -=, =, /=, %=)
#include <stdio.h>
int main() {
int a = 10;
int b = 20;
int c = 30;
int d = 5;
int e = 100;
int f = 15;
a = 5;
b += 5;
c -= 5;
d = 5;
e /= 5;
f %= 5;
printf("Value of a: %d\n", a);
printf("Value of b: %d\n", b);
printf("Value of c: %d\n", c);
printf("Value of d: %d\n", d);
printf("Value of e: %d\n", e);
printf("Value of f: %d\n", f);
return 0;
}
💡 Approach
Step 1: Declare integer variables. (Declare variables
a, b, c, d, e, f and initialize them with a value)
Step 2: Demonstrate the assignment operator (=). (Assign a value to variable a using the = operator)
Step 3: Demonstrate the addition assignment operator (+=). (Add a value to variable b using the += operator)
Step 4: Demonstrate the subtraction assignment operator (-=). (Subtract a value from variable c using the -= operator)
Step 5: Demonstrate the multiplication assignment operator (=). (Multiply variable d by a value using the = operator)
Step 6: Demonstrate the division assignment operator (/=). (Divide variable e by a value using the /= operator)
Step 7: Demonstrate the modulus assignment operator (%=). (Find the remainder of dividing variable f by a value using the %= operator)
Step 8: Print the values of all variables. (Print the values of a, b, c, d, e, and f to display the results of the assignment operations.)
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❤️ Understood | 👎 Not Understood📝 Demonstrate assignment operators (=, +=, -=, =, /=, %=)
Write a C program that declares an integer variable, initializes it to a value, and then demonstrates the use of assignment operators ( =, +=, -=, =, /=, %= ) to modify its value. The program should print the value of the variable after each assignment operation.
Demonstrate bitwise operators (&, |, ^, ~, <<, >>)
#include <stdio.h>
int main() {
// Declare and initialize integer variables
int num1 = 12; // Binary: 1100
int num2 = 25; // Binary: 11001
// Demonstrate the AND operator (&)
printf("num1 & num2 = %d (Bitwise AND)\n", num1 & num2);
// Demonstrate the OR operator (|)
printf("num1 | num2 = %d (Bitwise OR)\n", num1 | num2);
// Demonstrate the XOR operator (^)
printf("num1 ^ num2 = %d (Bitwise XOR)\n", num1 ^ num2);
// Demonstrate the NOT operator (~)
printf("~num1 = %d (Bitwise NOT)\n", ~num1);
// Demonstrate the Left Shift operator (<<)
printf("num1 << 2 = %d (Left Shift by 2)\n", num1 << 2);
// Demonstrate the Right Shift operator (>>)
printf("num1 >> 2 = %d (Right Shift by 2)\n", num1 >> 2);
return 0;
}
💡 Approach
Here's a step-by-step approach to demonstrate bitwise operators in C:
Step 1: Declare and Initialize Integer Variables: Create two integer variables (e.g.,
num1, num2) and assign them some initial values. These will be the operands for our bitwise operations.
Step 2: Demonstrate the AND Operator (&): Print the result of num1 & num2. Explain in a comment that this performs a bitwise AND operation.
Step 3: Demonstrate the OR Operator (|): Print the result of num1 | num2. Explain in a comment that this performs a bitwise OR operation.
Step 4: Demonstrate the XOR Operator (^): Print the result of num1 ^ num2. Explain in a comment that this performs a bitwise XOR operation.
Step 5: Demonstrate the NOT Operator (~): Print the result of ~num1. Explain in a comment that this performs a bitwise NOT operation (one's complement).
Step 6: Demonstrate the Left Shift Operator (<<): Print the result of num1 << 2. Explain in a comment that this shifts the bits of num1 two positions to the left.
Step 7: Demonstrate the Right Shift Operator (>>): Print the result of num1 >> 2. Explain in a comment that this shifts the bits of num1 two positions to the right.
Step 8: Add Clear Output with Explanations: For each operation, use printf to display both the operation being performed (e.g., "num1 & num2 = ") and the result, including comments explaining what each operator does.
─────────────────────────────
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❤️ Understood | 👎 Not Understood📝 Demonstrate bitwise operators (&, |, ^, ~, <<, >>)
Write a C program that demonstrates the functionality of bitwise operators: AND (&), OR (|), XOR (^), NOT (~), Left Shift (<<), and Right Shift (>>). The program should take two integer inputs, apply each bitwise operator to them, and print the result of each operation clearly labeled.
Demonstrate logical operators (&&, ||, !)
#include <stdio.h>
int main() {
int a = 5;
int b = 10;
int result;
if (a > 0 && b < 20) {
printf("a is greater than 0 AND b is less than 20\n");
} else {
printf("At least one of the conditions is false\n");
}
result = (a > 0 && b < 20);
printf("Result of (a > 0 && b < 20): %d\n", result);
if (a < 0 || b > 5) {
printf("a is less than 0 OR b is greater than 5\n");
} else {
printf("Both conditions are false\n");
}
result = (a < 0 || b > 5);
printf("Result of (a < 0 || b > 5): %d\n", result);
printf("!(a > b): %d\n", !(a > b));
result = !(a > b);
printf("Result of !(a > b): %d\n", result);
return 0;
}
💡 Approach
Step 1: Declare and Initialize Variables: Declare integer variables
a, b, and result. Assign a and b some initial integer values (e.g., a = 5, b = 10).
Step 2: Demonstrate the AND (&&) Operator: Use an if statement with the && operator to check if a is greater than 0 AND b is less than 20. Print a message to the console based on whether the condition is true or false. Store the result of the conditional expression (a > 0 && b < 20) in the result variable and print its value (1 for true, 0 for false).
Step 3: Demonstrate the OR (||) Operator: Use another if statement with the || operator to check if a is less than 0 OR b is greater than 5. Print a message to the console based on whether the condition is true or false. Store the result of the conditional expression (a < 0 || b > 5) in the result variable and print its value (1 for true, 0 for false).
Step 4: Demonstrate the NOT (!) Operator: Use the ! operator to negate the value of a > b. Print the result to the console. Store the result of the expression !(a > b) in the result variable and print its value (1 for true, 0 for false).
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❤️ Understood | 👎 Not Understood📝 Demonstrate logical operators (&&, ||, !)
Write a C program that prompts the user for two integer values and then uses logical operators (&&, ||, !) to determine and print whether both numbers are positive, if at least one is positive, and if the first number is not positive. Clearly display the results of each logical operation.
