C Programming Codes
C Programming Codes || Quizzes || DSA Learn along with the community Any queries admin - @Pradeep_saii
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Channel C Programming Codes (@c_programming_codes) in the English language segment is an active participant. Currently, the community unites 13 422 subscribers, ranking 9 537 in the Technologies & Applications category and 32 062 in the India region.
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Since its creation on Π½Π΅Π²ΡΠ΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 13 422 subscribers.
According to the latest data from 12 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -240 over the last 30 days and by -9 over the last 24 hours, overall reach remains high.
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βC Programming Codes || Quizzes || DSA
Learn along with the community
Any queries
admin - @Pradeep_saiiβ
Thanks to the high frequency of updates (latest data received on 13 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.
x and y, and initialize x with a starting value (e.g., 10).
Step 2: Demonstrate post-increment: Print the current value of x. Then, use the post-increment operator (x++) and print the value of x again. Explain the observed change in value.
Step 3: Demonstrate pre-increment: Reset x to its original value (e.g., 10). Then, use the pre-increment operator (++x) and print the value of x. Explain the observed change in value.
Step 4: Demonstrate post-decrement: Initialize another integer variable y (e.g., with 20). Print the current value of y. Then, use the post-decrement operator (y--) and print the value of y again. Explain the observed change in value.
Step 5: Demonstrate pre-decrement: Reset y to its original value (e.g., 20). Then, use the pre-decrement operator (--y) and print the value of y. Explain the observed change in value.
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β€οΈ Understood | π Not Understooda, b, c, d, e, f and initialize them with a value)
Step 2: Demonstrate the assignment operator (=). (Assign a value to variable a using the = operator)
Step 3: Demonstrate the addition assignment operator (+=). (Add a value to variable b using the += operator)
Step 4: Demonstrate the subtraction assignment operator (-=). (Subtract a value from variable c using the -= operator)
Step 5: Demonstrate the multiplication assignment operator (=). (Multiply variable d by a value using the = operator)
Step 6: Demonstrate the division assignment operator (/=). (Divide variable e by a value using the /= operator)
Step 7: Demonstrate the modulus assignment operator (%=). (Find the remainder of dividing variable f by a value using the %= operator)
Step 8: Print the values of all variables. (Print the values of a, b, c, d, e, and f to display the results of the assignment operations.)
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β€οΈ Understood | π Not Understoodnum1, num2) and assign them some initial values. These will be the operands for our bitwise operations.
Step 2: Demonstrate the AND Operator (&): Print the result of num1 & num2. Explain in a comment that this performs a bitwise AND operation.
Step 3: Demonstrate the OR Operator (|): Print the result of num1 | num2. Explain in a comment that this performs a bitwise OR operation.
Step 4: Demonstrate the XOR Operator (^): Print the result of num1 ^ num2. Explain in a comment that this performs a bitwise XOR operation.
Step 5: Demonstrate the NOT Operator (~): Print the result of ~num1. Explain in a comment that this performs a bitwise NOT operation (one's complement).
Step 6: Demonstrate the Left Shift Operator (<<): Print the result of num1 << 2. Explain in a comment that this shifts the bits of num1 two positions to the left.
Step 7: Demonstrate the Right Shift Operator (>>): Print the result of num1 >> 2. Explain in a comment that this shifts the bits of num1 two positions to the right.
Step 8: Add Clear Output with Explanations: For each operation, use printf to display both the operation being performed (e.g., "num1 & num2 = ") and the result, including comments explaining what each operator does.
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β€οΈ Understood | π Not Understooda, b, and result. Assign a and b some initial integer values (e.g., a = 5, b = 10).
Step 2: Demonstrate the AND (&&) Operator: Use an if statement with the && operator to check if a is greater than 0 AND b is less than 20. Print a message to the console based on whether the condition is true or false. Store the result of the conditional expression (a > 0 && b < 20) in the result variable and print its value (1 for true, 0 for false).
Step 3: Demonstrate the OR (||) Operator: Use another if statement with the || operator to check if a is less than 0 OR b is greater than 5. Print a message to the console based on whether the condition is true or false. Store the result of the conditional expression (a < 0 || b > 5) in the result variable and print its value (1 for true, 0 for false).
Step 4: Demonstrate the NOT (!) Operator: Use the ! operator to negate the value of a > b. Print the result to the console. Store the result of the expression !(a > b) in the result variable and print its value (1 for true, 0 for false).
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β€οΈ Understood | π Not Understoodint a = 10; int b = 5;
Step 2: Use printf to display the results of each relational operator. For each operator (==, !=, <, >, <=, >=), create a printf statement. The printf statement should display the operator being used and the result (which will be either 1 for true or 0 for false). For example, printf("a == b: %d\n", a == b);
Step 3: Repeat Step 2 for all six relational operators. Ensure each operator is demonstrated comparing the same two integer variables, a and b.
Step 4: Compile and run the program. This will display the output of each printf statement, demonstrating the result of each relational operator comparison.
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