C Programming Codes
C Programming Codes || Quizzes || DSA Learn along with the community Any queries admin - @Pradeep_saii
Mostrar más📈 Análisis del canal de Telegram C Programming Codes
El canal C Programming Codes (@c_programming_codes) en el segmento lingüístico de Inglés es un actor destacado. Actualmente la comunidad reúne a 13 422 suscriptores, ocupando la posición 9 537 en la categoría Tecnologías y Aplicaciones y el puesto 32 062 en la región India.
📊 Métricas de audiencia y dinámica
Desde su creación el невідомо, el proyecto ha mostrado un crecimiento acelerado, reuniendo a 13 422 suscriptores.
Según los últimos datos del 12 junio, 2026, el canal mantiene una actividad estable. En los últimos 30 días la variación de miembros fue de -240, y en las últimas 24 horas de -9, conservando un alto alcance.
- Estado de verificación: No verificado
- Tasa de interacción (ER): El promedio de interacción de la audiencia es 9.78%. Durante las primeras 24 horas tras publicar, el contenido suele obtener N/A% de reacciones respecto al total de suscriptores.
- Alcance de las publicaciones: Cada publicación recibe en promedio 0 visualizaciones. En el primer día suele acumular 0 visualizaciones.
- Reacciones e interacción: La audiencia responde de forma activa: el promedio de reacciones por publicación es 0.
- Intereses temáticos: El contenido se centra en temas clave como input, string, scanf("%d, array, element.
📝 Descripción y política de contenido
El autor describe el recurso como un espacio para expresar opiniones subjetivas:
“C Programming Codes || Quizzes || DSA
Learn along with the community
Any queries
admin - @Pradeep_saii”
Gracias a la alta frecuencia de actualizaciones (últimos datos recibidos el 13 junio, 2026), el canal mantiene la vigencia y un amplio alcance. La analítica demuestra que la audiencia interactúa activamente con el contenido, lo que lo convierte en un punto de referencia dentro de la categoría Tecnologías y Aplicaciones.
x and y, and initialize x with a starting value (e.g., 10).
Step 2: Demonstrate post-increment: Print the current value of x. Then, use the post-increment operator (x++) and print the value of x again. Explain the observed change in value.
Step 3: Demonstrate pre-increment: Reset x to its original value (e.g., 10). Then, use the pre-increment operator (++x) and print the value of x. Explain the observed change in value.
Step 4: Demonstrate post-decrement: Initialize another integer variable y (e.g., with 20). Print the current value of y. Then, use the post-decrement operator (y--) and print the value of y again. Explain the observed change in value.
Step 5: Demonstrate pre-decrement: Reset y to its original value (e.g., 20). Then, use the pre-decrement operator (--y) and print the value of y. Explain the observed change in value.
─────────────────────────────
Have you Understood? Drop a reaction:
❤️ Understood | 👎 Not Understooda, b, c, d, e, f and initialize them with a value)
Step 2: Demonstrate the assignment operator (=). (Assign a value to variable a using the = operator)
Step 3: Demonstrate the addition assignment operator (+=). (Add a value to variable b using the += operator)
Step 4: Demonstrate the subtraction assignment operator (-=). (Subtract a value from variable c using the -= operator)
Step 5: Demonstrate the multiplication assignment operator (=). (Multiply variable d by a value using the = operator)
Step 6: Demonstrate the division assignment operator (/=). (Divide variable e by a value using the /= operator)
Step 7: Demonstrate the modulus assignment operator (%=). (Find the remainder of dividing variable f by a value using the %= operator)
Step 8: Print the values of all variables. (Print the values of a, b, c, d, e, and f to display the results of the assignment operations.)
─────────────────────────────
Have you Understood? Drop a reaction:
❤️ Understood | 👎 Not Understoodnum1, num2) and assign them some initial values. These will be the operands for our bitwise operations.
Step 2: Demonstrate the AND Operator (&): Print the result of num1 & num2. Explain in a comment that this performs a bitwise AND operation.
Step 3: Demonstrate the OR Operator (|): Print the result of num1 | num2. Explain in a comment that this performs a bitwise OR operation.
Step 4: Demonstrate the XOR Operator (^): Print the result of num1 ^ num2. Explain in a comment that this performs a bitwise XOR operation.
Step 5: Demonstrate the NOT Operator (~): Print the result of ~num1. Explain in a comment that this performs a bitwise NOT operation (one's complement).
Step 6: Demonstrate the Left Shift Operator (<<): Print the result of num1 << 2. Explain in a comment that this shifts the bits of num1 two positions to the left.
Step 7: Demonstrate the Right Shift Operator (>>): Print the result of num1 >> 2. Explain in a comment that this shifts the bits of num1 two positions to the right.
Step 8: Add Clear Output with Explanations: For each operation, use printf to display both the operation being performed (e.g., "num1 & num2 = ") and the result, including comments explaining what each operator does.
─────────────────────────────
Have you Understood? Drop a reaction:
❤️ Understood | 👎 Not Understooda, b, and result. Assign a and b some initial integer values (e.g., a = 5, b = 10).
Step 2: Demonstrate the AND (&&) Operator: Use an if statement with the && operator to check if a is greater than 0 AND b is less than 20. Print a message to the console based on whether the condition is true or false. Store the result of the conditional expression (a > 0 && b < 20) in the result variable and print its value (1 for true, 0 for false).
Step 3: Demonstrate the OR (||) Operator: Use another if statement with the || operator to check if a is less than 0 OR b is greater than 5. Print a message to the console based on whether the condition is true or false. Store the result of the conditional expression (a < 0 || b > 5) in the result variable and print its value (1 for true, 0 for false).
Step 4: Demonstrate the NOT (!) Operator: Use the ! operator to negate the value of a > b. Print the result to the console. Store the result of the expression !(a > b) in the result variable and print its value (1 for true, 0 for false).
─────────────────────────────
Have you Understood? Drop a reaction:
❤️ Understood | 👎 Not Understoodint a = 10; int b = 5;
Step 2: Use printf to display the results of each relational operator. For each operator (==, !=, <, >, <=, >=), create a printf statement. The printf statement should display the operator being used and the result (which will be either 1 for true or 0 for false). For example, printf("a == b: %d\n", a == b);
Step 3: Repeat Step 2 for all six relational operators. Ensure each operator is demonstrated comparing the same two integer variables, a and b.
Step 4: Compile and run the program. This will display the output of each printf statement, demonstrating the result of each relational operator comparison.
─────────────────────────────
Have you Understood? Drop a reaction:
❤️ Understood | 👎 Not Understood
¡Ya disponible! Investigación de Telegram 2025 — los principales insights del año 
