C Programming Language || Hands On Coding
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Hands-on C programming language challenges for beginners. Learn building logic by solving programs. Owner: @Pradeep_saii
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El canal C Programming Language || Hands On Coding (@c_programming_language_coding) en el segmento lingüístico de Inglés es un actor destacado. Actualmente la comunidad reúne a 12 822 suscriptores, ocupando la posición 9 572 en la categoría Tecnologías y Aplicaciones y el puesto 31 202 en la región India.
📊 Métricas de audiencia y dinámica
Desde su creación el невідомо, el proyecto ha mostrado un crecimiento acelerado, reuniendo a 12 822 suscriptores.
Según los últimos datos del 27 agosto, 2026, el canal mantiene una actividad estable. En los últimos 30 días la variación de miembros fue de -217, y en las últimas 24 horas de -11, conservando un alto alcance.
- Estado de verificación: No verificado
- Tasa de interacción (ER): El promedio de interacción de la audiencia es 6.62%. Durante las primeras 24 horas tras publicar, el contenido suele obtener 2.42% de reacciones respecto al total de suscriptores.
- Alcance de las publicaciones: Cada publicación recibe en promedio 849 visualizaciones. En el primer día suele acumular 310 visualizaciones.
- Reacciones e interacción: La audiencia responde de forma activa: el promedio de reacciones por publicación es 2.
- Intereses temáticos: El contenido se centra en temas clave como input, string, scanf("%d, array, element.
📝 Descripción y política de contenido
El autor describe el recurso como un espacio para expresar opiniones subjetivas:
“Hands-on C programming language challenges for beginners. Learn building logic by solving programs.
Owner: @Pradeep_saii”
Gracias a la alta frecuencia de actualizaciones (últimos datos recibidos el 28 agosto, 2026), el canal mantiene la vigencia y un amplio alcance. La analítica demuestra que la audiencia interactúa activamente con el contenido, lo que lo convierte en un punto de referencia dentro de la categoría Tecnologías y Aplicaciones.
12 822
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💡 Approach
Step 1: Declare variables: Declare the variables you'll be using, including the initial values for the operands involved in the compound assignment operations. Make sure to select appropriate data types (e.g., `int`, `float`) based on the expected values.
Step 2: Perform compound assignment operations: Use the compound assignment operators (+=, -=, =, /=, %=) on the variables. For example, `x += y` is equivalent to `x = x + y`. Perform the calculations sequentially as required by the problem.
Step 3: Print the results:* After each compound assignment, or at the end of all operations, print the final values of the variables that were modified. Use `printf` with appropriate format specifiers (e.g., `%d` for integers, `%f` for floats) to display the values correctly.
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📝 Calculate compound assignment operations
Write a C program that takes two integer inputs,
x and y. Perform and print the result of the following compound assignment operations on x: addition assignment (+= y), subtraction assignment (-= y), multiplication assignment (*= y), division assignment (/= y), and modulo assignment (%= y).Use ternary operator (conditional operator)
#include <stdio.h>
int main() {
int number = 10;
int abs_value;
abs_value = (number >= 0) ? number : -number;
printf("The absolute value of %d is %d\n", number, abs_value);
int age = 20;
const char *status;
status = (age >= 18) ? "Adult" : "Minor";
printf("Age: %d, Status: %s\n", age, status);
int a = 5, b = 10, max;
max = (a > b) ? a : b;
printf("The maximum of %d and %d is %d\n", a, b, max);
return 0;
}
💡 Approach
Here's a step-by-step approach to using the ternary operator in C:
Step 1: Identify the Condition: Determine the condition you want to evaluate. This is the expression that will be tested for truthiness.
Step 2: Define the 'True' Result: Decide what value or expression should be executed/returned if the condition is true (non-zero).
Step 3: Define the 'False' Result: Decide what value or expression should be executed/returned if the condition is false (zero).
Step 4: Construct the Ternary Operator: Use the following structure:
(condition) ? (result_if_true) : (result_if_false);
Step 5: Assign or Use the Result: Assign the result of the ternary operation to a variable, use it in a print statement, or in any other way you need to utilize the conditional outcome.
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❤️ Understood | 👎 Not Understood📝 Use ternary operator (conditional operator)
Write a C program that takes two integers as input and uses the ternary operator to determine the larger of the two. Print the larger number to the console.
Demonstrate increment (++) and decrement (--) operators (pre and post)
#include <stdio.h>
int main() {
int x = 10;
int y = 20;
printf("Demonstrating Post-Increment:\n");
printf("Value of x before post-increment: %d\n", x);
printf("Value of x after post-increment: %d\n", x++);
printf("Value of x now: %d\n", x);
x = 10;
printf("\nDemonstrating Pre-Increment:\n");
printf("Value of x before pre-increment: %d\n", x);
printf("Value of x after pre-increment: %d\n", ++x);
printf("Value of x now: %d\n", x);
printf("\nDemonstrating Post-Decrement:\n");
printf("Value of y before post-decrement: %d\n", y);
printf("Value of y after post-decrement: %d\n", y--);
printf("Value of y now: %d\n", y);
y = 20;
printf("\nDemonstrating Pre-Decrement:\n");
printf("Value of y before pre-decrement: %d\n", y);
printf("Value of y after pre-decrement: %d\n", --y);
printf("Value of y now: %d\n", y);
return 0;
}
💡 Approach
Step 1: Declare integer variables: Declare two integer variables,
x and y, and initialize x with a starting value (e.g., 10).
Step 2: Demonstrate post-increment: Print the current value of x. Then, use the post-increment operator (x++) and print the value of x again. Explain the observed change in value.
Step 3: Demonstrate pre-increment: Reset x to its original value (e.g., 10). Then, use the pre-increment operator (++x) and print the value of x. Explain the observed change in value.
Step 4: Demonstrate post-decrement: Initialize another integer variable y (e.g., with 20). Print the current value of y. Then, use the post-decrement operator (y--) and print the value of y again. Explain the observed change in value.
Step 5: Demonstrate pre-decrement: Reset y to its original value (e.g., 20). Then, use the pre-decrement operator (--y) and print the value of y. Explain the observed change in value.
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❤️ Understood | 👎 Not Understood📝 Demonstrate increment (++) and decrement (--) operators (pre and post)
Write a C program that showcases the pre-increment, post-increment, pre-decrement, and post-decrement operators. The program should declare an integer variable, demonstrate each operator on it, and print the value of the variable and the result of the operation after each use to illustrate the difference between pre and post versions.
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Demonstrate assignment operators (=, +=, -=, =, /=, %=)
#include <stdio.h>
int main() {
int a = 10;
int b = 20;
int c = 30;
int d = 5;
int e = 100;
int f = 15;
a = 5;
b += 5;
c -= 5;
d = 5;
e /= 5;
f %= 5;
printf("Value of a: %d\n", a);
printf("Value of b: %d\n", b);
printf("Value of c: %d\n", c);
printf("Value of d: %d\n", d);
printf("Value of e: %d\n", e);
printf("Value of f: %d\n", f);
return 0;
}
💡 Approach
Step 1: Declare integer variables. (Declare variables
a, b, c, d, e, f and initialize them with a value)
Step 2: Demonstrate the assignment operator (=). (Assign a value to variable a using the = operator)
Step 3: Demonstrate the addition assignment operator (+=). (Add a value to variable b using the += operator)
Step 4: Demonstrate the subtraction assignment operator (-=). (Subtract a value from variable c using the -= operator)
Step 5: Demonstrate the multiplication assignment operator (=). (Multiply variable d by a value using the = operator)
Step 6: Demonstrate the division assignment operator (/=). (Divide variable e by a value using the /= operator)
Step 7: Demonstrate the modulus assignment operator (%=). (Find the remainder of dividing variable f by a value using the %= operator)
Step 8: Print the values of all variables. (Print the values of a, b, c, d, e, and f to display the results of the assignment operations.)
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❤️ Understood | 👎 Not Understood📝 Demonstrate assignment operators (=, +=, -=, =, /=, %=)
Write a C program that declares an integer variable, initializes it to a value, and then demonstrates the use of assignment operators ( =, +=, -=, =, /=, %= ) to modify its value. The program should print the value of the variable after each assignment operation.
Demonstrate bitwise operators (&, |, ^, ~, <<, >>)
#include <stdio.h>
int main() {
// Declare and initialize integer variables
int num1 = 12; // Binary: 1100
int num2 = 25; // Binary: 11001
// Demonstrate the AND operator (&)
printf("num1 & num2 = %d (Bitwise AND)\n", num1 & num2);
// Demonstrate the OR operator (|)
printf("num1 | num2 = %d (Bitwise OR)\n", num1 | num2);
// Demonstrate the XOR operator (^)
printf("num1 ^ num2 = %d (Bitwise XOR)\n", num1 ^ num2);
// Demonstrate the NOT operator (~)
printf("~num1 = %d (Bitwise NOT)\n", ~num1);
// Demonstrate the Left Shift operator (<<)
printf("num1 << 2 = %d (Left Shift by 2)\n", num1 << 2);
// Demonstrate the Right Shift operator (>>)
printf("num1 >> 2 = %d (Right Shift by 2)\n", num1 >> 2);
return 0;
}
💡 Approach
Here's a step-by-step approach to demonstrate bitwise operators in C:
Step 1: Declare and Initialize Integer Variables: Create two integer variables (e.g.,
num1, num2) and assign them some initial values. These will be the operands for our bitwise operations.
Step 2: Demonstrate the AND Operator (&): Print the result of num1 & num2. Explain in a comment that this performs a bitwise AND operation.
Step 3: Demonstrate the OR Operator (|): Print the result of num1 | num2. Explain in a comment that this performs a bitwise OR operation.
Step 4: Demonstrate the XOR Operator (^): Print the result of num1 ^ num2. Explain in a comment that this performs a bitwise XOR operation.
Step 5: Demonstrate the NOT Operator (~): Print the result of ~num1. Explain in a comment that this performs a bitwise NOT operation (one's complement).
Step 6: Demonstrate the Left Shift Operator (<<): Print the result of num1 << 2. Explain in a comment that this shifts the bits of num1 two positions to the left.
Step 7: Demonstrate the Right Shift Operator (>>): Print the result of num1 >> 2. Explain in a comment that this shifts the bits of num1 two positions to the right.
Step 8: Add Clear Output with Explanations: For each operation, use printf to display both the operation being performed (e.g., "num1 & num2 = ") and the result, including comments explaining what each operator does.
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❤️ Understood | 👎 Not Understood📝 Demonstrate bitwise operators (&, |, ^, ~, <<, >>)
Write a C program that demonstrates the functionality of bitwise operators: AND (&), OR (|), XOR (^), NOT (~), Left Shift (<<), and Right Shift (>>). The program should take two integer inputs, apply each bitwise operator to them, and print the result of each operation clearly labeled.
Demonstrate logical operators (&&, ||, !)
#include <stdio.h>
int main() {
int a = 5;
int b = 10;
int result;
if (a > 0 && b < 20) {
printf("a is greater than 0 AND b is less than 20\n");
} else {
printf("At least one of the conditions is false\n");
}
result = (a > 0 && b < 20);
printf("Result of (a > 0 && b < 20): %d\n", result);
if (a < 0 || b > 5) {
printf("a is less than 0 OR b is greater than 5\n");
} else {
printf("Both conditions are false\n");
}
result = (a < 0 || b > 5);
printf("Result of (a < 0 || b > 5): %d\n", result);
printf("!(a > b): %d\n", !(a > b));
result = !(a > b);
printf("Result of !(a > b): %d\n", result);
return 0;
}
💡 Approach
Step 1: Declare and Initialize Variables: Declare integer variables
a, b, and result. Assign a and b some initial integer values (e.g., a = 5, b = 10).
Step 2: Demonstrate the AND (&&) Operator: Use an if statement with the && operator to check if a is greater than 0 AND b is less than 20. Print a message to the console based on whether the condition is true or false. Store the result of the conditional expression (a > 0 && b < 20) in the result variable and print its value (1 for true, 0 for false).
Step 3: Demonstrate the OR (||) Operator: Use another if statement with the || operator to check if a is less than 0 OR b is greater than 5. Print a message to the console based on whether the condition is true or false. Store the result of the conditional expression (a < 0 || b > 5) in the result variable and print its value (1 for true, 0 for false).
Step 4: Demonstrate the NOT (!) Operator: Use the ! operator to negate the value of a > b. Print the result to the console. Store the result of the expression !(a > b) in the result variable and print its value (1 for true, 0 for false).
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❤️ Understood | 👎 Not Understood📝 Demonstrate logical operators (&&, ||, !)
Write a C program that prompts the user for two integer values and then uses logical operators (&&, ||, !) to determine and print whether both numbers are positive, if at least one is positive, and if the first number is not positive. Clearly display the results of each logical operation.
Demonstrate relational operators (==, !=, <, >, <=, >=)
#include <stdio.h>
int main() {
int num1 = 10;
int num2 = 5;
printf("num1 == num2: %d\n", num1 == num2);
printf("num1 != num2: %d\n", num1 != num2);
printf("num1 < num2: %d\n", num1 < num2);
printf("num1 > num2: %d\n", num1 > num2);
printf("num1 <= num2: %d\n", num1 <= num2);
printf("num1 >= num2: %d\n", num1 >= num2);
return 0;
}
💡 Approach
Step 1: Declare and initialize two integer variables. This provides the values we'll use to demonstrate the relational operators. For example,
int a = 10; int b = 5;
Step 2: Use printf to display the results of each relational operator. For each operator (==, !=, <, >, <=, >=), create a printf statement. The printf statement should display the operator being used and the result (which will be either 1 for true or 0 for false). For example, printf("a == b: %d\n", a == b);
Step 3: Repeat Step 2 for all six relational operators. Ensure each operator is demonstrated comparing the same two integer variables, a and b.
Step 4: Compile and run the program. This will display the output of each printf statement, demonstrating the result of each relational operator comparison.
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