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📈 Аналітичний огляд Telegram-каналу allcoding1

Канал allcoding1 (@allcoding1) у мовному сегменті Англійська є активним учасником. На даний момент спільнота об'єднує 22 590 підписників, посідаючи 8 822 місце в категорії Освіта та 19 518 місце у регіоні Індія.

📊 Показники аудиторії та динаміка

З моменту свого створення невідомо, проект продемонстрував стрімке зростання, зібравши аудиторію у 22 590 підписників.

За останніми даними від 12 червня, 2026, канал демонструє стабільну активність. Хоча за останні 30 днів спостерігається зміна кількості учасників на -437, а за останні 24 години на -6, загальне охоплення залишається високим.

  • Статус верифікації: Не верифікований
  • Рівень залученості (ER): Середній показник залученості аудиторії становить 5.99%. Протягом перших 24 годин після публікації контент зазвичай збирає 1.25% реакцій від загальної кількості підписників.
  • Охоплення публікацій: В середньому кожен допис отримує 1 353 переглядів. Протягом першої доби публікація в середньому набирає 283 переглядів.
  • Реакції та взаємодія: Аудиторія активно підтримує контент: середня кількість реакцій на один пост – 2.
  • Тематичні інтереси: Контент зосереджений навколо ключових тем, таких як dsa, stack, namaste, javascript, learning.

📝 Опис та контентна політика

Опис каналу не надано.

Завдяки високій частоті оновлень (останні дані отримано 13 червня, 2026), канал підтримує актуальність та високий рівень охоплення публікацій. Аналітика показує, що аудиторія активно взаємодіє з контентом, що робить його важливою точкою впливу в категорії Освіта.

22 590
Підписники
-624 години
-967 днів
-43730 день
Архів дописів
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🎯Accenture Job role:- Associate Software Engineer (ASE) Experience: 0 Month - 11 Month(s) Salary: INR 4,60,700 - Job Type: Full Time Location: Bangalore, Hyderabad, Pune, Mumbai, Chennai, Gurugram, Kolkata, Indore, Jaipur, Coimbatore, Ahmedabad, Bhubaneswar Apply Now:- https://indiacampus.accenture.com/myzone/accenture/1/jobs/25377/job-details Telegram:- @allcoding1

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Repost from allcoding1_official
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT 📌Linux 📌Networking 📌Design patterns 📌Donet 📌Docker 📌Entity framework 📌Node.js 📌ASP. Net 📌Aps. Net cro 📌java 📌JavaScript 📌full stack developer Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources  English , 🇫🇷 𝐂𝐘𝐁𝐄𝐑 𝐒𝐄𝐂𝐔𝐑𝐈𝐓𝐘 𝐀𝐋𝐋  𝐂𝐎𝐔𝐑𝐒𝐄 ⚡️ Reconnaissance and Footprinting ⚡️ Network Scanning ⚡️ Enumeration ⚡️ Firewalls HIDs Honeypot ⚡️ Malware and Threats ⚡️ Mobile Platform ⚡️ Pentesting ⚡️ Sql Injection ⚡️ System Hacking ⚡️ Web Application ⚡️ Wireless Network ⚡️ Cloud Computing ⚡️ Web Server ⚡️ Social Engineering ⚡️ Session Hijacking ⚡️ Sniffing ⚡️ BufferOverflow ⚡️ Cryptography ⚡️ Denial Of Service All courses @ 50 rupees Contact:- @meterials_available

Repost from allcoding1_official
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT 📌Linux 📌Networking 📌Design patterns 📌Donet
+7
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT 📌Linux 📌Networking 📌Design patterns 📌Donet 📌Docker 📌Entity framework 📌Node.js 📌ASP. Net 📌Aps. Net cro 📌java 📌JavaScript 📌full stack developer Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources  English , 🇫🇷 𝐂𝐘𝐁𝐄𝐑 𝐒𝐄𝐂𝐔𝐑𝐈𝐓𝐘 𝐀𝐋𝐋  𝐂𝐎𝐔𝐑𝐒𝐄 ⚡️ Reconnaissance and Footprinting ⚡️ Network Scanning ⚡️ Enumeration ⚡️ Firewalls HIDs Honeypot ⚡️ Malware and Threats ⚡️ Mobile Platform ⚡️ Pentesting ⚡️ Sql Injection ⚡️ System Hacking ⚡️ Web Application ⚡️ Wireless Network ⚡️ Cloud Computing ⚡️ Web Server ⚡️ Social Engineering ⚡️ Session Hijacking ⚡️ Sniffing ⚡️ BufferOverflow ⚡️ Cryptography ⚡️ Denial Of Service All courses @ 75rs Contact:- @meterials_available

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📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT 📌Linux 📌Networking 📌Design patterns 📌Donet
+7
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT 📌Linux 📌Networking 📌Design patterns 📌Donet 📌Docker 📌Entity framework 📌Node.js 📌ASP. Net 📌Aps. Net cro 📌java 📌JavaScript 📌full stack developer Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources  English , 🇫🇷 𝐂𝐘𝐁𝐄𝐑 𝐒𝐄𝐂𝐔𝐑𝐈𝐓𝐘 𝐀𝐋𝐋  𝐂𝐎𝐔𝐑𝐒𝐄 ⚡️ Reconnaissance and Footprinting ⚡️ Network Scanning ⚡️ Enumeration ⚡️ Firewalls HIDs Honeypot ⚡️ Malware and Threats ⚡️ Mobile Platform ⚡️ Pentesting ⚡️ Sql Injection ⚡️ System Hacking ⚡️ Web Application ⚡️ Wireless Network ⚡️ Cloud Computing ⚡️ Web Server ⚡️ Social Engineering ⚡️ Session Hijacking ⚡️ Sniffing ⚡️ BufferOverflow ⚡️ Cryptography ⚡️ Denial Of Service All courses (100 rupees) Contact:- @meterials_available

Repost from allcoding1_official
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT 📌Linux 📌Networking 📌Design patterns 📌Donet
+7
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT 📌Linux 📌Networking 📌Design patterns 📌Donet 📌Docker 📌Entity framework 📌Node.js 📌ASP. Net 📌Aps. Net cro 📌java 📌JavaScript 📌full stack developer Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources  English , 🇫🇷 𝐂𝐘𝐁𝐄𝐑 𝐒𝐄𝐂𝐔𝐑𝐈𝐓𝐘 𝐀𝐋𝐋  𝐂𝐎𝐔𝐑𝐒𝐄 ⚡️ Reconnaissance and Footprinting ⚡️ Network Scanning ⚡️ Enumeration ⚡️ Firewalls HIDs Honeypot ⚡️ Malware and Threats ⚡️ Mobile Platform ⚡️ Pentesting ⚡️ Sql Injection ⚡️ System Hacking ⚡️ Web Application ⚡️ Wireless Network ⚡️ Cloud Computing ⚡️ Web Server ⚡️ Social Engineering ⚡️ Session Hijacking ⚡️ Sniffing ⚡️ BufferOverflow ⚡️ Cryptography ⚡️ Denial Of Service All courses @ 70 rupees Contact:- @meterials_available

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Repost from allcoding1
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT 📌Linux 📌Networking 📌Design patterns 📌Donet
+7
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT 📌Linux 📌Networking 📌Design patterns 📌Donet 📌Docker 📌Entity framework 📌Node.js 📌ASP. Net 📌Aps. Net cro 📌java 📌JavaScript 📌full stack developer Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources  English , 🇫🇷 𝐂𝐘𝐁𝐄𝐑 𝐒𝐄𝐂𝐔𝐑𝐈𝐓𝐘 𝐀𝐋𝐋  𝐂𝐎𝐔𝐑𝐒𝐄 ⚡️ Reconnaissance and Footprinting ⚡️ Network Scanning ⚡️ Enumeration ⚡️ Firewalls HIDs Honeypot ⚡️ Malware and Threats ⚡️ Mobile Platform ⚡️ Pentesting ⚡️ Sql Injection ⚡️ System Hacking ⚡️ Web Application ⚡️ Wireless Network ⚡️ Cloud Computing ⚡️ Web Server ⚡️ Social Engineering ⚡️ Session Hijacking ⚡️ Sniffing ⚡️ BufferOverflow ⚡️ Cryptography ⚡️ Denial Of Service All courses (100 rupees) Contact:- @meterials_available

#include #include #include using namespace std; double solve(const vector& cnts) { vector den = {0.20, 0.40, 1, 2, 5, 10}
#include <iostream> #include <vector> #include <numeric> using namespace std; double solve(const vector<int>& cnts) { vector<double> den = {0.20, 0.40, 1, 2, 5, 10}; double tot = 0.0; for (size_t i = 0; i < cnts.size(); ++i) { tot += cnts[i] * den[i]; } return tot; } int main() { vector<int> cnts; int input; while (cin >> input) { cnts.push_back(input); } cout << solve(cnts) << endl; return 0; }

#include <bits/stdc++.h> int getMinimumStress(int graph_nodes, int graph_edges, vector<pair<int, int>>& edges, vector<int>& weights, int source, int destination) { Graph graph(graph_nodes + 1); for (int i = 0; i < graph_edges; ++i) { int u = edges[i].first; int v = edges[i].second; int w = weights[i]; graph[u].push_back({v, w}); graph[v].push_back({u, w}); } priority_queue<pii, vector<pii>, greater<pii>> pq; vector<int> min_stress(graph_nodes + 1, INT_MAX ); pq.push({0, source}); min_stress[source] = 0; while (!pq.empty()) { int curr_stress = pq.top().first; int u = pq.top().second; pq.pop(); if (u == destination) { return curr_stress; } if (curr_stress > min_stress[u]) { continue; } for (const auto& neighbor : graph[u]) { int v = neighbor.first; int weight = neighbor.second; int next_stress = max(curr_stress, weight); if (next_stress < min_stress[v]) { min_stress[v] = next_stress; pq.push({next_stress, v}); } } } return -1; }

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#include <iostream> #include <vector> #include <cmath> #include <string> #include <algorithm> using namespace std; int main() {     vector<string> k = {"1234567890", "qwertyuiop", "asdfghjkl", "zxcvbnm"};     string w;     getline(cin, w);     transform(w.begin(), w.end(), w.begin(), ::tolower);     vector<string> words;     string temp;     for (char c : w)     {         if (c == ' ')         {             if (!temp.empty())             {                 words.push_back(temp);                 temp.clear();             }         }         else         {             temp += c;         }     }     if (!temp.empty())     {         words.push_back(temp);     }     int t = 0;     for (string v : words)     {         int l = v.length();         vector<int> r(l, -1);         vector<int> p(l, -1);         for (int i = 0; i < l; ++i)         {             bool f = false;             for (int j = 0; j < k.size(); ++j)             {                 int c = k[j].find(v[i]);                 if (c != string::npos)                 {                     r[i] = j;                     p[i] = c;                     f = true;                     break;                 }             }             if (!f)             {                 break;             }         }         int c = 0;         for (int i = 1; i < l; ++i)         {             if (r[i] == r[i - 1] && abs(p[i] - p[i - 1]) <= 1)             {                 c += 1;             }             else             {                 if (c > 0)                 {                     if (r[i - 1] == -1)                     {                         t += 2;                     }                     else                     {                         t += 1;                     }                     c = 0;                 }             }         }         if (c > 0)         {             if (r[l - 1] == -1)             {                 t += 2;             }             else             {                 t += 1;             }         }     }     cout << t << endl;     return 0; }

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