allcoding1
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إظهار المزيد
📈 نظرة تحليلية على قناة تيليجرام allcoding1
تُعد قناة allcoding1 (@allcoding1) في القطاع اللغوي الإنكليزية لاعباً نشطاً. يضم المجتمع حالياً 22 590 مشتركاً، محتلاً المرتبة 8 822 في فئة التعليم والمرتبة 19 518 في منطقة الهند.
📊 مؤشرات الجمهور والحراك
منذ تأسيسه في невідомо، حقق المشروع نمواً سريعاً وجمع 22 590 مشتركاً.
بحسب آخر البيانات بتاريخ 12 يونيو, 2026، تحافظ القناة على نشاط مستقر. خلال آخر 30 يوماً تغيّر عدد الأعضاء بمقدار -437، وفي آخر 24 ساعة بمقدار -6، مع بقاء الوصول العام مرتفعاً.
- حالة التحقق: غير موثّقة
- معدل التفاعل (ER): يبلغ متوسط تفاعل الجمهور 5.99%. وخلال أول 24 ساعة من النشر يحصد المحتوى عادةً 1.25% من ردود الفعل نسبةً إلى إجمالي المشتركين.
- وصول المنشورات: يحصل كل منشور على متوسط 1 353 مشاهدة. وخلال اليوم الأول يجمع عادةً 283 مشاهدة.
- التفاعلات والاستجابة: يتفاعل الجمهور بانتظام؛ متوسط التفاعلات لكل منشور يبلغ 2.
- الاهتمامات الموضوعية: يركز المحتوى على مواضيع رئيسية مثل dsa, stack, namaste, javascript, learning.
📝 الوصف وسياسة المحتوى
وصف القناة غير متوفر.
بفضل وتيرة التحديث المرتفعة (أحدث البيانات بتاريخ 13 يونيو, 2026) تحافظ القناة على حداثتها ومستوى وصول مرتفع. وتُظهر التحليلات تفاعلاً نشطاً من الجمهور، ما يجعلها نقطة تأثير مهمة ضمن فئة التعليم.
22 590
المشتركون
-624 ساعات
-967 أيام
-43730 أيام
أرشيف المشاركات
22 590
+7
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🔹SPSS
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🔹Data Base
🔹Learning language resources English , 🇫🇷
𝐂𝐘𝐁𝐄𝐑 𝐒𝐄𝐂𝐔𝐑𝐈𝐓𝐘 𝐀𝐋𝐋 𝐂𝐎𝐔𝐑𝐒𝐄
⚡️ Reconnaissance and Footprinting
⚡️ Network Scanning
⚡️ Enumeration
⚡️ Firewalls HIDs Honeypot
⚡️ Malware and Threats
⚡️ Mobile Platform
⚡️ Pentesting
⚡️ Sql Injection
⚡️ System Hacking
⚡️ Web Application
⚡️ Wireless Network
⚡️ Cloud Computing
⚡️ Web Server
⚡️ Social Engineering
⚡️ Session Hijacking
⚡️ Sniffing
⚡️ BufferOverflow
⚡️ Cryptography
⚡️ Denial Of Service
All courses (100 rupees)
Contact:- @meterials_available
22 590
Meesho | SDE l - Android | 17 - 21 LPA ( expected ) | 1+ year experience | Bangalore
Link : https://meesho.io/jobs/android-developer---i?id=f35e1cae-5847-4b92-bd76-c0474197724f
22 590
🎯Accenture
Job role:- Associate Software Engineer (ASE)
Experience: 0 Month - 11 Month(s)
Salary: INR 4,60,700 -
Job Type: Full Time
Location: Bangalore, Hyderabad, Pune, Mumbai, Chennai, Gurugram, Kolkata, Indore, Jaipur, Coimbatore, Ahmedabad, Bhubaneswar
Apply Now:- https://indiacampus.accenture.com/myzone/accenture/1/jobs/25377/job-details
Telegram:- @allcoding1
22 590
+7
📌IT learning courses
📌All programing courses
📌Abdul bari courses
📌Ashok IT
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📌Donet
📌Docker
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📌Node.js
📌ASP. Net
📌Aps. Net cro
📌java
📌JavaScript
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Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
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🔹BI
🔹Google Cloud Platform
🔹IT Training
🔹MBA
🔹Machine Learning
🔹Deep Learning
🔹Ethical Hacking
🔹SPSS
🔹Statistics
🔹Data Base
🔹Learning language resources English , 🇫🇷
𝐂𝐘𝐁𝐄𝐑 𝐒𝐄𝐂𝐔𝐑𝐈𝐓𝐘 𝐀𝐋𝐋 𝐂𝐎𝐔𝐑𝐒𝐄
⚡️ Reconnaissance and Footprinting
⚡️ Network Scanning
⚡️ Enumeration
⚡️ Firewalls HIDs Honeypot
⚡️ Malware and Threats
⚡️ Mobile Platform
⚡️ Pentesting
⚡️ Sql Injection
⚡️ System Hacking
⚡️ Web Application
⚡️ Wireless Network
⚡️ Cloud Computing
⚡️ Web Server
⚡️ Social Engineering
⚡️ Session Hijacking
⚡️ Sniffing
⚡️ BufferOverflow
⚡️ Cryptography
⚡️ Denial Of Service
All courses (100 rupees)
Contact:- @meterials_available
22 590
🎯Shell is hiring for Interns
2025 batch eligible
Location : Bangalore/Gurgaon
Apply:-
https://jobs.shell.com/job/bengaluru/shell-assessed-internship-programme-2025-india/25244/67560377344
22 590
Repost from allcoding1_official
📌IT learning courses
📌All programing courses
📌Abdul bari courses
📌Ashok IT
📌Linux
📌Networking
📌Design patterns
📌Donet
📌Docker
📌Entity framework
📌Node.js
📌ASP. Net
📌Aps. Net cro
📌java
📌JavaScript
📌full stack developer
Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
🔹Python
🔹Artificial Intelligence
🔹AWS Certified
🔹Cloud
🔹BIG DATA
🔹Data Analytics
🔹BI
🔹Google Cloud Platform
🔹IT Training
🔹MBA
🔹Machine Learning
🔹Deep Learning
🔹Ethical Hacking
🔹SPSS
🔹Statistics
🔹Data Base
🔹Learning language resources English , 🇫🇷
𝐂𝐘𝐁𝐄𝐑 𝐒𝐄𝐂𝐔𝐑𝐈𝐓𝐘 𝐀𝐋𝐋 𝐂𝐎𝐔𝐑𝐒𝐄
⚡️ Reconnaissance and Footprinting
⚡️ Network Scanning
⚡️ Enumeration
⚡️ Firewalls HIDs Honeypot
⚡️ Malware and Threats
⚡️ Mobile Platform
⚡️ Pentesting
⚡️ Sql Injection
⚡️ System Hacking
⚡️ Web Application
⚡️ Wireless Network
⚡️ Cloud Computing
⚡️ Web Server
⚡️ Social Engineering
⚡️ Session Hijacking
⚡️ Sniffing
⚡️ BufferOverflow
⚡️ Cryptography
⚡️ Denial Of Service
All courses @ 50 rupees
Contact:- @meterials_available
22 590
Repost from allcoding1_official
+7
📌IT learning courses
📌All programing courses
📌Abdul bari courses
📌Ashok IT
📌Linux
📌Networking
📌Design patterns
📌Donet
📌Docker
📌Entity framework
📌Node.js
📌ASP. Net
📌Aps. Net cro
📌java
📌JavaScript
📌full stack developer
Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
🔹Python
🔹Artificial Intelligence
🔹AWS Certified
🔹Cloud
🔹BIG DATA
🔹Data Analytics
🔹BI
🔹Google Cloud Platform
🔹IT Training
🔹MBA
🔹Machine Learning
🔹Deep Learning
🔹Ethical Hacking
🔹SPSS
🔹Statistics
🔹Data Base
🔹Learning language resources English , 🇫🇷
𝐂𝐘𝐁𝐄𝐑 𝐒𝐄𝐂𝐔𝐑𝐈𝐓𝐘 𝐀𝐋𝐋 𝐂𝐎𝐔𝐑𝐒𝐄
⚡️ Reconnaissance and Footprinting
⚡️ Network Scanning
⚡️ Enumeration
⚡️ Firewalls HIDs Honeypot
⚡️ Malware and Threats
⚡️ Mobile Platform
⚡️ Pentesting
⚡️ Sql Injection
⚡️ System Hacking
⚡️ Web Application
⚡️ Wireless Network
⚡️ Cloud Computing
⚡️ Web Server
⚡️ Social Engineering
⚡️ Session Hijacking
⚡️ Sniffing
⚡️ BufferOverflow
⚡️ Cryptography
⚡️ Denial Of Service
All courses @ 75rs
Contact:- @meterials_available
22 590
🎯Tech Mahindra link open for 2024 Batch
Immediately apply before it closed
Apply Now:-
https://registration.techmahindra.com/Candidate/Instructions.aspx
22 590
+7
📌IT learning courses
📌All programing courses
📌Abdul bari courses
📌Ashok IT
📌Linux
📌Networking
📌Design patterns
📌Donet
📌Docker
📌Entity framework
📌Node.js
📌ASP. Net
📌Aps. Net cro
📌java
📌JavaScript
📌full stack developer
Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
🔹Python
🔹Artificial Intelligence
🔹AWS Certified
🔹Cloud
🔹BIG DATA
🔹Data Analytics
🔹BI
🔹Google Cloud Platform
🔹IT Training
🔹MBA
🔹Machine Learning
🔹Deep Learning
🔹Ethical Hacking
🔹SPSS
🔹Statistics
🔹Data Base
🔹Learning language resources English , 🇫🇷
𝐂𝐘𝐁𝐄𝐑 𝐒𝐄𝐂𝐔𝐑𝐈𝐓𝐘 𝐀𝐋𝐋 𝐂𝐎𝐔𝐑𝐒𝐄
⚡️ Reconnaissance and Footprinting
⚡️ Network Scanning
⚡️ Enumeration
⚡️ Firewalls HIDs Honeypot
⚡️ Malware and Threats
⚡️ Mobile Platform
⚡️ Pentesting
⚡️ Sql Injection
⚡️ System Hacking
⚡️ Web Application
⚡️ Wireless Network
⚡️ Cloud Computing
⚡️ Web Server
⚡️ Social Engineering
⚡️ Session Hijacking
⚡️ Sniffing
⚡️ BufferOverflow
⚡️ Cryptography
⚡️ Denial Of Service
All courses (100 rupees)
Contact:- @meterials_available
22 590
+7
📌IT learning courses
📌All programing courses
📌Abdul bari courses
📌Ashok IT
📌Linux
📌Networking
📌Design patterns
📌Donet
📌Docker
📌Entity framework
📌Node.js
📌ASP. Net
📌Aps. Net cro
📌java
📌JavaScript
📌full stack developer
Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
🔹Python
🔹Artificial Intelligence
🔹AWS Certified
🔹Cloud
🔹BIG DATA
🔹Data Analytics
🔹BI
🔹Google Cloud Platform
🔹IT Training
🔹MBA
🔹Machine Learning
🔹Deep Learning
🔹Ethical Hacking
🔹SPSS
🔹Statistics
🔹Data Base
🔹Learning language resources English , 🇫🇷
𝐂𝐘𝐁𝐄𝐑 𝐒𝐄𝐂𝐔𝐑𝐈𝐓𝐘 𝐀𝐋𝐋 𝐂𝐎𝐔𝐑𝐒𝐄
⚡️ Reconnaissance and Footprinting
⚡️ Network Scanning
⚡️ Enumeration
⚡️ Firewalls HIDs Honeypot
⚡️ Malware and Threats
⚡️ Mobile Platform
⚡️ Pentesting
⚡️ Sql Injection
⚡️ System Hacking
⚡️ Web Application
⚡️ Wireless Network
⚡️ Cloud Computing
⚡️ Web Server
⚡️ Social Engineering
⚡️ Session Hijacking
⚡️ Sniffing
⚡️ BufferOverflow
⚡️ Cryptography
⚡️ Denial Of Service
All courses (100 rupees)
Contact:- @meterials_available
22 590
GenC PWD Hiring 2023 & 2024 Batch
Apply link 👇
https://app.joinsuperset.com/join/#/signup/student/jobprofiles/07a89094-b25f-4041-b191-5bd8eb09a5aa
22 590
Repost from allcoding1_official
+7
📌IT learning courses
📌All programing courses
📌Abdul bari courses
📌Ashok IT
📌Linux
📌Networking
📌Design patterns
📌Donet
📌Docker
📌Entity framework
📌Node.js
📌ASP. Net
📌Aps. Net cro
📌java
📌JavaScript
📌full stack developer
Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
🔹Python
🔹Artificial Intelligence
🔹AWS Certified
🔹Cloud
🔹BIG DATA
🔹Data Analytics
🔹BI
🔹Google Cloud Platform
🔹IT Training
🔹MBA
🔹Machine Learning
🔹Deep Learning
🔹Ethical Hacking
🔹SPSS
🔹Statistics
🔹Data Base
🔹Learning language resources English , 🇫🇷
𝐂𝐘𝐁𝐄𝐑 𝐒𝐄𝐂𝐔𝐑𝐈𝐓𝐘 𝐀𝐋𝐋 𝐂𝐎𝐔𝐑𝐒𝐄
⚡️ Reconnaissance and Footprinting
⚡️ Network Scanning
⚡️ Enumeration
⚡️ Firewalls HIDs Honeypot
⚡️ Malware and Threats
⚡️ Mobile Platform
⚡️ Pentesting
⚡️ Sql Injection
⚡️ System Hacking
⚡️ Web Application
⚡️ Wireless Network
⚡️ Cloud Computing
⚡️ Web Server
⚡️ Social Engineering
⚡️ Session Hijacking
⚡️ Sniffing
⚡️ BufferOverflow
⚡️ Cryptography
⚡️ Denial Of Service
All courses @
70 rupees
Contact:- @meterials_available
22 590
Ciena is hiring for Software Engineering DevOps New Grad
Expected Salary : 10-20 LPA
Batch : 2024/2023 passouts eligible
Apply here :
https://careers.ciena.com/us/en/job/CIENUSR025123ENUS/Software-Engineering-DevOps-New-Grad
Telegram:- @allcoding1
22 590
Repost from allcoding1
+7
📌IT learning courses
📌All programing courses
📌Abdul bari courses
📌Ashok IT
📌Linux
📌Networking
📌Design patterns
📌Donet
📌Docker
📌Entity framework
📌Node.js
📌ASP. Net
📌Aps. Net cro
📌java
📌JavaScript
📌full stack developer
Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
🔹Python
🔹Artificial Intelligence
🔹AWS Certified
🔹Cloud
🔹BIG DATA
🔹Data Analytics
🔹BI
🔹Google Cloud Platform
🔹IT Training
🔹MBA
🔹Machine Learning
🔹Deep Learning
🔹Ethical Hacking
🔹SPSS
🔹Statistics
🔹Data Base
🔹Learning language resources English , 🇫🇷
𝐂𝐘𝐁𝐄𝐑 𝐒𝐄𝐂𝐔𝐑𝐈𝐓𝐘 𝐀𝐋𝐋 𝐂𝐎𝐔𝐑𝐒𝐄
⚡️ Reconnaissance and Footprinting
⚡️ Network Scanning
⚡️ Enumeration
⚡️ Firewalls HIDs Honeypot
⚡️ Malware and Threats
⚡️ Mobile Platform
⚡️ Pentesting
⚡️ Sql Injection
⚡️ System Hacking
⚡️ Web Application
⚡️ Wireless Network
⚡️ Cloud Computing
⚡️ Web Server
⚡️ Social Engineering
⚡️ Session Hijacking
⚡️ Sniffing
⚡️ BufferOverflow
⚡️ Cryptography
⚡️ Denial Of Service
All courses (100 rupees)
Contact:- @meterials_available
22 590
#include <iostream>
#include <vector>
#include <numeric>
using namespace std;
double solve(const vector<int>& cnts) {
vector<double> den = {0.20, 0.40, 1, 2, 5, 10};
double tot = 0.0;
for (size_t i = 0; i < cnts.size(); ++i) {
tot += cnts[i] * den[i];
}
return tot;
}
int main() {
vector<int> cnts;
int input;
while (cin >> input) {
cnts.push_back(input);
}
cout << solve(cnts) << endl;
return 0;
}
22 590
#include <bits/stdc++.h>
int getMinimumStress(int graph_nodes, int graph_edges, vector<pair<int, int>>& edges, vector<int>& weights, int source, int destination) {
Graph graph(graph_nodes + 1);
for (int i = 0; i < graph_edges; ++i) {
int u = edges[i].first;
int v = edges[i].second;
int w = weights[i];
graph[u].push_back({v, w});
graph[v].push_back({u, w});
}
priority_queue<pii, vector<pii>, greater<pii>> pq;
vector<int> min_stress(graph_nodes + 1, INT_MAX );
pq.push({0, source});
min_stress[source] = 0;
while (!pq.empty()) {
int curr_stress = pq.top().first;
int u = pq.top().second;
pq.pop();
if (u == destination) {
return curr_stress;
}
if (curr_stress > min_stress[u]) {
continue;
}
for (const auto& neighbor : graph[u]) {
int v = neighbor.first;
int weight = neighbor.second;
int next_stress = max(curr_stress, weight);
if (next_stress < min_stress[v]) {
min_stress[v] = next_stress;
pq.push({next_stress, v});
}
}
}
return -1;
}
22 590
#include <iostream>
#include <vector>
#include <cmath>
#include <string>
#include <algorithm>
using namespace std;
int main()
{
vector<string> k = {"1234567890", "qwertyuiop", "asdfghjkl", "zxcvbnm"};
string w;
getline(cin, w);
transform(w.begin(), w.end(), w.begin(), ::tolower);
vector<string> words;
string temp;
for (char c : w)
{
if (c == ' ')
{
if (!temp.empty())
{
words.push_back(temp);
temp.clear();
}
}
else
{
temp += c;
}
}
if (!temp.empty())
{
words.push_back(temp);
}
int t = 0;
for (string v : words)
{
int l = v.length();
vector<int> r(l, -1);
vector<int> p(l, -1);
for (int i = 0; i < l; ++i)
{
bool f = false;
for (int j = 0; j < k.size(); ++j)
{
int c = k[j].find(v[i]);
if (c != string::npos)
{
r[i] = j;
p[i] = c;
f = true;
break;
}
}
if (!f)
{
break;
}
}
int c = 0;
for (int i = 1; i < l; ++i)
{
if (r[i] == r[i - 1] && abs(p[i] - p[i - 1]) <= 1)
{
c += 1;
}
else
{
if (c > 0)
{
if (r[i - 1] == -1)
{
t += 2;
}
else
{
t += 1;
}
c = 0;
}
}
}
if (c > 0)
{
if (r[l - 1] == -1)
{
t += 2;
}
else
{
t += 1;
}
}
}
cout << t << endl;
return 0;
}
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