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allcoding1

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allcoding1 (@allcoding1) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 22 590 obunachidan iborat bo'lib, Taʼlim toifasida 8 822-o'rinni va Hindiston mintaqasida 19 518-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 22 590 obunachiga ega bo‘ldi.

12 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -437 ga, so‘nggi 24 soatda esa -6 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 5.99% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.25% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 1 353 marta ko‘riladi; birinchi sutkada odatda 283 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 2 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, learning kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Kanal uchun tavsif kiritilmagan.

Yuqori yangilanish chastotasi (oxirgi ma’lumot 13 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

22 590
Obunachilar
-624 soatlar
-967 kunlar
-43730 kunlar
Postlar arxiv
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Repost from allcoding1_official
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT 📌Linux 📌Networking 📌Design patterns 📌Donet 📌Docker 📌Entity framework 📌Node.js 📌ASP. Net 📌Aps. Net cro 📌java 📌JavaScript 📌full stack developer Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources  English , 🇫🇷 𝐂𝐘𝐁𝐄𝐑 𝐒𝐄𝐂𝐔𝐑𝐈𝐓𝐘 𝐀𝐋𝐋  𝐂𝐎𝐔𝐑𝐒𝐄 ⚡️ Reconnaissance and Footprinting ⚡️ Network Scanning ⚡️ Enumeration ⚡️ Firewalls HIDs Honeypot ⚡️ Malware and Threats ⚡️ Mobile Platform ⚡️ Pentesting ⚡️ Sql Injection ⚡️ System Hacking ⚡️ Web Application ⚡️ Wireless Network ⚡️ Cloud Computing ⚡️ Web Server ⚡️ Social Engineering ⚡️ Session Hijacking ⚡️ Sniffing ⚡️ BufferOverflow ⚡️ Cryptography ⚡️ Denial Of Service All courses @ 50 rupees Contact:- @meterials_available

Repost from allcoding1_official
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT 📌Linux 📌Networking 📌Design patterns 📌Donet
+7
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT 📌Linux 📌Networking 📌Design patterns 📌Donet 📌Docker 📌Entity framework 📌Node.js 📌ASP. Net 📌Aps. Net cro 📌java 📌JavaScript 📌full stack developer Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources  English , 🇫🇷 𝐂𝐘𝐁𝐄𝐑 𝐒𝐄𝐂𝐔𝐑𝐈𝐓𝐘 𝐀𝐋𝐋  𝐂𝐎𝐔𝐑𝐒𝐄 ⚡️ Reconnaissance and Footprinting ⚡️ Network Scanning ⚡️ Enumeration ⚡️ Firewalls HIDs Honeypot ⚡️ Malware and Threats ⚡️ Mobile Platform ⚡️ Pentesting ⚡️ Sql Injection ⚡️ System Hacking ⚡️ Web Application ⚡️ Wireless Network ⚡️ Cloud Computing ⚡️ Web Server ⚡️ Social Engineering ⚡️ Session Hijacking ⚡️ Sniffing ⚡️ BufferOverflow ⚡️ Cryptography ⚡️ Denial Of Service All courses @ 75rs Contact:- @meterials_available

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📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT 📌Linux 📌Networking 📌Design patterns 📌Donet
+7
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT 📌Linux 📌Networking 📌Design patterns 📌Donet 📌Docker 📌Entity framework 📌Node.js 📌ASP. Net 📌Aps. Net cro 📌java 📌JavaScript 📌full stack developer Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources  English , 🇫🇷 𝐂𝐘𝐁𝐄𝐑 𝐒𝐄𝐂𝐔𝐑𝐈𝐓𝐘 𝐀𝐋𝐋  𝐂𝐎𝐔𝐑𝐒𝐄 ⚡️ Reconnaissance and Footprinting ⚡️ Network Scanning ⚡️ Enumeration ⚡️ Firewalls HIDs Honeypot ⚡️ Malware and Threats ⚡️ Mobile Platform ⚡️ Pentesting ⚡️ Sql Injection ⚡️ System Hacking ⚡️ Web Application ⚡️ Wireless Network ⚡️ Cloud Computing ⚡️ Web Server ⚡️ Social Engineering ⚡️ Session Hijacking ⚡️ Sniffing ⚡️ BufferOverflow ⚡️ Cryptography ⚡️ Denial Of Service All courses (100 rupees) Contact:- @meterials_available

Repost from allcoding1_official
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT 📌Linux 📌Networking 📌Design patterns 📌Donet
+7
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT 📌Linux 📌Networking 📌Design patterns 📌Donet 📌Docker 📌Entity framework 📌Node.js 📌ASP. Net 📌Aps. Net cro 📌java 📌JavaScript 📌full stack developer Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources  English , 🇫🇷 𝐂𝐘𝐁𝐄𝐑 𝐒𝐄𝐂𝐔𝐑𝐈𝐓𝐘 𝐀𝐋𝐋  𝐂𝐎𝐔𝐑𝐒𝐄 ⚡️ Reconnaissance and Footprinting ⚡️ Network Scanning ⚡️ Enumeration ⚡️ Firewalls HIDs Honeypot ⚡️ Malware and Threats ⚡️ Mobile Platform ⚡️ Pentesting ⚡️ Sql Injection ⚡️ System Hacking ⚡️ Web Application ⚡️ Wireless Network ⚡️ Cloud Computing ⚡️ Web Server ⚡️ Social Engineering ⚡️ Session Hijacking ⚡️ Sniffing ⚡️ BufferOverflow ⚡️ Cryptography ⚡️ Denial Of Service All courses @ 70 rupees Contact:- @meterials_available

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Repost from allcoding1
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT 📌Linux 📌Networking 📌Design patterns 📌Donet
+7
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT 📌Linux 📌Networking 📌Design patterns 📌Donet 📌Docker 📌Entity framework 📌Node.js 📌ASP. Net 📌Aps. Net cro 📌java 📌JavaScript 📌full stack developer Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources  English , 🇫🇷 𝐂𝐘𝐁𝐄𝐑 𝐒𝐄𝐂𝐔𝐑𝐈𝐓𝐘 𝐀𝐋𝐋  𝐂𝐎𝐔𝐑𝐒𝐄 ⚡️ Reconnaissance and Footprinting ⚡️ Network Scanning ⚡️ Enumeration ⚡️ Firewalls HIDs Honeypot ⚡️ Malware and Threats ⚡️ Mobile Platform ⚡️ Pentesting ⚡️ Sql Injection ⚡️ System Hacking ⚡️ Web Application ⚡️ Wireless Network ⚡️ Cloud Computing ⚡️ Web Server ⚡️ Social Engineering ⚡️ Session Hijacking ⚡️ Sniffing ⚡️ BufferOverflow ⚡️ Cryptography ⚡️ Denial Of Service All courses (100 rupees) Contact:- @meterials_available

#include #include #include using namespace std; double solve(const vector& cnts) { vector den = {0.20, 0.40, 1, 2, 5, 10}
#include <iostream> #include <vector> #include <numeric> using namespace std; double solve(const vector<int>& cnts) { vector<double> den = {0.20, 0.40, 1, 2, 5, 10}; double tot = 0.0; for (size_t i = 0; i < cnts.size(); ++i) { tot += cnts[i] * den[i]; } return tot; } int main() { vector<int> cnts; int input; while (cin >> input) { cnts.push_back(input); } cout << solve(cnts) << endl; return 0; }

#include <bits/stdc++.h> int getMinimumStress(int graph_nodes, int graph_edges, vector<pair<int, int>>& edges, vector<int>& weights, int source, int destination) { Graph graph(graph_nodes + 1); for (int i = 0; i < graph_edges; ++i) { int u = edges[i].first; int v = edges[i].second; int w = weights[i]; graph[u].push_back({v, w}); graph[v].push_back({u, w}); } priority_queue<pii, vector<pii>, greater<pii>> pq; vector<int> min_stress(graph_nodes + 1, INT_MAX ); pq.push({0, source}); min_stress[source] = 0; while (!pq.empty()) { int curr_stress = pq.top().first; int u = pq.top().second; pq.pop(); if (u == destination) { return curr_stress; } if (curr_stress > min_stress[u]) { continue; } for (const auto& neighbor : graph[u]) { int v = neighbor.first; int weight = neighbor.second; int next_stress = max(curr_stress, weight); if (next_stress < min_stress[v]) { min_stress[v] = next_stress; pq.push({next_stress, v}); } } } return -1; }

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#include <iostream> #include <vector> #include <cmath> #include <string> #include <algorithm> using namespace std; int main() {     vector<string> k = {"1234567890", "qwertyuiop", "asdfghjkl", "zxcvbnm"};     string w;     getline(cin, w);     transform(w.begin(), w.end(), w.begin(), ::tolower);     vector<string> words;     string temp;     for (char c : w)     {         if (c == ' ')         {             if (!temp.empty())             {                 words.push_back(temp);                 temp.clear();             }         }         else         {             temp += c;         }     }     if (!temp.empty())     {         words.push_back(temp);     }     int t = 0;     for (string v : words)     {         int l = v.length();         vector<int> r(l, -1);         vector<int> p(l, -1);         for (int i = 0; i < l; ++i)         {             bool f = false;             for (int j = 0; j < k.size(); ++j)             {                 int c = k[j].find(v[i]);                 if (c != string::npos)                 {                     r[i] = j;                     p[i] = c;                     f = true;                     break;                 }             }             if (!f)             {                 break;             }         }         int c = 0;         for (int i = 1; i < l; ++i)         {             if (r[i] == r[i - 1] && abs(p[i] - p[i - 1]) <= 1)             {                 c += 1;             }             else             {                 if (c > 0)                 {                     if (r[i - 1] == -1)                     {                         t += 2;                     }                     else                     {                         t += 1;                     }                     c = 0;                 }             }         }         if (c > 0)         {             if (r[l - 1] == -1)             {                 t += 2;             }             else             {                 t += 1;             }         }     }     cout << t << endl;     return 0; }

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