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📈 Аналітичний огляд Telegram-каналу allcoding1_official

Канал allcoding1_official (@allcoding1_official) у мовному сегменті Англійська є активним учасником. На даний момент спільнота об'єднує 85 703 підписників, посідаючи 1 509 місце в категорії Технології та додатки та 3 512 місце у регіоні Індія.

📊 Показники аудиторії та динаміка

З моменту свого створення невідомо, проект продемонстрував стрімке зростання, зібравши аудиторію у 85 703 підписників.

За останніми даними від 20 червня, 2026, канал демонструє стабільну активність. Хоча за останні 30 днів спостерігається зміна кількості учасників на -1 460, а за останні 24 години на -39, загальне охоплення залишається високим.

  • Статус верифікації: Не верифікований
  • Рівень залученості (ER): Середній показник залученості аудиторії становить 3.36%. Протягом перших 24 годин після публікації контент зазвичай збирає 0.73% реакцій від загальної кількості підписників.
  • Охоплення публікацій: В середньому кожен допис отримує 2 882 переглядів. Протягом першої доби публікація в середньому набирає 625 переглядів.
  • Реакції та взаємодія: Аудиторія активно підтримує контент: середня кількість реакцій на один пост – 1.
  • Тематичні інтереси: Контент зосереджений навколо ключових тем, таких як dsa, stack, namaste, javascript, dev.

📝 Опис та контентна політика

Опис каналу не надано.

Завдяки високій частоті оновлень (останні дані отримано 21 червня, 2026), канал підтримує актуальність та високий рівень охоплення публікацій. Аналітика показує, що аудиторія активно взаємодіє з контентом, що робить його важливою точкою впливу в категорії Технології та додатки.

85 703
Підписники
-3924 години
-3267 днів
-1 46030 день
Архів дописів
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Palindrome
Palindrome

Good sequence
Good sequence

import java.util.*; public class Maib {     private static int reverseNumber(int num) {         int reversed = 0;         while (num != 0) {             reversed = reversed * 10 + num % 10;             num /= 10;         }         return reversed;     }     private static int largestPossibleNumber(int num) {         char[] digits = String.valueOf(num).toCharArray();         Arrays.sort(digits);         StringBuilder largestNumStr = new StringBuilder(new String(digits)).reverse();         return Integer.parseInt(largestNumStr.toString());     }     private static List<Integer> splitIntoDigits(int num) {         List<Integer> digits = new ArrayList<>();         while (num != 0) {             digits.add(num % 10);             num /= 10;         }         Collections.reverse(digits);         return digits;     }     public static String processAndEncodeArray(int[] arr) {         for (int i = 0; i < arr.length; i++) {             arr[i] = reverseNumber(arr[i]);         }                 for (int i = 0; i < arr.length; i++) {             arr[i] = largestPossibleNumber(arr[i]);         }                 List<Integer> allDigits = new ArrayList<>();         for (int num : arr) {             allDigits.addAll(splitIntoDigits(num));         }                 Set<Integer> uniqueDigits = new LinkedHashSet<>(allDigits);         List<Integer> uniqueDigitList = new ArrayList<>(uniqueDigits);                 // Step 5: Generate the encoded string         StringBuilder encodedString = new StringBuilder();         for (int digit : uniqueDigitList) {             if (digit == 0) {                 encodedString.append('$');             } else if (digit % 2 == 0) {                 encodedString.append('*');             } else {                 encodedString.append('#');             }         }                 return encodedString.toString();     }     public static void main(String[] args) {         Scanner scanner = new Scanner(System.in);         int n = scanner.nextInt();         int[] arr = new int[n];         for (int i = 0; i < n; i++) {             arr[i] = scanner.nextInt();         }        String result = processAndEncodeArray(arr);         System.out.println(result);     } }

photo content
+3

class Result { public static void goodSequence(BufferedReader bufferedReader) throws IOException { StringTokenizer st = new StringTokenizer(bufferedReader.readLine()); int T = Integer.parseInt(st.nextToken()); for (int t = 0; t < T; t++) { st = new StringTokenizer(bufferedReader.readLine(), ","); int N = Integer.parseInt(st.nextToken()); int M = Integer.parseInt(st.nextToken()); st = new StringTokenizer(bufferedReader.readLine(), ","); int[] sequence = new int[N]; for (int i = 0; i < N; i++) { sequence[i] = Integer.parseInt(st.nextToken()); } String result = solveTestCase(N, M, sequence); System.out.println(result); } } private static String solveTestCase(int N, int M, int[] sequence) { int countDivisible = 0; for (int x : sequence) { if (x % M == 0) { countDivisible++; } } if (countDivisible == 0) { return "0/1"; } long totalSubsequences = (1L << N) - 1; long goodSubsequences = (1L << countDivisible) - 1; long P = goodSubsequences; long Q = totalSubsequences; long commonDivisor = gcd(P, Q); P /= commonDivisor; Q /= commonDivisor; return P + "/" + Q; } private static long gcd(long a, long b) { while (b != 0) { long temp = b; b = a % b; a = temp; } return a; } }

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Only today night
Only today night

Only today night
Only today night

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