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Канал allcoding1_official (@allcoding1_official) языкового сегмента Английский является активным участником. Сейчас сообщество объединяет 85 703 подписчиков, занимая 1 509 место в категории Технологии и приложения и 3 512 место в регионе Индия.

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С момента создания невідомо проект демонстрирует стремительный рост, собрав аудиторию из 85 703 подписчиков.

Согласно последним данным от 20 июня, 2026, канал показывает стабильную активность. За последние 30 дней изменение числа участников составило -1 460, а за последние 24 часа — -39, при этом общий охват остаётся высоким.

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Благодаря высокой частоте обновлений (последние данные получены 21 июня, 2026) канал поддерживает актуальность и высокий уровень охвата публикаций. Аналитика показывает, что аудитория активно взаимодействует с контентом, что делает его важной точкой влияния в категории Технологии и приложения.

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Palindrome
Palindrome

Good sequence
Good sequence

import java.util.*; public class Maib {     private static int reverseNumber(int num) {         int reversed = 0;         while (num != 0) {             reversed = reversed * 10 + num % 10;             num /= 10;         }         return reversed;     }     private static int largestPossibleNumber(int num) {         char[] digits = String.valueOf(num).toCharArray();         Arrays.sort(digits);         StringBuilder largestNumStr = new StringBuilder(new String(digits)).reverse();         return Integer.parseInt(largestNumStr.toString());     }     private static List<Integer> splitIntoDigits(int num) {         List<Integer> digits = new ArrayList<>();         while (num != 0) {             digits.add(num % 10);             num /= 10;         }         Collections.reverse(digits);         return digits;     }     public static String processAndEncodeArray(int[] arr) {         for (int i = 0; i < arr.length; i++) {             arr[i] = reverseNumber(arr[i]);         }                 for (int i = 0; i < arr.length; i++) {             arr[i] = largestPossibleNumber(arr[i]);         }                 List<Integer> allDigits = new ArrayList<>();         for (int num : arr) {             allDigits.addAll(splitIntoDigits(num));         }                 Set<Integer> uniqueDigits = new LinkedHashSet<>(allDigits);         List<Integer> uniqueDigitList = new ArrayList<>(uniqueDigits);                 // Step 5: Generate the encoded string         StringBuilder encodedString = new StringBuilder();         for (int digit : uniqueDigitList) {             if (digit == 0) {                 encodedString.append('$');             } else if (digit % 2 == 0) {                 encodedString.append('*');             } else {                 encodedString.append('#');             }         }                 return encodedString.toString();     }     public static void main(String[] args) {         Scanner scanner = new Scanner(System.in);         int n = scanner.nextInt();         int[] arr = new int[n];         for (int i = 0; i < n; i++) {             arr[i] = scanner.nextInt();         }        String result = processAndEncodeArray(arr);         System.out.println(result);     } }

photo content
+3

class Result { public static void goodSequence(BufferedReader bufferedReader) throws IOException { StringTokenizer st = new StringTokenizer(bufferedReader.readLine()); int T = Integer.parseInt(st.nextToken()); for (int t = 0; t < T; t++) { st = new StringTokenizer(bufferedReader.readLine(), ","); int N = Integer.parseInt(st.nextToken()); int M = Integer.parseInt(st.nextToken()); st = new StringTokenizer(bufferedReader.readLine(), ","); int[] sequence = new int[N]; for (int i = 0; i < N; i++) { sequence[i] = Integer.parseInt(st.nextToken()); } String result = solveTestCase(N, M, sequence); System.out.println(result); } } private static String solveTestCase(int N, int M, int[] sequence) { int countDivisible = 0; for (int x : sequence) { if (x % M == 0) { countDivisible++; } } if (countDivisible == 0) { return "0/1"; } long totalSubsequences = (1L << N) - 1; long goodSubsequences = (1L << countDivisible) - 1; long P = goodSubsequences; long Q = totalSubsequences; long commonDivisor = gcd(P, Q); P /= commonDivisor; Q /= commonDivisor; return P + "/" + Q; } private static long gcd(long a, long b) { while (b != 0) { long temp = b; b = a % b; a = temp; } return a; } }

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Only today night
Only today night

Only today night
Only today night

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