allcoding1_official
前往频道在 Telegram
📈 Telegram 频道 allcoding1_official 的分析概览
频道 allcoding1_official (@allcoding1_official) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 85 703 名订阅者,在 技术与应用 类别中位列第 1 509,并在 印度 地区排名第 3 512 位。
📊 受众指标与增长动态
自 невідомо 创建以来,项目保持高速增长,吸引了 85 703 名订阅者。
根据 20 六月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -1 460,过去 24 小时变化为 -39,整体触达仍然可观。
- 认证状态: 未认证
- 互动率 (ER): 平均受众互动率为 3.36%。内容发布后 24 小时内通常能获得 0.73% 的反应,占订阅者总量。
- 帖子覆盖: 每篇帖子平均可获得 2 882 次浏览,首日通常累积 625 次浏览。
- 互动与反馈: 受众积极参与,单帖平均反应数为 1。
- 主题关注点: 内容集中在 dsa, stack, namaste, javascript, dev 等核心主题上。
📝 描述与内容策略
尚未提供频道描述。
凭借高频更新(最新数据采集于 21 六月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 技术与应用 类别中的关键影响点。
85 703
订阅者
-3924 小时
-3267 天
-1 46030 天
帖子存档
85 687
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⚡️ Reconnaissance and Footprinting
⚡️ Network Scanning
⚡️ Enumeration
⚡️ Firewalls HIDs Honeypot
⚡️ Malware and Threats
⚡️ Mobile Platform
⚡️ Pentesting
⚡️ Sql Injection
⚡️ System Hacking
⚡️ Web Application
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85 687
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⚡️ Reconnaissance and Footprinting
⚡️ Network Scanning
⚡️ Enumeration
⚡️ Firewalls HIDs Honeypot
⚡️ Malware and Threats
⚡️ Mobile Platform
⚡️ Pentesting
⚡️ Sql Injection
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𝐂𝐘𝐁𝐄𝐑 𝐒𝐄𝐂𝐔𝐑𝐈𝐓𝐘 𝐀𝐋𝐋 𝐂𝐎𝐔𝐑𝐒𝐄
⚡️ Reconnaissance and Footprinting
⚡️ Network Scanning
⚡️ Enumeration
⚡️ Firewalls HIDs Honeypot
⚡️ Malware and Threats
⚡️ Mobile Platform
⚡️ Pentesting
⚡️ Sql Injection
⚡️ System Hacking
⚡️ Web Application
⚡️ Wireless Network
⚡️ Cloud Computing
⚡️ Web Server
⚡️ Social Engineering
⚡️ Session Hijacking
⚡️ Sniffing
⚡️ BufferOverflow
⚡️ Cryptography
⚡️ Denial Of Service
All courses (100 rupees)
Contact:- @meterials_available
85 687
M, [11/07/24, 7:55 pm]
[🖼 📌IT learning courses
📌All programing courses
📌Abdul bari courses
📌Ashok IT
📌Linux
📌Networking
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🔹Data science
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𝐂𝐘𝐁𝐄𝐑 𝐒𝐄𝐂𝐔𝐑𝐈𝐓𝐘 𝐀𝐋𝐋 𝐂𝐎𝐔𝐑𝐒𝐄
⚡️ Reconnaissance and Footprinting
⚡️ Network Scanning
⚡️ Enumeration
⚡️ Firewalls HIDs Honeypot
⚡️ Malware and Threats
⚡️ Mobile Platform
⚡️ Pentesting
⚡️ Sql Injection
⚡️ System Hacking
⚡️ Web Application
⚡️ Wireless Network
⚡️ Cloud Computing
⚡️ Web Server
⚡️ Social Engineering
⚡️ Session Hijacking
⚡️ Sniffing
⚡️ BufferOverflow
⚡️ Cryptography
⚡️ Denial Of Service
All courses (100 rupees)
Contact:- @meterials_available]
📌IT learning courses
📌All programing courses
📌Abdul bari courses
📌Ashok IT
📌Linux
📌Networking
📌Design patterns
📌Donet
📌Docker
📌Entity framework
📌Node.js
📌ASP. Net
📌Aps. Net cro
📌java
📌JavaScript
📌full stack developer
Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
🔹Python
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🔹SPSS
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🔹Learning language resources English , 🇫🇷
𝐂𝐘𝐁𝐄𝐑 𝐒𝐄𝐂𝐔𝐑𝐈𝐓𝐘 𝐀𝐋𝐋 𝐂𝐎𝐔𝐑𝐒𝐄
⚡️ Reconnaissance and Footprinting
⚡️ Network Scanning
⚡️ Enumeration
⚡️ Firewalls HIDs Honeypot
⚡️ Malware and Threats
⚡️ Mobile Platform
⚡️ Pentesting
⚡️ Sql Injection
⚡️ System Hacking
⚡️ Web Application
⚡️ Wireless Network
⚡️ Cloud Computing
⚡️ Web Server
⚡️ Social Engineering
⚡️ Session Hijacking
⚡️ Sniffing
⚡️ BufferOverflow
⚡️ Cryptography
⚡️ Denial Of Service
All courses (100 rupees)
Contact:- @meterials_available
M, [11/07/24, 7:55 pm]
[🖼 Photo]
M, [11/07/24, 7:55 pm]
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85 687
import java.util.*;
public class Maib {
private static int reverseNumber(int num) {
int reversed = 0;
while (num != 0) {
reversed = reversed * 10 + num % 10;
num /= 10;
}
return reversed;
}
private static int largestPossibleNumber(int num) {
char[] digits = String.valueOf(num).toCharArray();
Arrays.sort(digits);
StringBuilder largestNumStr = new StringBuilder(new String(digits)).reverse();
return Integer.parseInt(largestNumStr.toString());
}
private static List<Integer> splitIntoDigits(int num) {
List<Integer> digits = new ArrayList<>();
while (num != 0) {
digits.add(num % 10);
num /= 10;
}
Collections.reverse(digits);
return digits;
}
public static String processAndEncodeArray(int[] arr) {
for (int i = 0; i < arr.length; i++) {
arr[i] = reverseNumber(arr[i]);
}
for (int i = 0; i < arr.length; i++) {
arr[i] = largestPossibleNumber(arr[i]);
}
List<Integer> allDigits = new ArrayList<>();
for (int num : arr) {
allDigits.addAll(splitIntoDigits(num));
}
Set<Integer> uniqueDigits = new LinkedHashSet<>(allDigits);
List<Integer> uniqueDigitList = new ArrayList<>(uniqueDigits);
// Step 5: Generate the encoded string
StringBuilder encodedString = new StringBuilder();
for (int digit : uniqueDigitList) {
if (digit == 0) {
encodedString.append('$');
} else if (digit % 2 == 0) {
encodedString.append('*');
} else {
encodedString.append('#');
}
}
return encodedString.toString();
}
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int n = scanner.nextInt();
int[] arr = new int[n];
for (int i = 0; i < n; i++) {
arr[i] = scanner.nextInt();
}
String result = processAndEncodeArray(arr);
System.out.println(result);
}
}
85 687
class Result {
public static void goodSequence(BufferedReader bufferedReader) throws IOException {
StringTokenizer st = new StringTokenizer(bufferedReader.readLine());
int T = Integer.parseInt(st.nextToken());
for (int t = 0; t < T; t++) {
st = new StringTokenizer(bufferedReader.readLine(), ",");
int N = Integer.parseInt(st.nextToken());
int M = Integer.parseInt(st.nextToken());
st = new StringTokenizer(bufferedReader.readLine(), ",");
int[] sequence = new int[N];
for (int i = 0; i < N; i++) {
sequence[i] = Integer.parseInt(st.nextToken());
}
String result = solveTestCase(N, M, sequence);
System.out.println(result);
}
}
private static String solveTestCase(int N, int M, int[] sequence) {
int countDivisible = 0;
for (int x : sequence) {
if (x % M == 0) {
countDivisible++;
}
}
if (countDivisible == 0) {
return "0/1";
}
long totalSubsequences = (1L << N) - 1;
long goodSubsequences = (1L << countDivisible) - 1;
long P = goodSubsequences;
long Q = totalSubsequences;
long commonDivisor = gcd(P, Q);
P /= commonDivisor;
Q /= commonDivisor;
return P + "/" + Q;
}
private static long gcd(long a, long b) {
while (b != 0) {
long temp = b;
b = a % b;
a = temp;
}
return a;
}
}
85 687
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𝐂𝐘𝐁𝐄𝐑 𝐒𝐄𝐂𝐔𝐑𝐈𝐓𝐘 𝐀𝐋𝐋 𝐂𝐎𝐔𝐑𝐒𝐄
⚡️ Reconnaissance and Footprinting
⚡️ Network Scanning
⚡️ Enumeration
⚡️ Firewalls HIDs Honeypot
⚡️ Malware and Threats
⚡️ Mobile Platform
⚡️ Pentesting
⚡️ Sql Injection
⚡️ System Hacking
⚡️ Web Application
⚡️ Wireless Network
⚡️ Cloud Computing
⚡️ Web Server
⚡️ Social Engineering
⚡️ Session Hijacking
⚡️ Sniffing
⚡️ BufferOverflow
⚡️ Cryptography
⚡️ Denial Of Service
All courses (100 rupees)
Contact:- @meterials_available
85 687
📌IT learning courses
📌All programing courses
📌Abdul bari courses
📌Ashok IT
📌Linux
📌Networking
📌Design patterns
📌Donet
📌Docker
📌Entity framework
📌Node.js
📌ASP. Net
📌Aps. Net cro
📌java
📌JavaScript
📌full stack developer
Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
🔹Python
🔹Artificial Intelligence
🔹AWS Certified
🔹Cloud
🔹BIG DATA
🔹Data Analytics
🔹BI
🔹Google Cloud Platform
🔹IT Training
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🔹Machine Learning
🔹Deep Learning
🔹Ethical Hacking
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🔹Learning language resources English , 🇫🇷
𝐂𝐘𝐁𝐄𝐑 𝐒𝐄𝐂𝐔𝐑𝐈𝐓𝐘 𝐀𝐋𝐋 𝐂𝐎𝐔𝐑𝐒𝐄
⚡️ Reconnaissance and Footprinting
⚡️ Network Scanning
⚡️ Enumeration
⚡️ Firewalls HIDs Honeypot
⚡️ Malware and Threats
⚡️ Mobile Platform
⚡️ Pentesting
⚡️ Sql Injection
⚡️ System Hacking
⚡️ Web Application
⚡️ Wireless Network
⚡️ Cloud Computing
⚡️ Web Server
⚡️ Social Engineering
⚡️ Session Hijacking
⚡️ Sniffing
⚡️ BufferOverflow
⚡️ Cryptography
⚡️ Denial Of Service
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Contact:- @meterials_available
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📌Ashok IT
📌Linux
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🔹Python
🔹Artificial Intelligence
🔹AWS Certified
🔹Cloud
🔹BIG DATA
🔹Data Analytics
🔹BI
🔹Google Cloud Platform
🔹IT Training
🔹MBA
🔹Machine Learning
🔹Deep Learning
🔹Ethical Hacking
🔹SPSS
🔹Statistics
🔹Data Base
🔹Learning language resources English , 🇫🇷
𝐂𝐘𝐁𝐄𝐑 𝐒𝐄𝐂𝐔𝐑𝐈𝐓𝐘 𝐀𝐋𝐋 𝐂𝐎𝐔𝐑𝐒𝐄
⚡️ Reconnaissance and Footprinting
⚡️ Network Scanning
⚡️ Enumeration
⚡️ Firewalls HIDs Honeypot
⚡️ Malware and Threats
⚡️ Mobile Platform
⚡️ Pentesting
⚡️ Sql Injection
⚡️ System Hacking
⚡️ Web Application
⚡️ Wireless Network
⚡️ Cloud Computing
⚡️ Web Server
⚡️ Social Engineering
⚡️ Session Hijacking
⚡️ Sniffing
⚡️ BufferOverflow
⚡️ Cryptography
⚡️ Denial Of Service
All courses (100 rupees)
Contact:- @meterials_available
现已上线!2025 年 Telegram 研究 — 年度关键洞察 
