Physics Spmnetic!™ 🔭

Hye hye quiz time🔥

🚨 Quick update for everyone! We honestly didn't expect THIS many of you to show up on day one — and we're so grateful 🙏 Right now our system is limited to 100 users, and we're already hitting that cap. We're working on fixing this RIGHT NOW so everyone can get in. Hang tight — we'll update you as soon as it's resolved! 💪 — Ken, KenTeach

Any errors please message @tehtzeken or @TCKblbl [Please be as specific as possible] and we will try to solve it

Eh korang 👋 Real talk. I built something and I need you guys to try it. I'm Ken, 17 years old from Penang. While studying for SPM Physics I got so frustrated with boring notes and random YouTube videos that I just... built my own app. 😅 It's called KenTeach — think Duolingo but for SPM Physics. Here's what's inside (100% free, no cap): ⚡️ Past year papers from all 13 states 🎮 XP, streaks & leaderboard (yes, your username is a Malaysian food) 🧮 Built-in Casio fx-570SPM calculator emulator 📊 Weak Topics Tracker so you know exactly what to fix ⏱️ Full exam simulation mode — feels like the real thing No tuition fees. No RM10/month. Free. I built this myself in my bedroom. It's not perfect but it works — and I genuinely think it'll help you score better in Physics. Takes 2 minutes to try. If you hate it, at least you tried lah 😂 CTA: 👉 Sign up free → https://kenteach.com Drop a 🙋 in the comments if you sign up — I read every single one.

MOTIVATION keep this as your phone wallpaper...

MOTIVATION keep this as you phone wallpaper...

I am sorry for teaching wrongly, the correct answer to this question is , you cannot determine if the object is accelerating or decelerating , because the initial velocity of object is not given, if lets say the initial velocity was -3ms-1, or in words 3 meters per second to the left(assuming right as positive and left as negative) then it would be deceleration because acceleration works like a push force. lets say u are moving to the right with speed of 2ms-1 and if your acceleration is 2 ms-2, then its acceleration because the push direction and the direction of your initial motion is same, but if lets say the u are moving left with the speed of 2ms-1 and if your acceleration is 2 ms-2, then its deceleration because the push direction and the direction of your initial motion is not same, so to determine if an object is accelerating or decelerating, we have a formula av>0 means acceleration or av<0 means deceleration, where a is acceleration and v is velocity. Saya minta maaf kerana sebelum ini tersilap mengajar. Jawapan yang betul untuk soalan ini ialah: kita tidak boleh tentukan sama ada objek itu sedang memecut atau mengalami nyahpecutan kerana halaju awal objek tidak diberikan. Sebabnya, pecutan bertindak seperti daya tolakan (push force). Katakanlah halaju awal ialah -3 ms-1 (iaitu bergerak 3 meter sesaat ke kiri, jika kita anggap kanan sebagai positif dan kiri sebagai negatif): Jika kita bergerak ke kanan dengan halaju 2 ms-1 dan pecutan kita juga 2 ms-2 (ke kanan sebab anggap kanan sebagai positif dan kiri sebagai negatifi), maka itu adalah Pecutan. Ini kerana arah tolakan dan arah gerakan asal adalah sama. Jika kita bergerak ke kiri dengan halaju 2 ms-1 tetapi pecutan kita adalah 2 ms-2 (ke kanan), maka itu adalah Nyahpecutan. Ini kerana arah tolakan bertentangan dengan arah gerakan asal, menyebabkan objek menjadi perlahan. Jadi, untuk menentukan sama ada sesuatu objek itu memecut atau mengalami nyahpecutan, kita gunakan formula ini: av > 0 bermaksud Pecutan (Laju bertambah). av < 0 bermaksud Nyahpecutan (Laju berkurang). Di mana a ialah pecutan dan v ialah halaju.

this question

I am sorry for teaching wrongly, the correct answer to this question is , you cannot determine if the object is accelerating or decelerating , because the initial velocity of object is not given, if lets say the initial velocity was -3ms-1, or in words 3 meters per second to the left(assuming right as positive and left as negative) then it would be deceleration because acceleration works like a push force. lets say u are moving to the right with speed of 2ms-2 and if your acceleration is 2 ms-2, then its acceleration because the push direction and the direction of your initial motion is same, but if lets say the u are moving left with the speed of 2ms-1 and if your acceleration is 2 ms-2, then its deceleration because the push direction and the direction of your initial motion is not same, so to determine if an object is accelerating or decelerating, we have a formula av>0 means acceleration or av<0 means deceleration, where a is acceleration and v is velocity. Saya minta maaf kerana sebelum ini tersilap mengajar. Jawapan yang betul untuk soalan ini ialah: kita tidak boleh tentukan sama ada objek itu sedang memecut atau mengalami nyahpecutan kerana halaju awal objek tidak diberikan. Sebabnya, pecutan bertindak seperti daya tolakan (push force). Katakanlah halaju awal ialah -3 ms-1 (iaitu bergerak 3 meter sesaat ke kiri, jika kita anggap kanan sebagai positif dan kiri sebagai negatif): Jika kita bergerak ke kanan dengan halaju 2 ms-1 dan pecutan kita juga 2 ms-2 (ke kanan sebab anggap kanan sebagai positif dan kiri sebagai negatifi), maka itu adalah Pecutan. Ini kerana arah tolakan dan arah gerakan asal adalah sama. Jika kita bergerak ke kiri dengan halaju 2 ms-1 tetapi pecutan kita adalah 2 ms-2 (ke kanan), maka itu adalah Nyahpecutan. Ini kerana arah tolakan bertentangan dengan arah gerakan asal, menyebabkan objek menjadi perlahan. Jadi, untuk menentukan sama ada sesuatu objek itu memecut atau mengalami nyahpecutan, kita gunakan formula ini: av > 0 bermaksud Pecutan (Laju bertambah). av < 0 bermaksud Nyahpecutan (Laju berkurang). Di mana a ialah pecutan dan v ialah halaju.

Trial mrsm 2022 done ✅ congratulations 🎉

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