OSSSC / OSSC MATH AND REASONING

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𝐀𝐧𝐲 PROMOTION RELATED CONTACT OWNER @BUNNYTAPAS Join our YouTube Channel: https://shorturl.at/Ulwjw 🔴 𝐂𝐮𝐫𝐫𝐞𝐧𝐭 𝐚𝐟𝐟𝐚𝐢𝐫𝐬 @CURRENT_AFFAIRS_REGULARLY 🔴𝐄𝐧𝐠𝐥𝐢𝐬𝐡- @BLACKBOOK_ENGLISH

Network:ଓଡ଼ିଆ ବ୍ୟାକରଣ India33 457 Education17 102...

📈 Analytical overview of Telegram channel OSSSC / OSSC MATH AND REASONING

Channel OSSSC / OSSC MATH AND REASONING (@pinnacle_math_reasoning) in the English language segment is an active participant. Currently, the community unites 11 535 subscribers, ranking 17 102 in the Education category and 33 457 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 11 535 subscribers.

According to the latest data from 02 October, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by 147 over the last 30 days and by 0 over the last 24 hours, overall reach remains high.

Verification status: Not verified
Engagement rate (ER): The average audience engagement rate is 20.61%. Within the first 24 hours after publication, content typically collects 4.23% reactions from the total number of subscribers.
Post reach: On average, each post receives 2 377 views. Within the first day, a publication typically gains 488 views.
Reactions and interaction: The audience actively supports content: the average number of reactions per post is 4.
Thematic interests: Content is focused on key topics such as ʜᴇʀᴇ, cgle, cgl, mcqs, mcq.

📝 Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
“𝐀𝐧𝐲 PROMOTION RELATED CONTACT OWNER @BUNNYTAPAS Join our YouTube Channel: https://shorturl.at/Ulwjw 🔴 𝐂𝐮𝐫𝐫𝐞𝐧𝐭 𝐚𝐟𝐟𝐚𝐢𝐫𝐬 @CURRENT_AFFAIRS_REGULARLY 🔴𝐄𝐧𝐠𝐥𝐢𝐬𝐡- @BLACKBOOK_ENGLISH”

Thanks to the high frequency of updates (latest data received on 03 October, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

11 535

Subscribers

No data24 hours

+227 days

+14730 days

2 377

Post views

~ 48824 hours

~ 70648 hours

20.61%

Engagement rate

~ 1

Posts per day

Ads index

beta

Posts Archive

11 535

𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘 The average of n numbers is 42. If 75% of the numbers are increased by 4 each and the remaining numbers are decreased by 8 each, then what is the average of the numbers, so obtained?

Anonymous voting

11 535

𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘 The average of 18 numbers is 37.5. If six numbers of average x are added to them, then the average of all the numbers increases by one. The value of x is :

Anonymous voting

11 535

𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘 The average of 13 numbers is 42. If a 14th number is included, then the average becomes 44. What is the 14th number?

Anonymous voting

11 535

16th number = Sum of 24 numbers – [ Sum of first 15 numbers + Sum of last 8 numbers] = 24 × 26 – (15×23+8×33) = 624 – (345+264) = 624 – 609 ∴ 16th number · 15 ✅

11 535

𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘 The average of 24 numbers is 26. The average of the first 15 numbers is 23 and that of the last 8 numbers is 33. Find the 16th number.

Anonymous voting

11 535

𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘 The average weight of P, Q and R is 62 kg. The weight of R is 12 kg more than P and 9 kg more than Q. What is the average weight of P, Q, R and S if weight of S is 15 kg less than R ?

Anonymous voting

11 535

𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘 The average age of 24 students is 15.5 years. The age of the teacher is 24 years more than the average age of all the students and teacher. What is the age (in years) of the teacher?

Anonymous voting

11 535

Anonymous voting

11 535

𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘 The average of 33 numbers is 74.The average of the first17 numbers is 72.8 and that of the last 17 numbers is 77.2.If the 17th number is excluded,then what will be the average of the remaining numbers ?

Anonymous voting

11 535

Sum = Average × No. of total terms. 18 × 37.5 + 6x = 24 × 38.5 112.5 + x = 154 x = 154–112.5 = 41.5 ✅

11 535

Anonymous voting

11 535

𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘 The average marks of 40 students was found to be 68. If the marks of two students were incorrectly entered as 48 and 64 instead of 84 and 46 respectively, then what is the correct average?

Anonymous voting

11 535

𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘 The average marks of 50 students in an examination was 65. It was later found that the marks of one student had been wrongly entered as 83 instead of 38. The correct average is?

Anonymous voting

11 535

Since the average of 39 number is zero. So maximum 38 number can be greater than zero where as 39th number should be such that the sum is zero i-e negative.