OSSSC / OSSC MATH AND REASONING

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𝐀𝐧𝐲 PROMOTION RELATED CONTACT OWNER @BUNNYTAPAS Join our YouTube Channel: https://shorturl.at/Ulwjw 🔴 𝐂𝐮𝐫𝐫𝐞𝐧𝐭 𝐚𝐟𝐟𝐚𝐢𝐫𝐬 @CURRENT_AFFAIRS_REGULARLY 🔴𝐄𝐧𝐠𝐥𝐢𝐬𝐡- @BLACKBOOK_ENGLISH

Network:ଓଡ଼ିଆ ବ୍ୟାକରଣ India33 457 Education17 102...

📈 Analytical overview of Telegram channel OSSSC / OSSC MATH AND REASONING

Channel OSSSC / OSSC MATH AND REASONING (@pinnacle_math_reasoning) in the English language segment is an active participant. Currently, the community unites 11 535 subscribers, ranking 17 102 in the Education category and 33 457 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 11 535 subscribers.

According to the latest data from 02 October, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by 147 over the last 30 days and by 0 over the last 24 hours, overall reach remains high.

Verification status: Not verified
Engagement rate (ER): The average audience engagement rate is 20.61%. Within the first 24 hours after publication, content typically collects 4.23% reactions from the total number of subscribers.
Post reach: On average, each post receives 2 377 views. Within the first day, a publication typically gains 488 views.
Reactions and interaction: The audience actively supports content: the average number of reactions per post is 4.
Thematic interests: Content is focused on key topics such as ʜᴇʀᴇ, cgle, cgl, mcqs, mcq.

📝 Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
“𝐀𝐧𝐲 PROMOTION RELATED CONTACT OWNER @BUNNYTAPAS Join our YouTube Channel: https://shorturl.at/Ulwjw 🔴 𝐂𝐮𝐫𝐫𝐞𝐧𝐭 𝐚𝐟𝐟𝐚𝐢𝐫𝐬 @CURRENT_AFFAIRS_REGULARLY 🔴𝐄𝐧𝐠𝐥𝐢𝐬𝐡- @BLACKBOOK_ENGLISH”

Thanks to the high frequency of updates (latest data received on 03 October, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

11 535

Subscribers

No data24 hours

+227 days

+14730 days

2 377

Post views

~ 48824 hours

~ 70648 hours

20.61%

Engagement rate

~ 1

Posts per day

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beta

Posts Archive

11 535

𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘 The average of 39 numbers is zero. How many of those numbers can be greater than zero?

Anonymous voting

11 535

𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘 The average of nine 2 digit numbers is decreased by 6 when the digits of one of the 2 digit numbers is interchanged. Find the difference between the digits of that number.

Anonymous voting

11 535

𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘 The average of five numbers, given in a particular order, is 32. The average of the first three numbers is 28, while that of the last three numbers is 34. what is the average of the first two numbers?

Anonymous voting

11 535

𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘 What is the least number of square tiles required to pave the floor of a room 15m 17cm long and 9m 43cm broad?

Anonymous voting

11 535

a) : 1149 – 827 = 322 1310 – 1149 = 161 1310 – 827 = 483 Largest desired number = H.C.F of 322, 161 and 483 = 161 ✅

11 535

𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘 Which is the largest number that divides 827, 1149 and 1310 to leave the same remainder in each case?

Anonymous voting

11 535

On taking L.C.M of 12, 18, 24 and 28 LCM = 2×2×2×3×3×7 LCM = 8×9×7 = 72×7 = 504 ∴ The required number = 504 + 5 = 509 ✅

11 535

𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘 What is the least number which when divided by 12, 18, 24 and 28 we obtain 5 as the remainder in each case?

Anonymous voting

11 535

Ans. (d) : The H.C.F of both the numbers is 23 So, both the numbers will be divisible by 23. The greatest 3-digits number which is divisible by 23 = 989 The smallest 4-digits number which is divisible by 23 = 1012 Sum of both numbers = 989 + 1012 = 2001 ✅✅

11 535

𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘 What is the sum of the greatest three digit number and the smallest four digit number such that their HCF is 23?

Anonymous voting

11 535

Ans. (a) : Let the numbers be 15x and 15y. According to the question, 15x + 15y = 240 =>x + y = 16 Hence, the possible pairs of both the numbers = (1, 15), (3, 13), (5, 11), (7, 9) ∴ Possible number of pairs = 4 ✅

11 535

𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘 The sum of two positive number is 240 and their HCF is 15. Find the number of pairs of numbers satisfying the given condition.

Anonymous voting

11 535

𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘 Let x be the number divisible by 16,24,30,36 and 45, and x is also a perfect square. What is the remainder when x is divided by 123?

Anonymous voting

11 535

Ans. (a) : Product of two numbers = LCM × HCF ∴ LCM × HCF = 120 × 6 = 720 ∴ 720 = Product of two numbers From option (a) 24 × 30 = 720 Hence, option (a) is correct. ✅

11 535

𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘 If the HCF of two numbers is 6 and their LCM is 120, one such pair of numbers is:

Anonymous voting

11 535

Ans. (c): LCM of two number = 60 HCF of two numbers = 3 Difference of both numbers =3 Let the numbers be 3x and 3x + 3. 3x (3x+3) = 60×3 => x = 4 Sum of the numbers = 3x+3x+3 = 6x+3 = 24 +3 = 27 ✅