OSSSC / OSSC MATH AND REASONING
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网络:📈 Telegram 频道 OSSSC / OSSC MATH AND REASONING 的分析概览
频道 OSSSC / OSSC MATH AND REASONING (@pinnacle_math_reasoning) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 11 535 名订阅者，在 教育 类别中位列第 17 102，并在 印度 地区排名第 33 457 位。
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自 невідомо 创建以来，项目保持高速增长，吸引了 11 535 名订阅者。
根据 02 十月, 2026 的最新数据，频道保持稳定运转。过去 30 天订阅人数变化为 147，过去 24 小时变化为 0，整体触达仍然可观。
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Join our YouTube Channel: https://shorturl.at/Ulwjw
🔴 𝐂𝐮𝐫𝐫𝐞𝐧𝐭 𝐚𝐟𝐟𝐚𝐢𝐫𝐬 @CURRENT_AFFAIRS_REGULARLY
🔴𝐄𝐧𝐠𝐥𝐢𝐬𝐡- @BLACKBOOK_ENGLISH”
凭借高频更新（最新数据采集于 03 十月, 2026），频道始终保持新鲜度与高覆盖。分析显示受众积极互动，使其成为 教育 类别中的关键影响点。
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𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘
The average of 39 numbers is zero. How many of those numbers can be greater than zero?
𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘
The average of nine 2 digit numbers is decreased by 6 when the digits of one of the 2 digit numbers is interchanged. Find the difference between the digits of that number.
𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘
The average of five numbers, given in a particular order, is 32. The average of the first three numbers is 28, while that of the last three numbers is 34. what is the average of the first two numbers?
𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘
What is the least number of square tiles required to pave the floor of a room 15m 17cm long and 9m 43cm broad?
a) : 1149 – 827 = 322
1310 – 1149 = 161
1310 – 827 = 483
Largest desired number
= H.C.F of 322, 161 and 483
= 161 ✅
𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘
Which is the largest number that divides 827, 1149 and 1310 to leave the same remainder in each case?
On taking L.C.M of 12, 18, 24 and 28
LCM = 2×2×2×3×3×7
LCM = 8×9×7 = 72×7 = 504
∴ The required number
= 504 + 5 = 509 ✅
𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘
What is the least number which when divided by 12, 18, 24 and 28 we obtain 5 as the remainder in each case?
Ans. (d) :
The H.C.F of both the numbers is 23 So, both the numbers will be divisible by 23.
The greatest 3-digits number which is divisible by 23 = 989
The smallest 4-digits number which is divisible by 23 = 1012
Sum of both numbers = 989 + 1012 = 2001 ✅✅
𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘
What is the sum of the greatest three digit number and the smallest four digit number such that their HCF is 23?
Ans. (a) :
Let the numbers be 15x and 15y.
According to the question,
15x + 15y = 240
=>x + y = 16
Hence, the possible pairs of both the numbers = (1, 15), (3, 13), (5, 11), (7, 9)
∴ Possible number of pairs = 4 ✅
𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘
The sum of two positive number is 240 and their HCF is 15. Find the number of pairs of numbers satisfying the given condition.
𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘
Let x be the number divisible by 16,24,30,36 and 45, and x is also a perfect square. What is the remainder when x is divided by 123?
Ans. (a) :
Product of two numbers = LCM × HCF
∴ LCM × HCF = 120 × 6 = 720
∴ 720 = Product of two numbers
From option (a) 24 × 30 = 720
Hence, option (a) is correct. ✅
𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘
If the HCF of two numbers is 6 and their LCM is 120, one such pair of numbers is:
Ans. (c):
LCM of two number = 60 HCF of two numbers = 3
Difference of both numbers =3
Let the numbers be 3x and 3x + 3.
3x (3x+3) = 60×3
=> x = 4
Sum of the numbers
= 3x+3x+3
= 6x+3
= 24 +3 = 27 ✅
