C Programming Codes

Open in Telegram

C Programming Codes || Quizzes || DSA Learn along with the community Any queries admin - @Pradeep_saii

India32 040 Technologies & Applications9 552...

📈 Analytical overview of Telegram channel C Programming Codes

Channel C Programming Codes (@c_programming_codes) in the English language segment is an active participant. Currently, the community unites 13 412 subscribers, ranking 9 552 in the Technologies & Applications category and 32 040 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 13 412 subscribers.

According to the latest data from 13 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -228 over the last 30 days and by -2 over the last 24 hours, overall reach remains high.

Verification status: Not verified
Engagement rate (ER): The average audience engagement rate is 9.78%. Within the first 24 hours after publication, content typically collects N/A% reactions from the total number of subscribers.
Post reach: On average, each post receives 0 views. Within the first day, a publication typically gains 0 views.
Reactions and interaction: The audience actively supports content: the average number of reactions per post is 0.
Thematic interests: Content is focused on key topics such as input, string, scanf("%d, array, element.

📝 Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
“C Programming Codes || Quizzes || DSA Learn along with the community Any queries admin - @Pradeep_saii”

Thanks to the high frequency of updates (latest data received on 14 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.

13 412

Subscribers

-224 hours

-497 days

-22830 days

1 313

Post views

No data24 hours

No data48 hours

9.78%

Engagement rate

No data

Posts per day

Ads index

beta

Posts Archive

13 412

#CProgramming #NeonNumber #Algorithm

13 412

Check Neon Number

#include <stdio.h>

int main() {
  int n, square, sum = 0, temp;

  scanf("%d", &n);

  square = n * n;
  temp = square;

  while (temp > 0) {
    sum += temp % 10;
    temp /= 10;
  }

  if (sum == n) {
    printf("Neon");
  } else {
    printf("Not Neon");
  }

  return 0;
}

13 412

#CProgramming #AutomorphicNumber #InterviewQuestion

13 412

Check Automorphic Number

#include <stdio.h>
#include <stdbool.h>

int main() {
 int num, sq;
 printf("Enter a number: ");
 scanf("%d", &num);
 sq = num * num;
 int temp = num;
 int digits = 0;
 while (temp > 0) {
 digits++;
 temp /= 10;
 }
 int lastDigits = sq % (int)pow(10, digits);
 if (lastDigits == num) {
 printf("%d is an Automorphic number.\n", num);
 } else {
 printf("%d is not an Automorphic number.\n", num);
 }
 return 0;
}

13 412

#CProgramming #Divisors #Algorithms

13 412

Print All Divisors of a Number

#include <stdio.h>

void printDivisors(int n) {
  for (int i = 1; i <= n; i++) {
    if (n % i == 0) {
      printf("%d ", i);
    }
  }
  printf("\n");
}

int main() {
  int num;
  scanf("%d", &num);
  printDivisors(num);
  return 0;
}

13 412

#CProgramming #Factorial #BigNumbers

13 412

Find Factorial (Big Numbers using Arrays)

#include <stdio.h>

int multiply(int x, int res[], int res_size) {
    int carry = 0;
    for (int i = 0; i < res_size; i++) {
        int prod = res[i] * x + carry;
        res[i] = prod % 10;
        carry = prod / 10;
    }
    while (carry) {
        res[res_size] = carry % 10;
        carry = carry / 10;
        res_size++;
    }
    return res_size;
}

void factorial(int n) {
    int res[500];
    res[0] = 1;
    int res_size = 1;

    for (int x = 2; x <= n; x++)
        res_size = multiply(x, res, res_size);

    for (int i = res_size - 1; i >= 0; i--)
        printf("%d", res[i]);
    printf("\n");
}

int main() {
    int n = 100;
    factorial(n);
    return 0;
}

13 412

#CProgramming #HarshadNumber #InterviewCode

13 412

Check Harshad (Niven) Number

#include <stdio.h>
#include <stdbool.h>

bool isHarshad(int n) {
    int sum = 0;
    int temp = n;
    while (temp > 0) {
        sum += temp % 10;
        temp /= 10;
    }
    return (n % sum == 0 && sum != 0);
}

int main() {
    int num;
    scanf("%d", &num);
    if (isHarshad(num)) {
        printf("Harshad\n");
    } else {
        printf("Not Harshad\n");
    }
    return 0;
}

13 412

#CProgramming #Summation #InterviewPrep

13 412

Sum of First N Natural Numbers

#include <stdio.h>

int sum_n(int n) {
  if (n <= 0) {
    return 0;
  }
  return n * (n + 1) / 2;
}

int main() {
  int num = 10;
  int sum = sum_n(num);
  printf("Sum of first %d natural numbers: %d\n", num, sum);
  return 0;
}

13 412

#CProgramming #Algorithm #DigitalRoot

13 412

Digital Root of a Number

#include <stdio.h>

int digitalRoot(int n) {
 while (n >= 10) {
 int sum = 0;
 while (n > 0) {
 sum += n % 10;
 n /= 10;
 }
 n = sum;
 }
 return n;
}

int main() {
 int num = 12345;
 printf("Digital root of %d is %d\n", num, digitalRoot(num));
 return 0;
}

13 412

#CProgramming #Recursion #Iteration

13 412

Sum of Digits (Recursive and Iterative)

#include <stdio.h>

int sumDigitsIterative(int n) {
    int sum = 0;
    while (n > 0) {
        sum += n % 10;
        n /= 10;
    }
    return sum;
}

int sumDigitsRecursive(int n) {
    if (n == 0) {
        return 0;
    }
    return (n % 10) + sumDigitsRecursive(n / 10);
}

int main() {
    int num = 12345;
    printf("Iterative Sum of Digits: %d\n", sumDigitsIterative(num));
    printf("Recursive Sum of Digits: %d\n", sumDigitsRecursive(num));
    return 0;
}

13 412

#Cprogramming #Palindrome #InterviewQuestion

13 412

Check Palindrome Number

#include <stdio.h>
#include <stdbool.h>

bool isPalindrome(int num) {
    int reversedNum = 0, originalNum = num, remainder;

    while (num != 0) {
        remainder = num % 10;
        reversedNum = reversedNum * 10 + remainder;
        num /= 10;
    }

    return originalNum == reversedNum;
}

int main() {
    int number;
    scanf("%d", &number);
    if (isPalindrome(number)) {
        printf("Palindrome");
    } else {
        printf("Not Palindrome");
    }
    return 0;
}

13 412

#CProgramming #BitwiseOperators #PowerOfTwo

13 412

Check Power of 2 (Iterative and Bitwise)

#include <stdbool.h>

bool isPowerOfTwoIterative(unsigned int n) {
 if (n == 0) return false;
 while (n % 2 == 0) {
 n /= 2;
 }
 return (n == 1);
}

bool isPowerOfTwoBitwise(unsigned int n) {
 return (n != 0) && ((n & (n - 1)) == 0);
}