C Programming Codes
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显示更多📈 Telegram 频道 C Programming Codes 的分析概览
频道 C Programming Codes (@c_programming_codes) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 13 412 名订阅者,在 技术与应用 类别中位列第 9 552,并在 印度 地区排名第 32 040 位。
📊 受众指标与增长动态
自 невідомо 创建以来,项目保持高速增长,吸引了 13 412 名订阅者。
根据 13 六月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -228,过去 24 小时变化为 -2,整体触达仍然可观。
- 认证状态: 未认证
- 互动率 (ER): 平均受众互动率为 9.78%。内容发布后 24 小时内通常能获得 N/A% 的反应,占订阅者总量。
- 帖子覆盖: 每篇帖子平均可获得 0 次浏览,首日通常累积 0 次浏览。
- 互动与反馈: 受众积极参与,单帖平均反应数为 0。
- 主题关注点: 内容集中在 input, string, scanf("%d, array, element 等核心主题上。
📝 描述与内容策略
作者将该频道定位为表达主观观点的平台:
“C Programming Codes || Quizzes || DSA
Learn along with the community
Any queries
admin - @Pradeep_saii”
凭借高频更新(最新数据采集于 14 六月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 技术与应用 类别中的关键影响点。
13 412
订阅者
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-22830 天
帖子存档
13 412
Check Neon Number
#include <stdio.h>
int main() {
int n, square, sum = 0, temp;
scanf("%d", &n);
square = n * n;
temp = square;
while (temp > 0) {
sum += temp % 10;
temp /= 10;
}
if (sum == n) {
printf("Neon");
} else {
printf("Not Neon");
}
return 0;
}13 412
Check Automorphic Number
#include <stdio.h>
#include <stdbool.h>
int main() {
int num, sq;
printf("Enter a number: ");
scanf("%d", &num);
sq = num * num;
int temp = num;
int digits = 0;
while (temp > 0) {
digits++;
temp /= 10;
}
int lastDigits = sq % (int)pow(10, digits);
if (lastDigits == num) {
printf("%d is an Automorphic number.\n", num);
} else {
printf("%d is not an Automorphic number.\n", num);
}
return 0;
}13 412
Print All Divisors of a Number
#include <stdio.h>
void printDivisors(int n) {
for (int i = 1; i <= n; i++) {
if (n % i == 0) {
printf("%d ", i);
}
}
printf("\n");
}
int main() {
int num;
scanf("%d", &num);
printDivisors(num);
return 0;
}13 412
Find Factorial (Big Numbers using Arrays)
#include <stdio.h>
int multiply(int x, int res[], int res_size) {
int carry = 0;
for (int i = 0; i < res_size; i++) {
int prod = res[i] * x + carry;
res[i] = prod % 10;
carry = prod / 10;
}
while (carry) {
res[res_size] = carry % 10;
carry = carry / 10;
res_size++;
}
return res_size;
}
void factorial(int n) {
int res[500];
res[0] = 1;
int res_size = 1;
for (int x = 2; x <= n; x++)
res_size = multiply(x, res, res_size);
for (int i = res_size - 1; i >= 0; i--)
printf("%d", res[i]);
printf("\n");
}
int main() {
int n = 100;
factorial(n);
return 0;
}13 412
Check Harshad (Niven) Number
#include <stdio.h>
#include <stdbool.h>
bool isHarshad(int n) {
int sum = 0;
int temp = n;
while (temp > 0) {
sum += temp % 10;
temp /= 10;
}
return (n % sum == 0 && sum != 0);
}
int main() {
int num;
scanf("%d", &num);
if (isHarshad(num)) {
printf("Harshad\n");
} else {
printf("Not Harshad\n");
}
return 0;
}13 412
Sum of First N Natural Numbers
#include <stdio.h>
int sum_n(int n) {
if (n <= 0) {
return 0;
}
return n * (n + 1) / 2;
}
int main() {
int num = 10;
int sum = sum_n(num);
printf("Sum of first %d natural numbers: %d\n", num, sum);
return 0;
}13 412
Digital Root of a Number
#include <stdio.h>
int digitalRoot(int n) {
while (n >= 10) {
int sum = 0;
while (n > 0) {
sum += n % 10;
n /= 10;
}
n = sum;
}
return n;
}
int main() {
int num = 12345;
printf("Digital root of %d is %d\n", num, digitalRoot(num));
return 0;
}13 412
Sum of Digits (Recursive and Iterative)
#include <stdio.h>
int sumDigitsIterative(int n) {
int sum = 0;
while (n > 0) {
sum += n % 10;
n /= 10;
}
return sum;
}
int sumDigitsRecursive(int n) {
if (n == 0) {
return 0;
}
return (n % 10) + sumDigitsRecursive(n / 10);
}
int main() {
int num = 12345;
printf("Iterative Sum of Digits: %d\n", sumDigitsIterative(num));
printf("Recursive Sum of Digits: %d\n", sumDigitsRecursive(num));
return 0;
}13 412
Check Palindrome Number
#include <stdio.h>
#include <stdbool.h>
bool isPalindrome(int num) {
int reversedNum = 0, originalNum = num, remainder;
while (num != 0) {
remainder = num % 10;
reversedNum = reversedNum * 10 + remainder;
num /= 10;
}
return originalNum == reversedNum;
}
int main() {
int number;
scanf("%d", &number);
if (isPalindrome(number)) {
printf("Palindrome");
} else {
printf("Not Palindrome");
}
return 0;
}13 412
Check Power of 2 (Iterative and Bitwise)
#include <stdbool.h>
bool isPowerOfTwoIterative(unsigned int n) {
if (n == 0) return false;
while (n % 2 == 0) {
n /= 2;
}
return (n == 1);
}
bool isPowerOfTwoBitwise(unsigned int n) {
return (n != 0) && ((n & (n - 1)) == 0);
}
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