C Programming Language || Hands On Coding
Hands-on C programming language challenges for beginners. Learn building logic by solving programs. Owner: @Pradeep_saii
Show more📈 Analytical overview of Telegram channel C Programming Language || Hands On Coding
Channel C Programming Language || Hands On Coding (@c_programming_language_coding) in the English language segment is an active participant. Currently, the community unites 12 809 subscribers, ranking 9 558 in the Technologies & Applications category and 30 933 in the India region.
📊 Audience metrics and dynamics
Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 12 809 subscribers.
According to the latest data from 29 August, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -215 over the last 30 days and by -7 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 7.22%. Within the first 24 hours after publication, content typically collects 2.42% reactions from the total number of subscribers.
- Post reach: On average, each post receives 925 views. Within the first day, a publication typically gains 310 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
- Thematic interests: Content is focused on key topics such as input, string, scanf("%d, array, element.
📝 Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
“Hands-on C programming language challenges for beginners. Learn building logic by solving programs.
Owner: @Pradeep_saii”
Thanks to the high frequency of updates (latest data received on 30 August, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.
#include <stdio.h>
void swap(int *x, int *y) {
*x = *x ^ *y;
*y = *x ^ *y;
*x = *x ^ *y;
}
int main() {
int a = 10, b = 5;
swap(&a, &b);
printf("a = %d, b = %d\n", a, b);
return 0;
}#include <stdio.h>
long long factorial(int n) {
if (n == 0)
return 1;
else
return n * factorial(n - 1);
}
long long nCr(int n, int r) {
if (r < 0 || r > n)
return 0;
if (r == 0 || r == n)
return 1;
if (r > n / 2)
r = n - r;
return factorial(n) / (factorial(r) * factorial(n - r));
}
int main() {
int n, r;
printf("Enter n and r: ");
scanf("%d %d", &n, &r);
printf("nCr = %lld\n", nCr(n, r));
return 0;
}#include <stdio.h>
int main() {
int rows, coef = 1, space, i, j;
scanf("%d", &rows);
for (i = 0; i < rows; i++) {
for (space = 1; space <= rows - i; space++)
printf(" ");
for (j = 0; j <= i; j++) {
if (j == 0 || i == 0)
coef = 1;
else
coef = coef * (i - j + 1) / j;
printf("%4d", coef);
}
printf("\n");
}
return 0;
}#include <stdio.h>
int sumOfFirstNEven(int n) {
return n * (n + 1);
}
int sumOfFirstNOdd(int n) {
return n * n;
}
int main() {
int n;
printf("Enter a number: ");
scanf("%d", &n);
printf("Sum of first %d even numbers: %d\n", n, sumOfFirstNEven(n));
printf("Sum of first %d odd numbers: %d\n", n, sumOfFirstNOdd(n));
return 0;
}#include <stdio.h>
#include <stdbool.h>
#include <math.h>
bool isPalindrome(int n) {
int reversed = 0, original = n, remainder;
while (n != 0) {
remainder = n % 10;
reversed = reversed * 10 + remainder;
n /= 10;
}
return original == reversed;
}
bool isPrime(int n) {
if (n <= 1) return false;
for (int i = 2; i <= sqrt(n); i++) {
if (n % i == 0) return false;
}
return true;
}
bool isPalindromicPrime(int n) {
return isPalindrome(n) && isPrime(n);
}
int main() {
int num;
scanf("%d", &num);
if (isPalindromicPrime(num)) {
printf("True\n");
} else {
printf("False\n");
}
return 0;
}#include <stdio.h>
int countTrailingZeroes(int n) {
int count = 0;
for (int i = 5; n / i >= 1; i *= 5) {
count += n / i;
}
return count;
}
int main() {
int num = 25;
printf("Trailing zeroes in %d! = %d\n", num, countTrailingZeroes(num));
return 0;
}#include <stdio.h>
#include <math.h>
int binaryToDecimal(long long n) {
int decimalNumber = 0, i = 0, remainder;
while (n!=0) {
remainder = n%10;
n /= 10;
decimalNumber += remainder*pow(2,i);
++i;
}
return decimalNumber;
}
int main() {
long long n;
printf("Enter a binary number: ");
scanf("%lld", &n);
printf("Decimal equivalent: %d", binaryToDecimal(n));
return 0;
}#include <stdio.h>
void decimalToBinary(int n) {
int binary[32];
int i = 0;
while (n > 0) {
binary[i] = n % 2;
n = n / 2;
i++;
}
for (int j = i - 1; j >= 0; j--)
printf("%d", binary[j]);
printf("\n");
}
void decimalToOctal(int n) {
int octal[32];
int i = 0;
while (n > 0) {
octal[i] = n % 8;
n = n / 8;
i++;
}
for (int j = i - 1; j >= 0; j--)
printf("%d", octal[j]);
printf("\n");
}
void decimalToHexadecimal(int n) {
char hex[32];
int i = 0;
while (n != 0) {
int temp = 0;
temp = n % 16;
if (temp < 10) {
hex[i] = temp + 48;
} else {
hex[i] = temp + 87;
}
n = n / 16;
i++;
}
for (int j = i - 1; j >= 0; j--)
printf("%c", hex[j]);
printf("\n");
}
int main() {
int decimal;
printf("Enter a decimal number: ");
scanf("%d", &decimal);
printf("Binary: ");
decimalToBinary(decimal);
printf("Octal: ");
decimalToOctal(decimal);
printf("Hexadecimal: ");
decimalToHexadecimal(decimal);
return 0;
}