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C Programming Language || Hands On Coding

C Programming Language || Hands On Coding

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Hands-on C programming language challenges for beginners. Learn building logic by solving programs. Owner: @Pradeep_saii

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📈 Telegram 频道 C Programming Language || Hands On Coding 的分析概览

频道 C Programming Language || Hands On Coding (@c_programming_language_coding) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 12 809 名订阅者,在 技术与应用 类别中位列第 9 558,并在 印度 地区排名第 30 933

📊 受众指标与增长动态

невідомо 创建以来,项目保持高速增长,吸引了 12 809 名订阅者。

根据 29 八月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -215,过去 24 小时变化为 -7,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 7.22%。内容发布后 24 小时内通常能获得 2.42% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 925 次浏览,首日通常累积 310 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 2
  • 主题关注点: 内容集中在 input, string, scanf("%d, array, element 等核心主题上。

📝 描述与内容策略

作者将该频道定位为表达主观观点的平台:
Hands-on C programming language challenges for beginners. Learn building logic by solving programs. Owner: @Pradeep_saii

凭借高频更新(最新数据采集于 30 八月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 技术与应用 类别中的关键影响点。

12 809
订阅者
-724 小时
-317
-21530
帖子存档
#CProgramming #BitwiseOperators #SwapTechnique

Swap Two Numbers using XOR
#include <stdio.h>

void swap(int *x, int *y) {
    *x = *x ^ *y;
    *y = *x ^ *y;
    *x = *x ^ *y;
}

int main() {
    int a = 10, b = 5;
    swap(&a, &b);
    printf("a = %d, b = %d\n", a, b);
    return 0;
}

#CProgramming #Combinations #nCr

Find nCr (Combinations)
#include <stdio.h>

long long factorial(int n) {
    if (n == 0)
        return 1;
    else
        return n * factorial(n - 1);
}

long long nCr(int n, int r) {
    if (r < 0 || r > n)
        return 0;
    if (r == 0 || r == n)
        return 1;
    if (r > n / 2)
        r = n - r;
    return factorial(n) / (factorial(r) * factorial(n - r));
}

int main() {
    int n, r;
    printf("Enter n and r: ");
    scanf("%d %d", &n, &r);
    printf("nCr = %lld\n", nCr(n, r));
    return 0;
}

#CProgramming #PascalTriangle #InterviewPrep

Print Pascal's Triangle
#include <stdio.h>

int main() {
  int rows, coef = 1, space, i, j;

  scanf("%d", &rows);

  for (i = 0; i < rows; i++) {
    for (space = 1; space <= rows - i; space++)
      printf("  ");

    for (j = 0; j <= i; j++) {
      if (j == 0 || i == 0)
        coef = 1;
      else
        coef = coef * (i - j + 1) / j;

      printf("%4d", coef);
    }
    printf("\n");
  }

  return 0;
}

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#Cprogramming #InterviewPrep #SumOfNumbers

Sum of First N Even/Odd Numbers
#include <stdio.h>

int sumOfFirstNEven(int n) {
    return n * (n + 1);
}

int sumOfFirstNOdd(int n) {
    return n * n;
}

int main() {
    int n;
    printf("Enter a number: ");
    scanf("%d", &n);
    printf("Sum of first %d even numbers: %d\n", n, sumOfFirstNEven(n));
    printf("Sum of first %d odd numbers: %d\n", n, sumOfFirstNOdd(n));
    return 0;
}

#CProgramming #Palindrome #PrimeNumbers

Check if Number is Palindromic Prime
#include <stdio.h>
#include <stdbool.h>
#include <math.h>

bool isPalindrome(int n) {
    int reversed = 0, original = n, remainder;
    while (n != 0) {
        remainder = n % 10;
        reversed = reversed * 10 + remainder;
        n /= 10;
    }
    return original == reversed;
}

bool isPrime(int n) {
    if (n <= 1) return false;
    for (int i = 2; i <= sqrt(n); i++) {
        if (n % i == 0) return false;
    }
    return true;
}

bool isPalindromicPrime(int n) {
    return isPalindrome(n) && isPrime(n);
}

int main() {
    int num;
    scanf("%d", &num);
    if (isPalindromicPrime(num)) {
        printf("True\n");
    } else {
        printf("False\n");
    }
    return 0;
}

#CProgramming #Factorial #TrailingZeroes

Count Trailing Zeroes in Factorial
#include <stdio.h>

int countTrailingZeroes(int n) {
  int count = 0;
  for (int i = 5; n / i >= 1; i *= 5) {
    count += n / i;
  }
  return count;
}

int main() {
  int num = 25;
  printf("Trailing zeroes in %d! = %d\n", num, countTrailingZeroes(num));
  return 0;
}

#CProgramming #BinaryToDecimal #InterviewPrep

Convert Binary to Decimal
#include <stdio.h>
#include <math.h>

int binaryToDecimal(long long n) {
    int decimalNumber = 0, i = 0, remainder;
    while (n!=0) {
        remainder = n%10;
        n /= 10;
        decimalNumber += remainder*pow(2,i);
        ++i;
    }
    return decimalNumber;
}

int main() {
    long long n;
    printf("Enter a binary number: ");
    scanf("%lld", &n);
    printf("Decimal equivalent: %d", binaryToDecimal(n));
    return 0;
}

#CProgramming #DecimalConversion #BinaryOctalHex

Convert Decimal to Binary, Octal, Hex
#include <stdio.h>

void decimalToBinary(int n) {
    int binary[32];
    int i = 0;
    while (n > 0) {
        binary[i] = n % 2;
        n = n / 2;
        i++;
    }
    for (int j = i - 1; j >= 0; j--)
        printf("%d", binary[j]);
    printf("\n");
}

void decimalToOctal(int n) {
    int octal[32];
    int i = 0;
    while (n > 0) {
        octal[i] = n % 8;
        n = n / 8;
        i++;
    }
    for (int j = i - 1; j >= 0; j--)
        printf("%d", octal[j]);
    printf("\n");
}

void decimalToHexadecimal(int n) {
    char hex[32];
    int i = 0;
    while (n != 0) {
        int temp = 0;
        temp = n % 16;
        if (temp < 10) {
            hex[i] = temp + 48;
        } else {
            hex[i] = temp + 87;
        }
        n = n / 16;
        i++;
    }
    for (int j = i - 1; j >= 0; j--)
        printf("%c", hex[j]);
    printf("\n");
}

int main() {
    int decimal;
    printf("Enter a decimal number: ");
    scanf("%d", &decimal);

    printf("Binary: ");
    decimalToBinary(decimal);

    printf("Octal: ");
    decimalToOctal(decimal);

    printf("Hexadecimal: ");
    decimalToHexadecimal(decimal);

    return 0;
}