不要被骗子欺骗！Telemetrio 会找到并标记这些频道 👉 如果想查看标记，请订阅

AI Coding & CSE Fundamentals

前往频道在 Telegram

🚀 Explore AI, Coding & Computer Science Fundamentals. 💻 Programming • DSA • DBMS • OS • Networks 🤖 AI & Emerging Technologies 🛠️ Projects • Tutorials • Learning Resources 📚 Your freedom to gain knowledge for free.

显示更多

印度31 257技术与应用10 235...

📈 Telegram 频道 AI Coding & CSE Fundamentals 的分析概览

频道 AI Coding & CSE Fundamentals (@aicoding_csefundamentals) 英语语言赛道中的是活跃参与者。目前社区聚集了 12 318 名订阅者，在 技术与应用 类别中位列第 10 235，并在印度地区排名第 31 257 位。

📊 受众指标与增长动态

自 невідомо 创建以来，项目保持高速增长，吸引了 12 318 名订阅者。

根据 13 十一月, 2026 的最新数据，频道保持稳定运转。过去 30 天订阅人数变化为 -236，过去 24 小时变化为 -9，整体触达仍然可观。

认证状态： 未认证
互动率 (ER)： 平均受众互动率为 10.85%。内容发布后 24 小时内通常能获得 N/A% 的反应，占订阅者总量。
帖子覆盖： 每篇帖子平均可获得 1 337 次浏览，首日通常累积 0 次浏览。
互动与反馈： 受众积极参与，单帖平均反应数为 11。
主题关注点： 内容集中在 input, string, scanf("%d, array, element 等核心主题上。

📝 描述与内容策略

作者将该频道定位为表达主观观点的平台：
“🚀 Explore AI, Coding & Computer Science Fundamentals. 💻 Programming • DSA • DBMS • OS • Networks 🤖 AI & Emerging Technologies 🛠️ Projects • Tutorials • Learning Resources 📚 Your freedom to gain knowledge for free.”

凭借高频更新（最新数据采集于 14 十一月, 2026），频道始终保持新鲜度与高覆盖。分析显示受众积极互动，使其成为 技术与应用 类别中的关键影响点。

12 318

订阅者

-924 小时

-837 天

-23630 天

1 337

帖子浏览量

无数据24 小时

无数据48 小时

10.85%

参与率

无数据

每日帖子数

Ads index

帖子存档

12 318

#CPP #BitManipulation #BrianKernighan

12 318

Count Set Bits (Brian Kernighan's Algorithm)

#include <iostream>

using namespace std;

int countSetBits(int n) {
    int count = 0;
    while (n) {
        n &= (n - 1);
        count++;
    }
    return count;
}

int main() {
    int num = 7; 
    cout << "Number of set bits in " << num << " is " << countSetBits(num) << endl;
    return 0;
}

12 318

#CProgramming #BitwiseOperators #SwapTechnique

12 318

Swap Two Numbers using XOR

#include <stdio.h>

void swap(int *x, int *y) {
    *x = *x ^ *y;
    *y = *x ^ *y;
    *x = *x ^ *y;
}

int main() {
    int a = 10, b = 5;
    swap(&a, &b);
    printf("a = %d, b = %d\n", a, b);
    return 0;
}

12 318

#CProgramming #Combinations #nCr

12 318

Find nCr (Combinations)

#include <stdio.h>

long long factorial(int n) {
    if (n == 0)
        return 1;
    else
        return n * factorial(n - 1);
}

long long nCr(int n, int r) {
    if (r < 0 || r > n)
        return 0;
    if (r == 0 || r == n)
        return 1;
    if (r > n / 2)
        r = n - r;
    return factorial(n) / (factorial(r) * factorial(n - r));
}

int main() {
    int n, r;
    printf("Enter n and r: ");
    scanf("%d %d", &n, &r);
    printf("nCr = %lld\n", nCr(n, r));
    return 0;
}

12 318

#CProgramming #PascalTriangle #InterviewPrep

12 318

Print Pascal's Triangle

#include <stdio.h>

int main() {
  int rows, coef = 1, space, i, j;

  scanf("%d", &rows);

  for (i = 0; i < rows; i++) {
    for (space = 1; space <= rows - i; space++)
      printf("  ");

    for (j = 0; j <= i; j++) {
      if (j == 0 || i == 0)
        coef = 1;
      else
        coef = coef * (i - j + 1) / j;

      printf("%4d", coef);
    }
    printf("\n");
  }

  return 0;
}

12 318

Is bot integration for explainations helping you?

Anonymous voting

12 318

Are bot integration for explainations helping you?

Anonymous voting

12 318

What do you feel about bot integration for explainations ?

Anonymous voting

12 318

https://t.me/cpp_code_snippets

12 318

#Cprogramming #InterviewPrep #SumOfNumbers

12 318

Sum of First N Even/Odd Numbers

#include <stdio.h>

int sumOfFirstNEven(int n) {
    return n * (n + 1);
}

int sumOfFirstNOdd(int n) {
    return n * n;
}

int main() {
    int n;
    printf("Enter a number: ");
    scanf("%d", &n);
    printf("Sum of first %d even numbers: %d\n", n, sumOfFirstNEven(n));
    printf("Sum of first %d odd numbers: %d\n", n, sumOfFirstNOdd(n));
    return 0;
}

12 318

#CProgramming #Palindrome #PrimeNumbers

12 318

Check if Number is Palindromic Prime

#include <stdio.h>
#include <stdbool.h>
#include <math.h>

bool isPalindrome(int n) {
    int reversed = 0, original = n, remainder;
    while (n != 0) {
        remainder = n % 10;
        reversed = reversed * 10 + remainder;
        n /= 10;
    }
    return original == reversed;
}

bool isPrime(int n) {
    if (n <= 1) return false;
    for (int i = 2; i <= sqrt(n); i++) {
        if (n % i == 0) return false;
    }
    return true;
}

bool isPalindromicPrime(int n) {
    return isPalindrome(n) && isPrime(n);
}

int main() {
    int num;
    scanf("%d", &num);
    if (isPalindromicPrime(num)) {
        printf("True\n");
    } else {
        printf("False\n");
    }
    return 0;
}

12 318

#CProgramming #Factorial #TrailingZeroes

12 318

Count Trailing Zeroes in Factorial

#include <stdio.h>

int countTrailingZeroes(int n) {
  int count = 0;
  for (int i = 5; n / i >= 1; i *= 5) {
    count += n / i;
  }
  return count;
}

int main() {
  int num = 25;
  printf("Trailing zeroes in %d! = %d\n", num, countTrailingZeroes(num));
  return 0;
}

12 318

#CProgramming #BinaryToDecimal #InterviewPrep

12 318

Convert Binary to Decimal

#include <stdio.h>
#include <math.h>

int binaryToDecimal(long long n) {
    int decimalNumber = 0, i = 0, remainder;
    while (n!=0) {
        remainder = n%10;
        n /= 10;
        decimalNumber += remainder*pow(2,i);
        ++i;
    }
    return decimalNumber;
}

int main() {
    long long n;
    printf("Enter a binary number: ");
    scanf("%lld", &n);
    printf("Decimal equivalent: %d", binaryToDecimal(n));
    return 0;
}