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C Programming Codes
C Programming Codes || Quizzes || DSA Learn along with the community Any queries admin - @Pradeep_saii
Show moreπ Analytical overview of Telegram channel C Programming Codes
Channel C Programming Codes (@c_programming_codes) in the English language segment is an active participant. Currently, the community unites 13 412 subscribers, ranking 9 552 in the Technologies & Applications category and 32 040 in the India region.
π Audience metrics and dynamics
Since its creation on Π½Π΅Π²ΡΠ΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 13 412 subscribers.
According to the latest data from 13 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -228 over the last 30 days and by -2 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 9.78%. Within the first 24 hours after publication, content typically collects N/A% reactions from the total number of subscribers.
- Post reach: On average, each post receives 0 views. Within the first day, a publication typically gains 0 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 0.
- Thematic interests: Content is focused on key topics such as input, string, scanf("%d, array, element.
π Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
βC Programming Codes || Quizzes || DSA
Learn along with the community
Any queries
admin - @Pradeep_saiiβ
Thanks to the high frequency of updates (latest data received on 14 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.
#include <stdio.h>
int main() {
unsigned int num = 10; // Example number
int bit_position = 1; // Example bit position (0-indexed)
// Set bit
unsigned int set_mask = 1 << bit_position;
unsigned int set_result = num | set_mask;
printf("Number after setting bit %d: %u\n", bit_position, set_result);
// Clear bit
unsigned int clear_mask = ~(1 << bit_position);
unsigned int clear_result = num & clear_mask;
printf("Number after clearing bit %d: %u\n", bit_position, clear_result);
// Toggle bit
unsigned int toggle_mask = 1 << bit_position;
unsigned int toggle_result = num ^ toggle_mask;
printf("Number after toggling bit %d: %u\n", bit_position, toggle_result);
return 0;
}#include <stdio.h>
#include <stdint.h>
int isNthBitSet(uint32_t num, int n) {
if (n < 0 || n >= 32) {
return -1;
}
return (num & (1UL << n)) != 0;
}
int main() {
uint32_t number = 10;
int n = 1;
int result = isNthBitSet(number, n);
if (result == -1) {
printf("Invalid bit position\n");
} else if (result) {
printf("Bit %d is set in %u\n", n, number);
} else {
printf("Bit %d is not set in %u\n", n, number);
}
return 0;
}#include <stdio.h>
int countSetBits(int n) {
int count = 0;
while (n) {
n &= (n - 1);
count++;
}
return count;
}
int main() {
int num = 9;
printf("Number of set bits in %d is %d\n", num, countSetBits(num));
return 0;
}#include <stdio.h>
int countSetBits(int n) {
int count = 0;
while (n) {
n &= (n - 1);
count++;
}
return count;
}
int main() {
int num = 9;
printf("Number of set bits in %d is %d\n", num, countSetBits(num));
return 0;
}#include <stdio.h>
int main() {
int a = 5;
int b = 10;
a = a + b;
b = a - b;
a = a - b;
printf("a = %d, b = %d\n", a, b);
return 0;
}#include <stdio.h>
int main() {
int a = 5;
int b = 10;
a = a + b;
b = a - b;
a = a - b;
printf("a = %d, b = %d\n", a, b);
return 0;
}#include <stdio.h>
int main() {
int a = 5;
int b = 10;
a = a + b;
b = a - b;
a = a - b;
printf("a = %d, b = %d\n", a, b);
return 0;
}#include <iostream>
using namespace std;
int countSetBits(int n) {
int count = 0;
while (n) {
n &= (n - 1);
count++;
}
return count;
}
int main() {
int num = 7;
cout << "Number of set bits in " << num << " is " << countSetBits(num) << endl;
return 0;
}#include <stdio.h>
void swap(int *x, int *y) {
*x = *x ^ *y;
*y = *x ^ *y;
*x = *x ^ *y;
}
int main() {
int a = 10, b = 5;
swap(&a, &b);
printf("a = %d, b = %d\n", a, b);
return 0;
}#include <stdio.h>
long long factorial(int n) {
if (n == 0)
return 1;
else
return n * factorial(n - 1);
}
long long nCr(int n, int r) {
if (r < 0 || r > n)
return 0;
if (r == 0 || r == n)
return 1;
if (r > n / 2)
r = n - r;
return factorial(n) / (factorial(r) * factorial(n - r));
}
int main() {
int n, r;
printf("Enter n and r: ");
scanf("%d %d", &n, &r);
printf("nCr = %lld\n", nCr(n, r));
return 0;
}