AI Coding & CSE Fundamentals
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🚀 Explore AI, Coding & Computer Science Fundamentals. 💻 Programming • DSA • DBMS • OS • Networks 🤖 AI & Emerging Technologies 🛠️ Projects • Tutorials • Learning Resources 📚 Your freedom to gain knowledge for free.
显示更多📈 Telegram 频道 AI Coding & CSE Fundamentals 的分析概览
频道 AI Coding & CSE Fundamentals (@aicoding_csefundamentals) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 12 318 名订阅者，在 技术与应用 类别中位列第 10 235，并在 印度 地区排名第 31 257 位。
📊 受众指标与增长动态
自 невідомо 创建以来，项目保持高速增长，吸引了 12 318 名订阅者。
根据 13 十一月, 2026 的最新数据，频道保持稳定运转。过去 30 天订阅人数变化为 -236，过去 24 小时变化为 -9，整体触达仍然可观。
- 认证状态： 未认证
- 互动率 (ER)： 平均受众互动率为 10.85%。内容发布后 24 小时内通常能获得 N/A% 的反应，占订阅者总量。
- 帖子覆盖： 每篇帖子平均可获得 1 337 次浏览，首日通常累积 0 次浏览。
- 互动与反馈： 受众积极参与，单帖平均反应数为 11。
- 主题关注点： 内容集中在 input, string, scanf("%d, array, element 等核心主题上。
📝 描述与内容策略
作者将该频道定位为表达主观观点的平台：
“🚀 Explore AI, Coding & Computer Science Fundamentals.
💻 Programming • DSA • DBMS • OS • Networks
🤖 AI & Emerging Technologies
🛠️ Projects • Tutorials • Learning Resources
📚 Your freedom to gain knowledge for free.”
凭借高频更新（最新数据采集于 14 十一月, 2026），频道始终保持新鲜度与高覆盖。分析显示受众积极互动，使其成为 技术与应用 类别中的关键影响点。
12 318
订阅者
-924 小时
-837 天
-23630 天
帖子存档
Divide/Multiply by 2 using Bit Shift
#include <stdio.h>
int main() {
int num = 16;
int multiplyBy2 = num << 1;
int divideBy2 = num >> 1;
printf("Original number: %d\n", num);
printf("Multiplied by 2: %d\n", multiplyBy2);
printf("Divided by 2: %d\n", divideBy2);
return 0;
}Check if a Number is Power of 2
#include <stdio.h>
#include <stdbool.h>
bool isPowerOfTwo(int n) {
if (n <= 0) {
return false;
}
return (n & (n - 1)) == 0;
}
int main() {
int num = 16;
if (isPowerOfTwo(num)) {
printf("%d is a power of 2\n", num);
} else {
printf("%d is not a power of 2\n", num);
}
return 0;
}Check if a Number is Power of 2
#include <stdio.h>#include <stdbool.h>bool isPowerOfTwo(int n) { if (n <= 0) { return false; } return (n & (n - 1)) == 0;}int main() { int num = 16; if (isPowerOfTwo(num)) { printf("%d is a power of 2\n", num); } else { printf("%d is not a power of 2\n", num); } return 0;}Set/Clear/Toggle Bits
#include <stdio.h>
int main() {
unsigned int num = 10; // Example number
int bit_position = 1; // Example bit position (0-indexed)
// Set bit
unsigned int set_mask = 1 << bit_position;
unsigned int set_result = num | set_mask;
printf("Number after setting bit %d: %u\n", bit_position, set_result);
// Clear bit
unsigned int clear_mask = ~(1 << bit_position);
unsigned int clear_result = num & clear_mask;
printf("Number after clearing bit %d: %u\n", bit_position, clear_result);
// Toggle bit
unsigned int toggle_mask = 1 << bit_position;
unsigned int toggle_result = num ^ toggle_mask;
printf("Number after toggling bit %d: %u\n", bit_position, toggle_result);
return 0;
}Check if Nth Bit is Set
#include <stdio.h>
#include <stdint.h>
int isNthBitSet(uint32_t num, int n) {
if (n < 0 || n >= 32) {
return -1;
}
return (num & (1UL << n)) != 0;
}
int main() {
uint32_t number = 10;
int n = 1;
int result = isNthBitSet(number, n);
if (result == -1) {
printf("Invalid bit position\n");
} else if (result) {
printf("Bit %d is set in %u\n", n, number);
} else {
printf("Bit %d is not set in %u\n", n, number);
}
return 0;
}Count Set Bits (Brian Kernighan's Algorithm)
#include <stdio.h>
int countSetBits(int n) {
int count = 0;
while (n) {
n &= (n - 1);
count++;
}
return count;
}
int main() {
int num = 9;
printf("Number of set bits in %d is %d\n", num, countSetBits(num));
return 0;
}#CProgramming #BitManipulation #Algorithm #InterviewQuestion #Kernighan
Count Set Bits (Brian Kernighan's Algorithm)
#include <stdio.h>
int countSetBits(int n) {
int count = 0;
while (n) {
n &= (n - 1);
count++;
}
return count;
}
int main() {
int num = 9;
printf("Number of set bits in %d is %d\n", num, countSetBits(num));
return 0;
}#CProgramming #SwapNumbers #WithoutTemp #InterviewQuestion #ArithmeticSwap
Swap Two Numbers Without Temp
#include <stdio.h>
int main() {
int a = 5;
int b = 10;
a = a + b;
b = a - b;
a = a - b;
printf("a = %d, b = %d\n", a, b);
return 0;
}Swap Two Numbers Without Temp
#include <stdio.h>
int main() {
int a = 5;
int b = 10;
a = a + b;
b = a - b;
a = a - b;
printf("a = %d, b = %d\n", a, b);
return 0;
}Swap Two Numbers Without Temp
#include <stdio.h>
int main() {
int a = 5;
int b = 10;
a = a + b;
b = a - b;
a = a - b;
printf("a = %d, b = %d\n", a, b);
return 0;
}