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C Programming Language || Hands On Coding

C Programming Language || Hands On Coding

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Hands-on C programming language challenges for beginners. Learn building logic by solving programs. Owner: @Pradeep_saii

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πŸ“ˆ Analytical overview of Telegram channel C Programming Language || Hands On Coding

Channel C Programming Language || Hands On Coding (@c_programming_language_coding) in the English language segment is an active participant. Currently, the community unites 12 822 subscribers, ranking 9 562 in the Technologies & Applications category and 31 207 in the India region.

πŸ“Š Audience metrics and dynamics

Since its creation on Π½Π΅Π²Ρ–Π΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 12 822 subscribers.

According to the latest data from 26 August, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -210 over the last 30 days and by -2 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 12.56%. Within the first 24 hours after publication, content typically collects 2.42% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 1 612 views. Within the first day, a publication typically gains 310 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 4.
  • Thematic interests: Content is focused on key topics such as input, string, scanf("%d, array, element.

πŸ“ Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
β€œHands-on C programming language challenges for beginners. Learn building logic by solving programs. Owner: @Pradeep_saii”

Thanks to the high frequency of updates (latest data received on 27 August, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.

12 822
Subscribers
-224 hours
-357 days
-21030 days
Posts Archive
πŸ’» Input Validation for Positive Number
#include <stdio.h>

int main() {
  int number;

  do {
    printf("Enter a positive number: ");
    scanf("%d", &number);

    if (number <= 0) {
      printf("Invalid input. Please enter a positive number.n");
    }
  } while (number <= 0);

  printf("You entered: %dn", number);

  return 0;
}
πŸ“€ Output:
Input: -5
Output: Enter a positive number: Invalid input. Please enter a positive number.
Input: 0
Output: Enter a positive number: Invalid input. Please enter a positive number.
Input: 10
Output: Enter a positive number: You entered: 10

πŸ’» Number Guessing Game
#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main() {
    int secretNumber, guess;
    int attempts = 0;

    srand(time(0));
    secretNumber = rand() % 100 + 1;

    do {
        printf("Guess a number between 1 and 100: ");
        scanf("%d", &guess);
        attempts++;

        if (guess > secretNumber) {
            printf("Too high!n");
        } else if (guess < secretNumber) {
            printf("Too low!n");
        } else {
            printf("Congratulations! You guessed the number in %d attempts.n", attempts);
        }
    } while (guess != secretNumber);

    return 0;
}
πŸ“€ Output:
Guess a number between 1 and 100: Input: 50
Output: Too high!
Guess a number between 1 and 100: Input: 25
Output: Too low!
Guess a number between 1 and 100: Input: 37
Output: Too high!
Guess a number between 1 and 100: Input: 31
Output: Too low!
Guess a number between 1 and 100: Input: 34
Output: Too low!
Guess a number between 1 and 100: Input: 35
Output: Congratulations! You guessed the number in 6 attempts.

πŸ’» Menu-Driven Calculator
#include <stdio.h>
#include <stdlib.h>

int main() {
    int choice;
    float num1, num2, result;

    do {
        printf("Menu:n");
        printf("1. Additionn");
        printf("2. Subtractionn");
        printf("3. Multiplicationn");
        printf("4. Divisionn");
        printf("0. Exitn");
        printf("Enter your choice: ");
        scanf("%d", &choice);

        if (choice >= 1 && choice <= 4) {
            printf("Enter two numbers: ");
            scanf("%f %f", &num1, &num2);
        }

        switch (choice) {
            case 1:
                result = num1 + num2;
                printf("Result: %fn", result);
                break;
            case 2:
                result = num1 - num2;
                printf("Result: %fn", result);
                break;
            case 3:
                result = num1 * num2;
                printf("Result: %fn", result);
                break;
            case 4:
                if (num2 != 0) {
                    result = num1 / num2;
                    printf("Result: %fn", result);
                } else {
                    printf("Cannot divide by zero.n");
                }
                break;
            case 0:
                printf("Exiting...n");
                break;
            default:
                printf("Invalid choice.n");
        }
    } while (choice != 0);

    return 0;
}
πŸ“€ Output:
Menu:
1. Addition
2. Subtraction
3. Multiplication
4. Division
0. Exit
Enter your choice: 1
Input: 1
Enter two numbers:
Input: 5.0 3.0
Output: Result: 8.000000
Menu:
1. Addition
2. Subtraction
3. Multiplication
4. Division
0. Exit
Enter your choice: 2
Input: 2
Enter two numbers:
Input: 10.0 4.0
Output: Result: 6.000000
Menu:
1. Addition
2. Subtraction
3. Multiplication
4. Division
0. Exit
Enter your choice: 3
Input: 3
Enter two numbers:
Input: 2.5 4.0
Output: Result: 10.000000
Menu:
1. Addition
2. Subtraction
3. Multiplication
4. Division
0. Exit
Enter your choice: 4
Input: 4
Enter two numbers:
Input: 10.0 2.0
Output: Result: 5.000000
Menu:
1. Addition
2. Subtraction
3. Multiplication
4. Division
0. Exit
Enter your choice: 4
Input: 4
Enter two numbers:
Input: 5.0 0.0
Output: Cannot divide by zero.
Menu:
1. Addition
2. Subtraction
3. Multiplication
4. Division
0. Exit
Enter your choice: 5
Input: 5
Output: Invalid choice.
Menu:
1. Addition
2. Subtraction
3. Multiplication
4. Division
0. Exit
Enter your choice: 0
Input: 0
Output: Exiting...

πŸ”§ Loops - Do-While

πŸ’» Calculate Power of Number (Without pow function)
#include <stdio.h>

int main() {
    int base, exponent;
    long long result = 1;

    printf("Enter the base: ");
    scanf("%d", &base);

    printf("Enter the exponent: ");
    scanf("%d", &exponent);

    for (int i = 0; i < exponent; i++) {
        result *= base;
    }

    printf("Result = %lldn", result);

    return 0;
}
πŸ“€ Output:
Input: 2
Input: 3
Output: Result = 8

Input: 5
Input: 0
Output: Result = 1

Input: 3
Input: 4
Output: Result = 81

Input: 2
Input: 10
Output: Result = 1024

πŸ’» Find LCM of Two Numbers
#include <stdio.h>

int main() {
    int num1, num2, max;

    scanf("%d %d", &num1, &num2);

    max = (num1 > num2) ? num1 : num2;

    for (;;) {
        if (max % num1 == 0 && max % num2 == 0) {
            printf("%d", max);
            break;
        }
        max++;
    }

    return 0;
}
πŸ“€ Output:
Input: 12 18
Output: 36
Input: 5 7
Output: 35
Input: 2 4
Output: 4
Input: 15 25
Output: 75
Input: 1 10
Output: 10

πŸ’» Print Pattern - Diamond
#include <stdio.h>

int main() {
    int rows, i, j, space;

    scanf("%d", &rows);

    for (i = 1; i <= rows; i++) {
        for (space = i; space < rows; space++) {
            printf(" ");
        }
        for (j = 1; j <= (2 * i - 1); j++) {
            printf("*");
        }
        printf("n");
    }

    for (i = rows - 1; i >= 1; i--) {
        for (space = i; space < rows; space++) {
            printf(" ");
        }
        for (j = 1; j <= (2 * i - 1); j++) {
            printf("*");
        }
        printf("n");
    }

    return 0;
}
πŸ“€ Output:
Input: 5
Output:
    *
   ***
  *****
 *******
*********
 *******
  *****
   ***
    *

πŸ’» Print Pattern - Pyramid
#include <stdio.h>

int main() {
  int rows, i, j, space;

  printf("Enter the number of rows: ");
  scanf("%d", &rows);

  for (i = 1; i <= rows; i++) {
    for (space = i; space < rows; space++) {
      printf(" ");
    }

    for (j = 1; j <= (2 * i - 1); j++) {
      printf("*");
    }
    printf("n");
  }

  return 0;
}
πŸ“€ Output:
// Code not available

πŸ’» Print Pattern - Inverted Right Triangle
#include <stdio.h>

int main() {
  int rows, i, j;

  printf("Enter the number of rows: ");
  scanf("%d", &rows);

  for (i = rows; i >= 1; --i) {
    for (j = 1; j <= i; ++j) {
      printf("*");
    }
    printf("n");
  }

  return 0;
}
πŸ“€ Output:
Input: 5
Output:
Enter the number of rows: *****
****
***
**
*

πŸ’» Print Pattern - Right Triangle
#include <stdio.h>

int main() {
  int rows;

  printf("Enter the number of rows: ");
  scanf("%d", &rows);

  for (int i = 1; i <= rows; i++) {
    for (int j = 1; j <= i; j++) {
      printf("*");
    }
    printf("n");
  }

  return 0;
}
πŸ“€ Output:
Input: 5
Output: *
**
***
****
*****

πŸ’» Find Factors of a Number
#include <stdio.h>

int main() {
    int num, i;

    printf("Enter an integer: ");
    scanf("%d", &num);

    printf("Factors of %d are: ", num);

    for (i = 1; i <= num; ++i) {
        if (num % i == 0) {
            printf("%d ", i);
        }
    }

    printf("n");

    return 0;
}
πŸ“€ Output:
Input: 12
Output: Factors of 12 are: 1 2 3 4 6 12

Input: 7
Output: Factors of 7 are: 1 7

Input: 25
Output: Factors of 25 are: 1 5 25

Input: 1
Output: Factors of 1 are: 1

πŸ’» Prime Number Checker
#include <stdio.h>

int main() {
    int num, i, flag = 0;

    printf("Enter a positive integer: ");
    scanf("%d", &num);

    if (num <= 1) {
        printf("%d is not a prime number.n", num);
        return 0;
    }

    for (i = 2; i <= num / 2; ++i) {
        if (num % i == 0) {
            flag = 1;
            break;
        }
    }

    if (flag == 0)
        printf("%d is a prime number.n", num);
    else
        printf("%d is not a prime number.n", num);

    return 0;
}
πŸ“€ Output:
Input: 7
Output: 7 is a prime number.

Input: 12
Output: 12 is not a prime number.

Input: 1
Output: 1 is not a prime number.

Input: 2
Output: 2 is a prime number.

Input: 0
Output: 0 is not a prime number.

Input: -5
Output: -5 is not a prime number.

πŸ’» Find Prime Numbers in a Range
#include <stdio.h>
#include <stdbool.h>

int main() {
    int start, end, i, j;
    bool isPrime;

    printf("Enter the starting number: ");
    scanf("%d", &start);

    printf("Enter the ending number: ");
    scanf("%d", &end);

    printf("Prime numbers between %d and %d are:n", start, end);

    for (i = start; i <= end; i++) {
        if (i <= 1)
            continue;

        isPrime = true;
        for (j = 2; j * j <= i; j++) {
            if (i % j == 0) {
                isPrime = false;
                break;
            }
        }

        if (isPrime) {
            printf("%d ", i);
        }
    }
    printf("n");
    return 0;
}
πŸ“€ Output:
Input: 10
Input: 20
Output: Prime numbers between 10 and 20 are:
11 13 17 19
Input: 1
Input: 10
Output: Prime numbers between 1 and 10 are:
2 3 5 7
Input: 20
Input: 30
Output: Prime numbers between 20 and 30 are:
23 29
Input: 1
Input: 1
Output: Prime numbers between 1 and 1 are:

πŸ’» Find Fibonacci Series up to N Terms
#include <stdio.h>

int main() {
  int n, i;
  int first = 0, second = 1;
  int next;

  printf("Enter the number of terms: ");
  scanf("%d", &n);

  printf("Fibonacci Series: ");

  for (i = 0; i < n; i++) {
    printf("%d ", first);
    next = first + second;
    first = second;
    second = next;
  }

  printf("n");
  return 0;
}
πŸ“€ Output:
Input: 10
Output: Fibonacci Series: 0 1 1 2 3 5 8 13 21 34

πŸ’» Find All Strong Numbers in a Range
#include <stdio.h>

int factorial(int n) {
    int fact = 1;
    for (int i = 1; i <= n; i++) {
        fact *= i;
    }
    return fact;
}

int isStrong(int num) {
    int sum = 0;
    int temp = num;
    while (temp != 0) {
        int digit = temp % 10;
        sum += factorial(digit);
        temp /= 10;
    }
    return (sum == num);
}

int main() {
    int start, end;

    printf("Enter the starting number: ");
    scanf("%d", &start);

    printf("Enter the ending number: ");
    scanf("%d", &end);

    printf("Strong numbers between %d and %d are: ", start, end);
    for (int i = start; i <= end; i++) {
        if (isStrong(i)) {
            printf("%d ", i);
        }
    }
    printf("n");

    return 0;
}
πŸ“€ Output:
Input: 1
Input: 150
Output: Strong numbers between 1 and 150 are: 1 2 145

πŸ’» Find All Perfect Numbers in a Range
#include <stdio.h>

int main() {
    int start, end, i, j, sum;

    printf("Enter the starting number: ");
    scanf("%d", &start);

    printf("Enter the ending number: ");
    scanf("%d", &end);

    printf("Perfect numbers between %d and %d are: ", start, end);

    for (i = start; i <= end; i++) {
        sum = 0;
        for (j = 1; j < i; j++) {
            if (i % j == 0) {
                sum += j;
            }
        }

        if (sum == i) {
            printf("%d ", i);
        }
    }
    printf("n");

    return 0;
}
πŸ“€ Output:
Input: 1
Input: 10
Output: Perfect numbers between 1 and 10 are: 6
Input: 20
Input: 30
Output: Perfect numbers between 20 and 30 are: 28
Input: 1
Input: 500
Output: Perfect numbers between 1 and 500 are: 6 28 496
Input: 490
Input: 500
Output: Perfect numbers between 490 and 500 are: 496

πŸ’» Find All Armstrong Numbers in a Range
#include <stdio.h>
#include <math.h>

int main() {
    int start, end, i, num, originalNum, remainder, n = 0;
    float result = 0.0;

    printf("Enter the start of the range: ");
    scanf("%d", &start);
    printf("Enter the end of the range: ");
    scanf("%d", &end);

    printf("Armstrong numbers between %d and %d are: ", start, end);

    for (i = start; i <= end; ++i) {
        originalNum = i;
        num = i;
        n = 0;
        result = 0.0;

        while (originalNum != 0) {
            originalNum /= 10;
            ++n;
        }

        originalNum = num;

        while (originalNum != 0) {
            remainder = originalNum % 10;
            result += pow(remainder, n);
            originalNum /= 10;
        }

        if ((int)result == num) {
            printf("%d ", num);
        }
    }

    printf("n");

    return 0;
}
πŸ“€ Output:
Input: 100
Input: 500
Output: Armstrong numbers between 100 and 500 are: 153 370 371 407
Input: 1
Input: 10
Output: Armstrong numbers between 1 and 10 are: 1 2 3 4 5 6 7 8 9
Input: 0
Input: 0
Output: Armstrong numbers between 0 and 0 are: 0

πŸ’» Check if Number is Armstrong
#include <stdio.h>
#include <math.h>

int main() {
    int number, originalNumber, remainder, n = 0;
    float result = 0.0;

    printf("Enter an integer: ");
    scanf("%d", &number);

    originalNumber = number;

    // Count number of digits
    while (originalNumber != 0) {
        originalNumber /= 10;
        ++n;
    }

    originalNumber = number;

    // Calculate result
    while (originalNumber != 0) {
        remainder = originalNumber % 10;
        result += pow(remainder, n);
        originalNumber /= 10;
    }

    // Check if number is Armstrong
    if ((int)result == number)
        printf("%d is an Armstrong number.", number);
    else
        printf("%d is not an Armstrong number.", number);

    return 0;
}
πŸ“€ Output:
Input: 153
Output: 153 is an Armstrong number.

Input: 120
Output: 120 is not an Armstrong number.

Input: 1634
Output: 1634 is an Armstrong number.

Input: 1234
Output: 1234 is not an Armstrong number.

πŸ’» Check if Number is Palindrome
#include <stdio.h>

int main() {
    int num, reversed_num = 0, remainder, original_num;

    printf("Enter an integer: ");
    scanf("%d", &num);

    original_num = num;

    for (; num != 0; num /= 10) {
        remainder = num % 10;
        reversed_num = reversed_num * 10 + remainder;
    }

    if (original_num == reversed_num)
        printf("%d is a palindrome.n", original_num);
    else
        printf("%d is not a palindrome.n", original_num);

    return 0;
}
πŸ“€ Output:
Input: 121
Output: 121 is a palindrome.

Input: 123
Output: 123 is not a palindrome.

Input: 12321
Output: 12321 is a palindrome.

Input: 12345
Output: 12345 is not a palindrome.

Input: 1
Output: 1 is a palindrome.

Input: 0
Output: 0 is a palindrome.