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Code With SaiPradeep

Code With SaiPradeep

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A space for curious minds to explore software engineering, computer science, programming and technology. Learn. Explore. Understand.

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πŸ“ˆ Analytical overview of Telegram channel Code With SaiPradeep

Channel Code With SaiPradeep (@codewithsaipradeep) in the English language segment is an active participant. Currently, the community unites 12 327 subscribers, ranking 10 232 in the Technologies & Applications category and 31 271 in the India region.

πŸ“Š Audience metrics and dynamics

Since its creation on Π½Π΅Π²Ρ–Π΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 12 327 subscribers.

According to the latest data from 12 November, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -238 over the last 30 days and by -8 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 10.45%. Within the first 24 hours after publication, content typically collects N/A% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 1 288 views. Within the first day, a publication typically gains 0 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 11.
  • Thematic interests: Content is focused on key topics such as input, string, scanf("%d, array, element.

πŸ“ Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
β€œA space for curious minds to explore software engineering, computer science, programming and technology. Learn. Explore. Understand.”

Thanks to the high frequency of updates (latest data received on 13 November, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.

12 327
Subscribers
-824 hours
-827 days
-23830 days
Posts Archive
πŸ’» Continue until User Says 'No'
#include <stdio.h>

int main() {
    char answer;

    do {
        printf("Do you want to continue? (y/n): ");
        scanf(" %c", &answer);

        if (answer == 'y') {
            printf("Continuing...n");
        } else if (answer == 'n') {
            printf("Exiting...n");
        } else {
            printf("Invalid input. Please enter 'y' or 'n'.n");
        }

    } while (answer != 'n');

    return 0;
}
πŸ“€ Output:
Input: y
Output: Do you want to continue? (y/n): Continuing...
Input: z
Output: Do you want to continue? (y/n): Invalid input. Please enter 'y' or 'n'.
Input: Y
Output: Do you want to continue? (y/n): Invalid input. Please enter 'y' or 'n'.
Input: n
Output: Do you want to continue? (y/n): Exiting...

πŸ’» Input Validation for Range
#include <stdio.h>

int main() {
  int number;
  int lower_bound = 10;
  int upper_bound = 20;

  do {
    printf("Enter a number between %d and %d: ", lower_bound, upper_bound);
    scanf("%d", &number);

    if (number < lower_bound || number > upper_bound) {
      printf("Invalid input. Please enter a number within the specified range.n");
    }
  } while (number < lower_bound || number > upper_bound);

  printf("You entered: %dn", number);

  return 0;
}
πŸ“€ Output:
Input: 5
Output: Enter a number between 10 and 20: 5
Invalid input. Please enter a number within the specified range.
Input: 25
Output: Enter a number between 10 and 20: 25
Invalid input. Please enter a number within the specified range.
Input: 15
Output: Enter a number between 10 and 20: 15
You entered: 15

πŸ’» Input Validation for Positive Number
#include <stdio.h>

int main() {
  int number;

  do {
    printf("Enter a positive number: ");
    scanf("%d", &number);

    if (number <= 0) {
      printf("Invalid input. Please enter a positive number.n");
    }
  } while (number <= 0);

  printf("You entered: %dn", number);

  return 0;
}
πŸ“€ Output:
Input: -5
Output: Enter a positive number: Invalid input. Please enter a positive number.
Input: 0
Output: Enter a positive number: Invalid input. Please enter a positive number.
Input: 10
Output: Enter a positive number: You entered: 10

πŸ’» Number Guessing Game
#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main() {
    int secretNumber, guess;
    int attempts = 0;

    srand(time(0));
    secretNumber = rand() % 100 + 1;

    do {
        printf("Guess a number between 1 and 100: ");
        scanf("%d", &guess);
        attempts++;

        if (guess > secretNumber) {
            printf("Too high!n");
        } else if (guess < secretNumber) {
            printf("Too low!n");
        } else {
            printf("Congratulations! You guessed the number in %d attempts.n", attempts);
        }
    } while (guess != secretNumber);

    return 0;
}
πŸ“€ Output:
Guess a number between 1 and 100: Input: 50
Output: Too high!
Guess a number between 1 and 100: Input: 25
Output: Too low!
Guess a number between 1 and 100: Input: 37
Output: Too high!
Guess a number between 1 and 100: Input: 31
Output: Too low!
Guess a number between 1 and 100: Input: 34
Output: Too low!
Guess a number between 1 and 100: Input: 35
Output: Congratulations! You guessed the number in 6 attempts.

πŸ’» Menu-Driven Calculator
#include <stdio.h>
#include <stdlib.h>

int main() {
    int choice;
    float num1, num2, result;

    do {
        printf("Menu:n");
        printf("1. Additionn");
        printf("2. Subtractionn");
        printf("3. Multiplicationn");
        printf("4. Divisionn");
        printf("0. Exitn");
        printf("Enter your choice: ");
        scanf("%d", &choice);

        if (choice >= 1 && choice <= 4) {
            printf("Enter two numbers: ");
            scanf("%f %f", &num1, &num2);
        }

        switch (choice) {
            case 1:
                result = num1 + num2;
                printf("Result: %fn", result);
                break;
            case 2:
                result = num1 - num2;
                printf("Result: %fn", result);
                break;
            case 3:
                result = num1 * num2;
                printf("Result: %fn", result);
                break;
            case 4:
                if (num2 != 0) {
                    result = num1 / num2;
                    printf("Result: %fn", result);
                } else {
                    printf("Cannot divide by zero.n");
                }
                break;
            case 0:
                printf("Exiting...n");
                break;
            default:
                printf("Invalid choice.n");
        }
    } while (choice != 0);

    return 0;
}
πŸ“€ Output:
Menu:
1. Addition
2. Subtraction
3. Multiplication
4. Division
0. Exit
Enter your choice: 1
Input: 1
Enter two numbers:
Input: 5.0 3.0
Output: Result: 8.000000
Menu:
1. Addition
2. Subtraction
3. Multiplication
4. Division
0. Exit
Enter your choice: 2
Input: 2
Enter two numbers:
Input: 10.0 4.0
Output: Result: 6.000000
Menu:
1. Addition
2. Subtraction
3. Multiplication
4. Division
0. Exit
Enter your choice: 3
Input: 3
Enter two numbers:
Input: 2.5 4.0
Output: Result: 10.000000
Menu:
1. Addition
2. Subtraction
3. Multiplication
4. Division
0. Exit
Enter your choice: 4
Input: 4
Enter two numbers:
Input: 10.0 2.0
Output: Result: 5.000000
Menu:
1. Addition
2. Subtraction
3. Multiplication
4. Division
0. Exit
Enter your choice: 4
Input: 4
Enter two numbers:
Input: 5.0 0.0
Output: Cannot divide by zero.
Menu:
1. Addition
2. Subtraction
3. Multiplication
4. Division
0. Exit
Enter your choice: 5
Input: 5
Output: Invalid choice.
Menu:
1. Addition
2. Subtraction
3. Multiplication
4. Division
0. Exit
Enter your choice: 0
Input: 0
Output: Exiting...

πŸ”§ Loops - Do-While

πŸ’» Calculate Power of Number (Without pow function)
#include <stdio.h>

int main() {
    int base, exponent;
    long long result = 1;

    printf("Enter the base: ");
    scanf("%d", &base);

    printf("Enter the exponent: ");
    scanf("%d", &exponent);

    for (int i = 0; i < exponent; i++) {
        result *= base;
    }

    printf("Result = %lldn", result);

    return 0;
}
πŸ“€ Output:
Input: 2
Input: 3
Output: Result = 8

Input: 5
Input: 0
Output: Result = 1

Input: 3
Input: 4
Output: Result = 81

Input: 2
Input: 10
Output: Result = 1024

πŸ’» Find LCM of Two Numbers
#include <stdio.h>

int main() {
    int num1, num2, max;

    scanf("%d %d", &num1, &num2);

    max = (num1 > num2) ? num1 : num2;

    for (;;) {
        if (max % num1 == 0 && max % num2 == 0) {
            printf("%d", max);
            break;
        }
        max++;
    }

    return 0;
}
πŸ“€ Output:
Input: 12 18
Output: 36
Input: 5 7
Output: 35
Input: 2 4
Output: 4
Input: 15 25
Output: 75
Input: 1 10
Output: 10

πŸ’» Print Pattern - Diamond
#include <stdio.h>

int main() {
    int rows, i, j, space;

    scanf("%d", &rows);

    for (i = 1; i <= rows; i++) {
        for (space = i; space < rows; space++) {
            printf(" ");
        }
        for (j = 1; j <= (2 * i - 1); j++) {
            printf("*");
        }
        printf("n");
    }

    for (i = rows - 1; i >= 1; i--) {
        for (space = i; space < rows; space++) {
            printf(" ");
        }
        for (j = 1; j <= (2 * i - 1); j++) {
            printf("*");
        }
        printf("n");
    }

    return 0;
}
πŸ“€ Output:
Input: 5
Output:
    *
   ***
  *****
 *******
*********
 *******
  *****
   ***
    *

πŸ’» Print Pattern - Pyramid
#include <stdio.h>

int main() {
  int rows, i, j, space;

  printf("Enter the number of rows: ");
  scanf("%d", &rows);

  for (i = 1; i <= rows; i++) {
    for (space = i; space < rows; space++) {
      printf(" ");
    }

    for (j = 1; j <= (2 * i - 1); j++) {
      printf("*");
    }
    printf("n");
  }

  return 0;
}
πŸ“€ Output:
// Code not available

πŸ’» Print Pattern - Inverted Right Triangle
#include <stdio.h>

int main() {
  int rows, i, j;

  printf("Enter the number of rows: ");
  scanf("%d", &rows);

  for (i = rows; i >= 1; --i) {
    for (j = 1; j <= i; ++j) {
      printf("*");
    }
    printf("n");
  }

  return 0;
}
πŸ“€ Output:
Input: 5
Output:
Enter the number of rows: *****
****
***
**
*

πŸ’» Print Pattern - Right Triangle
#include <stdio.h>

int main() {
  int rows;

  printf("Enter the number of rows: ");
  scanf("%d", &rows);

  for (int i = 1; i <= rows; i++) {
    for (int j = 1; j <= i; j++) {
      printf("*");
    }
    printf("n");
  }

  return 0;
}
πŸ“€ Output:
Input: 5
Output: *
**
***
****
*****

πŸ’» Find Factors of a Number
#include <stdio.h>

int main() {
    int num, i;

    printf("Enter an integer: ");
    scanf("%d", &num);

    printf("Factors of %d are: ", num);

    for (i = 1; i <= num; ++i) {
        if (num % i == 0) {
            printf("%d ", i);
        }
    }

    printf("n");

    return 0;
}
πŸ“€ Output:
Input: 12
Output: Factors of 12 are: 1 2 3 4 6 12

Input: 7
Output: Factors of 7 are: 1 7

Input: 25
Output: Factors of 25 are: 1 5 25

Input: 1
Output: Factors of 1 are: 1

πŸ’» Prime Number Checker
#include <stdio.h>

int main() {
    int num, i, flag = 0;

    printf("Enter a positive integer: ");
    scanf("%d", &num);

    if (num <= 1) {
        printf("%d is not a prime number.n", num);
        return 0;
    }

    for (i = 2; i <= num / 2; ++i) {
        if (num % i == 0) {
            flag = 1;
            break;
        }
    }

    if (flag == 0)
        printf("%d is a prime number.n", num);
    else
        printf("%d is not a prime number.n", num);

    return 0;
}
πŸ“€ Output:
Input: 7
Output: 7 is a prime number.

Input: 12
Output: 12 is not a prime number.

Input: 1
Output: 1 is not a prime number.

Input: 2
Output: 2 is a prime number.

Input: 0
Output: 0 is not a prime number.

Input: -5
Output: -5 is not a prime number.

πŸ’» Find Prime Numbers in a Range
#include <stdio.h>
#include <stdbool.h>

int main() {
    int start, end, i, j;
    bool isPrime;

    printf("Enter the starting number: ");
    scanf("%d", &start);

    printf("Enter the ending number: ");
    scanf("%d", &end);

    printf("Prime numbers between %d and %d are:n", start, end);

    for (i = start; i <= end; i++) {
        if (i <= 1)
            continue;

        isPrime = true;
        for (j = 2; j * j <= i; j++) {
            if (i % j == 0) {
                isPrime = false;
                break;
            }
        }

        if (isPrime) {
            printf("%d ", i);
        }
    }
    printf("n");
    return 0;
}
πŸ“€ Output:
Input: 10
Input: 20
Output: Prime numbers between 10 and 20 are:
11 13 17 19
Input: 1
Input: 10
Output: Prime numbers between 1 and 10 are:
2 3 5 7
Input: 20
Input: 30
Output: Prime numbers between 20 and 30 are:
23 29
Input: 1
Input: 1
Output: Prime numbers between 1 and 1 are:

πŸ’» Find Fibonacci Series up to N Terms
#include <stdio.h>

int main() {
  int n, i;
  int first = 0, second = 1;
  int next;

  printf("Enter the number of terms: ");
  scanf("%d", &n);

  printf("Fibonacci Series: ");

  for (i = 0; i < n; i++) {
    printf("%d ", first);
    next = first + second;
    first = second;
    second = next;
  }

  printf("n");
  return 0;
}
πŸ“€ Output:
Input: 10
Output: Fibonacci Series: 0 1 1 2 3 5 8 13 21 34

πŸ’» Find All Strong Numbers in a Range
#include <stdio.h>

int factorial(int n) {
    int fact = 1;
    for (int i = 1; i <= n; i++) {
        fact *= i;
    }
    return fact;
}

int isStrong(int num) {
    int sum = 0;
    int temp = num;
    while (temp != 0) {
        int digit = temp % 10;
        sum += factorial(digit);
        temp /= 10;
    }
    return (sum == num);
}

int main() {
    int start, end;

    printf("Enter the starting number: ");
    scanf("%d", &start);

    printf("Enter the ending number: ");
    scanf("%d", &end);

    printf("Strong numbers between %d and %d are: ", start, end);
    for (int i = start; i <= end; i++) {
        if (isStrong(i)) {
            printf("%d ", i);
        }
    }
    printf("n");

    return 0;
}
πŸ“€ Output:
Input: 1
Input: 150
Output: Strong numbers between 1 and 150 are: 1 2 145

πŸ’» Find All Perfect Numbers in a Range
#include <stdio.h>

int main() {
    int start, end, i, j, sum;

    printf("Enter the starting number: ");
    scanf("%d", &start);

    printf("Enter the ending number: ");
    scanf("%d", &end);

    printf("Perfect numbers between %d and %d are: ", start, end);

    for (i = start; i <= end; i++) {
        sum = 0;
        for (j = 1; j < i; j++) {
            if (i % j == 0) {
                sum += j;
            }
        }

        if (sum == i) {
            printf("%d ", i);
        }
    }
    printf("n");

    return 0;
}
πŸ“€ Output:
Input: 1
Input: 10
Output: Perfect numbers between 1 and 10 are: 6
Input: 20
Input: 30
Output: Perfect numbers between 20 and 30 are: 28
Input: 1
Input: 500
Output: Perfect numbers between 1 and 500 are: 6 28 496
Input: 490
Input: 500
Output: Perfect numbers between 490 and 500 are: 496

πŸ’» Find All Armstrong Numbers in a Range
#include <stdio.h>
#include <math.h>

int main() {
    int start, end, i, num, originalNum, remainder, n = 0;
    float result = 0.0;

    printf("Enter the start of the range: ");
    scanf("%d", &start);
    printf("Enter the end of the range: ");
    scanf("%d", &end);

    printf("Armstrong numbers between %d and %d are: ", start, end);

    for (i = start; i <= end; ++i) {
        originalNum = i;
        num = i;
        n = 0;
        result = 0.0;

        while (originalNum != 0) {
            originalNum /= 10;
            ++n;
        }

        originalNum = num;

        while (originalNum != 0) {
            remainder = originalNum % 10;
            result += pow(remainder, n);
            originalNum /= 10;
        }

        if ((int)result == num) {
            printf("%d ", num);
        }
    }

    printf("n");

    return 0;
}
πŸ“€ Output:
Input: 100
Input: 500
Output: Armstrong numbers between 100 and 500 are: 153 370 371 407
Input: 1
Input: 10
Output: Armstrong numbers between 1 and 10 are: 1 2 3 4 5 6 7 8 9
Input: 0
Input: 0
Output: Armstrong numbers between 0 and 0 are: 0