C Programming Language || Hands On Coding
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Hands-on C programming language challenges for beginners. Learn building logic by solving programs. Owner: @Pradeep_saii
Mostrar más📈 Análisis del canal de Telegram C Programming Language || Hands On Coding
El canal C Programming Language || Hands On Coding (@c_programming_language_coding) en el segmento lingüístico de Inglés es un actor destacado. Actualmente la comunidad reúne a 12 822 suscriptores, ocupando la posición 9 562 en la categoría Tecnologías y Aplicaciones y el puesto 31 207 en la región India.
📊 Métricas de audiencia y dinámica
Desde su creación el невідомо, el proyecto ha mostrado un crecimiento acelerado, reuniendo a 12 822 suscriptores.
Según los últimos datos del 26 agosto, 2026, el canal mantiene una actividad estable. En los últimos 30 días la variación de miembros fue de -210, y en las últimas 24 horas de -2, conservando un alto alcance.
- Estado de verificación: No verificado
- Tasa de interacción (ER): El promedio de interacción de la audiencia es 12.56%. Durante las primeras 24 horas tras publicar, el contenido suele obtener 2.42% de reacciones respecto al total de suscriptores.
- Alcance de las publicaciones: Cada publicación recibe en promedio 1 612 visualizaciones. En el primer día suele acumular 310 visualizaciones.
- Reacciones e interacción: La audiencia responde de forma activa: el promedio de reacciones por publicación es 4.
- Intereses temáticos: El contenido se centra en temas clave como input, string, scanf("%d, array, element.
📝 Descripción y política de contenido
El autor describe el recurso como un espacio para expresar opiniones subjetivas:
“Hands-on C programming language challenges for beginners. Learn building logic by solving programs.
Owner: @Pradeep_saii”
Gracias a la alta frecuencia de actualizaciones (últimos datos recibidos el 27 agosto, 2026), el canal mantiene la vigencia y un amplio alcance. La analítica demuestra que la audiencia interactúa activamente con el contenido, lo que lo convierte en un punto de referencia dentro de la categoría Tecnologías y Aplicaciones.
12 822
Suscriptores
-224 horas
-357 días
-21030 días
Archivo de publicaciones
💻 Input Validation for Positive Number
#include <stdio.h>
int main() {
int number;
do {
printf("Enter a positive number: ");
scanf("%d", &number);
if (number <= 0) {
printf("Invalid input. Please enter a positive number.n");
}
} while (number <= 0);
printf("You entered: %dn", number);
return 0;
}
Input: -5 Output: Enter a positive number: Invalid input. Please enter a positive number. Input: 0 Output: Enter a positive number: Invalid input. Please enter a positive number. Input: 10 Output: Enter a positive number: You entered: 10
💻 Number Guessing Game
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
int main() {
int secretNumber, guess;
int attempts = 0;
srand(time(0));
secretNumber = rand() % 100 + 1;
do {
printf("Guess a number between 1 and 100: ");
scanf("%d", &guess);
attempts++;
if (guess > secretNumber) {
printf("Too high!n");
} else if (guess < secretNumber) {
printf("Too low!n");
} else {
printf("Congratulations! You guessed the number in %d attempts.n", attempts);
}
} while (guess != secretNumber);
return 0;
}
Guess a number between 1 and 100: Input: 50 Output: Too high! Guess a number between 1 and 100: Input: 25 Output: Too low! Guess a number between 1 and 100: Input: 37 Output: Too high! Guess a number between 1 and 100: Input: 31 Output: Too low! Guess a number between 1 and 100: Input: 34 Output: Too low! Guess a number between 1 and 100: Input: 35 Output: Congratulations! You guessed the number in 6 attempts.
💻 Menu-Driven Calculator
#include <stdio.h>
#include <stdlib.h>
int main() {
int choice;
float num1, num2, result;
do {
printf("Menu:n");
printf("1. Additionn");
printf("2. Subtractionn");
printf("3. Multiplicationn");
printf("4. Divisionn");
printf("0. Exitn");
printf("Enter your choice: ");
scanf("%d", &choice);
if (choice >= 1 && choice <= 4) {
printf("Enter two numbers: ");
scanf("%f %f", &num1, &num2);
}
switch (choice) {
case 1:
result = num1 + num2;
printf("Result: %fn", result);
break;
case 2:
result = num1 - num2;
printf("Result: %fn", result);
break;
case 3:
result = num1 * num2;
printf("Result: %fn", result);
break;
case 4:
if (num2 != 0) {
result = num1 / num2;
printf("Result: %fn", result);
} else {
printf("Cannot divide by zero.n");
}
break;
case 0:
printf("Exiting...n");
break;
default:
printf("Invalid choice.n");
}
} while (choice != 0);
return 0;
}
Menu: 1. Addition 2. Subtraction 3. Multiplication 4. Division 0. Exit Enter your choice: 1 Input: 1 Enter two numbers: Input: 5.0 3.0 Output: Result: 8.000000 Menu: 1. Addition 2. Subtraction 3. Multiplication 4. Division 0. Exit Enter your choice: 2 Input: 2 Enter two numbers: Input: 10.0 4.0 Output: Result: 6.000000 Menu: 1. Addition 2. Subtraction 3. Multiplication 4. Division 0. Exit Enter your choice: 3 Input: 3 Enter two numbers: Input: 2.5 4.0 Output: Result: 10.000000 Menu: 1. Addition 2. Subtraction 3. Multiplication 4. Division 0. Exit Enter your choice: 4 Input: 4 Enter two numbers: Input: 10.0 2.0 Output: Result: 5.000000 Menu: 1. Addition 2. Subtraction 3. Multiplication 4. Division 0. Exit Enter your choice: 4 Input: 4 Enter two numbers: Input: 5.0 0.0 Output: Cannot divide by zero. Menu: 1. Addition 2. Subtraction 3. Multiplication 4. Division 0. Exit Enter your choice: 5 Input: 5 Output: Invalid choice. Menu: 1. Addition 2. Subtraction 3. Multiplication 4. Division 0. Exit Enter your choice: 0 Input: 0 Output: Exiting...
💻 Calculate Power of Number (Without pow function)
#include <stdio.h>
int main() {
int base, exponent;
long long result = 1;
printf("Enter the base: ");
scanf("%d", &base);
printf("Enter the exponent: ");
scanf("%d", &exponent);
for (int i = 0; i < exponent; i++) {
result *= base;
}
printf("Result = %lldn", result);
return 0;
}
Input: 2 Input: 3 Output: Result = 8 Input: 5 Input: 0 Output: Result = 1 Input: 3 Input: 4 Output: Result = 81 Input: 2 Input: 10 Output: Result = 1024
💻 Find LCM of Two Numbers
#include <stdio.h>
int main() {
int num1, num2, max;
scanf("%d %d", &num1, &num2);
max = (num1 > num2) ? num1 : num2;
for (;;) {
if (max % num1 == 0 && max % num2 == 0) {
printf("%d", max);
break;
}
max++;
}
return 0;
}
Input: 12 18 Output: 36 Input: 5 7 Output: 35 Input: 2 4 Output: 4 Input: 15 25 Output: 75 Input: 1 10 Output: 10
💻 Print Pattern - Diamond
#include <stdio.h>
int main() {
int rows, i, j, space;
scanf("%d", &rows);
for (i = 1; i <= rows; i++) {
for (space = i; space < rows; space++) {
printf(" ");
}
for (j = 1; j <= (2 * i - 1); j++) {
printf("*");
}
printf("n");
}
for (i = rows - 1; i >= 1; i--) {
for (space = i; space < rows; space++) {
printf(" ");
}
for (j = 1; j <= (2 * i - 1); j++) {
printf("*");
}
printf("n");
}
return 0;
}
Input: 5
Output:
*
***
*****
*******
*********
*******
*****
***
*💻 Print Pattern - Pyramid
#include <stdio.h>
int main() {
int rows, i, j, space;
printf("Enter the number of rows: ");
scanf("%d", &rows);
for (i = 1; i <= rows; i++) {
for (space = i; space < rows; space++) {
printf(" ");
}
for (j = 1; j <= (2 * i - 1); j++) {
printf("*");
}
printf("n");
}
return 0;
}
// Code not available
💻 Print Pattern - Inverted Right Triangle
#include <stdio.h>
int main() {
int rows, i, j;
printf("Enter the number of rows: ");
scanf("%d", &rows);
for (i = rows; i >= 1; --i) {
for (j = 1; j <= i; ++j) {
printf("*");
}
printf("n");
}
return 0;
}
Input: 5 Output: Enter the number of rows: ***** **** *** ** *
💻 Print Pattern - Right Triangle
#include <stdio.h>
int main() {
int rows;
printf("Enter the number of rows: ");
scanf("%d", &rows);
for (int i = 1; i <= rows; i++) {
for (int j = 1; j <= i; j++) {
printf("*");
}
printf("n");
}
return 0;
}
Input: 5 Output: * ** *** **** *****
💻 Find Factors of a Number
#include <stdio.h>
int main() {
int num, i;
printf("Enter an integer: ");
scanf("%d", &num);
printf("Factors of %d are: ", num);
for (i = 1; i <= num; ++i) {
if (num % i == 0) {
printf("%d ", i);
}
}
printf("n");
return 0;
}
Input: 12 Output: Factors of 12 are: 1 2 3 4 6 12 Input: 7 Output: Factors of 7 are: 1 7 Input: 25 Output: Factors of 25 are: 1 5 25 Input: 1 Output: Factors of 1 are: 1
💻 Prime Number Checker
#include <stdio.h>
int main() {
int num, i, flag = 0;
printf("Enter a positive integer: ");
scanf("%d", &num);
if (num <= 1) {
printf("%d is not a prime number.n", num);
return 0;
}
for (i = 2; i <= num / 2; ++i) {
if (num % i == 0) {
flag = 1;
break;
}
}
if (flag == 0)
printf("%d is a prime number.n", num);
else
printf("%d is not a prime number.n", num);
return 0;
}
Input: 7 Output: 7 is a prime number. Input: 12 Output: 12 is not a prime number. Input: 1 Output: 1 is not a prime number. Input: 2 Output: 2 is a prime number. Input: 0 Output: 0 is not a prime number. Input: -5 Output: -5 is not a prime number.
💻 Find Prime Numbers in a Range
#include <stdio.h>
#include <stdbool.h>
int main() {
int start, end, i, j;
bool isPrime;
printf("Enter the starting number: ");
scanf("%d", &start);
printf("Enter the ending number: ");
scanf("%d", &end);
printf("Prime numbers between %d and %d are:n", start, end);
for (i = start; i <= end; i++) {
if (i <= 1)
continue;
isPrime = true;
for (j = 2; j * j <= i; j++) {
if (i % j == 0) {
isPrime = false;
break;
}
}
if (isPrime) {
printf("%d ", i);
}
}
printf("n");
return 0;
}
Input: 10 Input: 20 Output: Prime numbers between 10 and 20 are: 11 13 17 19 Input: 1 Input: 10 Output: Prime numbers between 1 and 10 are: 2 3 5 7 Input: 20 Input: 30 Output: Prime numbers between 20 and 30 are: 23 29 Input: 1 Input: 1 Output: Prime numbers between 1 and 1 are:
💻 Find Fibonacci Series up to N Terms
#include <stdio.h>
int main() {
int n, i;
int first = 0, second = 1;
int next;
printf("Enter the number of terms: ");
scanf("%d", &n);
printf("Fibonacci Series: ");
for (i = 0; i < n; i++) {
printf("%d ", first);
next = first + second;
first = second;
second = next;
}
printf("n");
return 0;
}
Input: 10 Output: Fibonacci Series: 0 1 1 2 3 5 8 13 21 34
💻 Find All Strong Numbers in a Range
#include <stdio.h>
int factorial(int n) {
int fact = 1;
for (int i = 1; i <= n; i++) {
fact *= i;
}
return fact;
}
int isStrong(int num) {
int sum = 0;
int temp = num;
while (temp != 0) {
int digit = temp % 10;
sum += factorial(digit);
temp /= 10;
}
return (sum == num);
}
int main() {
int start, end;
printf("Enter the starting number: ");
scanf("%d", &start);
printf("Enter the ending number: ");
scanf("%d", &end);
printf("Strong numbers between %d and %d are: ", start, end);
for (int i = start; i <= end; i++) {
if (isStrong(i)) {
printf("%d ", i);
}
}
printf("n");
return 0;
}
Input: 1 Input: 150 Output: Strong numbers between 1 and 150 are: 1 2 145
💻 Find All Perfect Numbers in a Range
#include <stdio.h>
int main() {
int start, end, i, j, sum;
printf("Enter the starting number: ");
scanf("%d", &start);
printf("Enter the ending number: ");
scanf("%d", &end);
printf("Perfect numbers between %d and %d are: ", start, end);
for (i = start; i <= end; i++) {
sum = 0;
for (j = 1; j < i; j++) {
if (i % j == 0) {
sum += j;
}
}
if (sum == i) {
printf("%d ", i);
}
}
printf("n");
return 0;
}
Input: 1 Input: 10 Output: Perfect numbers between 1 and 10 are: 6 Input: 20 Input: 30 Output: Perfect numbers between 20 and 30 are: 28 Input: 1 Input: 500 Output: Perfect numbers between 1 and 500 are: 6 28 496 Input: 490 Input: 500 Output: Perfect numbers between 490 and 500 are: 496
💻 Find All Armstrong Numbers in a Range
#include <stdio.h>
#include <math.h>
int main() {
int start, end, i, num, originalNum, remainder, n = 0;
float result = 0.0;
printf("Enter the start of the range: ");
scanf("%d", &start);
printf("Enter the end of the range: ");
scanf("%d", &end);
printf("Armstrong numbers between %d and %d are: ", start, end);
for (i = start; i <= end; ++i) {
originalNum = i;
num = i;
n = 0;
result = 0.0;
while (originalNum != 0) {
originalNum /= 10;
++n;
}
originalNum = num;
while (originalNum != 0) {
remainder = originalNum % 10;
result += pow(remainder, n);
originalNum /= 10;
}
if ((int)result == num) {
printf("%d ", num);
}
}
printf("n");
return 0;
}
Input: 100 Input: 500 Output: Armstrong numbers between 100 and 500 are: 153 370 371 407 Input: 1 Input: 10 Output: Armstrong numbers between 1 and 10 are: 1 2 3 4 5 6 7 8 9 Input: 0 Input: 0 Output: Armstrong numbers between 0 and 0 are: 0
💻 Check if Number is Armstrong
#include <stdio.h>
#include <math.h>
int main() {
int number, originalNumber, remainder, n = 0;
float result = 0.0;
printf("Enter an integer: ");
scanf("%d", &number);
originalNumber = number;
// Count number of digits
while (originalNumber != 0) {
originalNumber /= 10;
++n;
}
originalNumber = number;
// Calculate result
while (originalNumber != 0) {
remainder = originalNumber % 10;
result += pow(remainder, n);
originalNumber /= 10;
}
// Check if number is Armstrong
if ((int)result == number)
printf("%d is an Armstrong number.", number);
else
printf("%d is not an Armstrong number.", number);
return 0;
}
Input: 153 Output: 153 is an Armstrong number. Input: 120 Output: 120 is not an Armstrong number. Input: 1634 Output: 1634 is an Armstrong number. Input: 1234 Output: 1234 is not an Armstrong number.
💻 Check if Number is Palindrome
#include <stdio.h>
int main() {
int num, reversed_num = 0, remainder, original_num;
printf("Enter an integer: ");
scanf("%d", &num);
original_num = num;
for (; num != 0; num /= 10) {
remainder = num % 10;
reversed_num = reversed_num * 10 + remainder;
}
if (original_num == reversed_num)
printf("%d is a palindrome.n", original_num);
else
printf("%d is not a palindrome.n", original_num);
return 0;
}
Input: 121 Output: 121 is a palindrome. Input: 123 Output: 123 is not a palindrome. Input: 12321 Output: 12321 is a palindrome. Input: 12345 Output: 12345 is not a palindrome. Input: 1 Output: 1 is a palindrome. Input: 0 Output: 0 is a palindrome.
