allcoding1

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📈 Analytical overview of Telegram channel allcoding1

Channel allcoding1 (@allcoding1) in the English language segment is an active participant. Currently, the community unites 22 561 subscribers, ranking 8 836 in the Education category and 19 517 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 22 561 subscribers.

According to the latest data from 13 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -442 over the last 30 days and by -20 over the last 24 hours, overall reach remains high.

Verification status: Not verified
Engagement rate (ER): The average audience engagement rate is 6.17%. Within the first 24 hours after publication, content typically collects 1.25% reactions from the total number of subscribers.
Post reach: On average, each post receives 1 394 views. Within the first day, a publication typically gains 283 views.
Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
Thematic interests: Content is focused on key topics such as dsa, stack, namaste, javascript, learning.

📝 Description and content policy

Channel description not provided.

Thanks to the high frequency of updates (latest data received on 14 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

22 561

Subscribers

-2024 hours

-897 days

-44230 days

1 394

Post views

~ 28324 hours

~ 39848 hours

6.17%

Engagement rate

No data

Posts per day

Ads index

beta

Posts Archive

22 561

#include <iostream> #include <vector> #include <unordered_map> using namespace std; const int MOD = 1e9 + 7; vector<vector<int>> tree; vector<int> a; unordered_map<int, int> countMap; bool checkPalindrome(unordered_map<int, int>& countMap) { int oddCount = 0; for (auto& it : countMap) { if (it.second % 2 != 0) oddCount++; if (oddCount > 1) return false; } return true; } int dfs(int node) { int ans = 0; countMap[a[node]]++; if (checkPalindrome(countMap)) { ans = 1; } for (auto& child : tree[node]) { ans += dfs(child); ans %= MOD; } countMap[a[node]]--; // Backtrack to remove the current node's count return ans; } int main() { int n; cin >> n; tree.resize(n + 1); a.resize(n + 1); vector<int> par(n + 1); for (int i = 2; i <= n; i++) { cin >> par[i]; tree[par[i]].push_back(i); } for (int i = 1; i <= n; i++) { cin >> a[i]; } int ans = dfs(1); cout << ans << endl; return 0; } c++ Palindromic subtrees

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Copy ur question and past you get Answer

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https://www.allcoding1.com/2023/12/allcoding1-answers.html?m=1

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https://www.allcoding1.com/2023/12/allcoding1-answers.html?m=1

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Send questions

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Maximum Count Hackwithinfy

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Gas Station Hackwithinfy

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Removable subarrays Hackwithinfy

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Repost from allcoding1

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Repost from allcoding1

📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT 100 rupees Contact:- @meterials_available

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promotions @Priya_i

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promotions @Priya_i

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Repost from allcoding1_official

I'm interest guys msg in group👇 @Deloitte_IBM_exam_Ans

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Repost from allcoding1_official

guys let's we can start business 0% investment

Anonymous voting

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Walkin interview drive for US mortgage for freshers 2023, 24, 22 yr passed out Work location - Crane Consulting firm , Kormangala, Bangalore Knowledge needed in foreclosure, bankruptcy, underwriting , 4cs Its held on April 3th wed , 4th thu - 10.30 am till 12.30 pm 220000 pa . 17,500 take home, 6 pm login / US shift Venue address -Crane Consulting , Attic Trishul 12, G, 1 & 2 Floors, 7th Cross Rd, 3rd Block, Koramangala, Bengaluru, 560034

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🎯Zoho Is Hiring Role : Software Developer Qualification:- any Batch:- any Location : Chennai Apply Now:- www.allcoding1.com Telegram:- @allcoding1

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vector<ll> babuswiggyjayega(vector<ll> a, vector<ll> b) { ll n1 = a.size(), n2 = b.size(); ll i = 0, j = 0, k = 0; vector<ll> golu(n1 + n2); while (i < n1 && j < n2) { if (a[i] < b[j]) golu[k++] = a[i++]; else golu[k++] = b[j++]; } while (i < n1) golu[k++] = a[i++]; while (j < n2) golu[k++] = b[j++]; return golu; } Merge 2 Arrays Telegram:- @allcoding1

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🎯NoBroker is hiring Role : SDE - Frontend Experience : 1 - 3 years CTC : 8 - 12 LPA Apply now :- https://hirespoof.com/job/nobroker-software-engineer-frontend/ Telegram:- @allcoding1