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#include <iostream> #include <vector> #include <algorithm> #include <climits> using namespace std; int getMaxMedian(vector<int> lower_bound, vector<int> upper_bound, long int max_sum) {     int n = lower_bound.size();     long long curr_sum = 0;     for (int i = 0; i < n; ++i) {         curr_sum += lower_bound[i] + upper_bound[i];     }     int num_elements = 2 * n;     long long target_sum = curr_sum + max_sum;     sort(upper_bound.begin(), upper_bound.end());     int median_index = num_elements / 2;     int left = 1, right = INT_MAX;     while (left <= right) {         int mid = left + (right - left) / 2;         long long sum = 0;         for (int i = 0; i < n; ++i) {             if (upper_bound[i] <= mid) {                 sum += upper_bound[i];             } else {                 sum += mid;             }         }         if (sum <= target_sum) {             left = mid + 1;         } else {             right = mid - 1;         }     }     return right; } int main() {     int n;     cin >> n;     vector<int> lower_bound(n);     vector<int> upper_bound(n);     for (int i = 0; i < n; ++i) {         cin >> lower_bound[i];     }     for (int i = 0; i < n; ++i) {         cin >> upper_bound[i];     }     long int max_sum;     cin >> max_sum;     int max_median = getMaxMedian(lower_bound, upper_bound, max_sum);     cout << max_median << endl;     return 0; } DE Shaw

#include <bits/stdc++.h> using namespace std; #define ll long long int main() {     ll n;     cin >> n;     vector<ll> v(n);     for(ll i=0; i<n; i++)         cin >> v[i];     sort(v.begin(), v.end());     ll sum = 0;     for(ll i=0; i<n; i++) {         if(sum + v[i] < 0)             return cout << -1, 0;         sum += v[i];     }     if(sum % 2 == 0)         cout << -1;     else         cout << sum;     return 0; } fortunejob

#include <iostream> using namespace std; int main() {     int e, d;     cin >> e >> d;         int mE = 0;     int mN = 0;         for (int i = 1; i <= d; i++) {         int gE = e * i;         int gN = 0;                 while (gE % 10 == 0) {             gN++;             gE /= 10;         }                 if (gN > mN) {             mN = gN;             mE = e * i;         } else if (gN == mN) {             mE = max(mE, e * i);         }     }         cout << mE << endl;         return 0; } goodenergy

#include<bits/stdc++.h> using namespace std; bool solve(char c) {     c = tolower(c);     return !(c == 'a' c == 'e' c == 'i' c == 'o' c == 'u') && c >= 'a' && c <= 'z'; } int main() {     string s;     cin >> s;     int count = 0;     for(int i = 0; i < s.length(); i += 2) {         if(solve(s[i])) {             count++;         }     }     cout << count << endl;     return 0; } Airtel Shecode anabellle @allcoding1

import java.util.Scanner; public class Solution {     public static void main(String[] args) {         Scanner sc = new Scanner(System.in);         int energy = sc.nextInt();         int maxDrink = sc.nextInt();         int maxGoodEnergy = 0;         int maxGoodNumber = 0;         for (int i = 1; i <= maxDrink; i++) {             int goodEnergy = energy * i;             int goodNumber = 0;             while (goodEnergy % 10 == 0) {                 goodNumber++;                 goodEnergy /= 10;             }             if (goodNumber > maxGoodNumber) {                 maxGoodNumber = goodNumber;                 maxGoodEnergy = energy * i;             } else if (goodNumber == maxGoodNumber) {                 maxGoodEnergy = Math.max(maxGoodEnergy, energy * i);             }         }         System.out.println(maxGoodEnergy);     } } Airtel shecode @allcoding1

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#include<bits/stdc++.h> #define ll long long using namespace std; ll solve(vector<int>a) {    set<int>s(a.begin(),a.end());    ll mex=0;     while (s.count(mex)) mex++;    ll ans=distance(s.lower_bound(mex),s.end());    if(ans==a.size()) return -2;    return ans; } int main() {     int n; cin>>n;     vector<int>arr(n);     for(int i=0;i<n;i++) cin>>arr[i];     cout<<solve(arr);     return 0; } Mex Number @allcoding1

#include <iostream> #include <vector> using namespace std; vector<int> HeightProblem(int n, vector<int>& arr) {     vector<int> ans(n);     for (int i = 0; i < n; ++i) {         int height = arr[i];         int closestLeftHeight = -1;         for (int j = i - 1; j >= 0; --j) {             if (arr[j] < height) {                 closestLeftHeight = arr[j];                 break;             }         }         ans[i] = closestLeftHeight;     }     return ans; } Height problem

#include <iostream> #include <vector> using namespace std; vector<int> HeightProblem(int n, vector<int>& arr) {     vector<int> ans(n);     for (int i = 0; i < n; ++i) {         int height = arr[i];         int closestLeftHeight = -1;         for (int j = i - 1; j >= 0; --j) {             if (arr[j] < height) {                 closestLeftHeight = arr[j];                 break;             }         }         ans[i] = closestLeftHeight;     }     return ans; } Height problem ✅

Case Changer

Money Count

Moving Average Python 3

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private static double[] calculateMovingAverage(int[] array, int K) {         double[] smoothedArray = new double[array.length - K + 1];         double sum = 0;                for (int i = 0; i < K; i++) {             sum += array[i];         }                for (int i = 0; i <= array.length - K; i++) {             if (i > 0) {                                sum = sum - array[i - 1] + array[i + K - 1];             }             smoothedArray[i] = sum / K;         }         return smoothedArray;     } Moving Averages Telegram:-

#include<bits/stdc++.h> using namespace std; int main(){     string a,b,c; cin>>a>>b>>c;     vector<int>cnt(26,0);     for(auto ele: a){         cnt[ele-'A']++;     }     for(auto ele: b){         cnt[ele-'A']++;     }     for(auto ele: c){         cnt[ele-'A']--;     }     bool flag=true;     for(auto ele: cnt){         if(ele<0) flag=false;     }     if(flag) cout<<"YES"<<endl;     else cout<<"NO"<<endl; } Magnetic Letters

#include <iostream> #include <string> using namespace std; int smallest_possible_number(const string& S) {     if (S.size() == 1 && S[0] == '0') {         return -1;     }     if (S.find('1') == string::npos) {         return -1;     }     int number = 1;     int n = S.size();     for (int i = n - 1; i >= 0; --i) {         if (S[i] == '1') {             if (number % (i + 1) != 0) {                 number *= (i + 1);             }         } else {             while (number % (i + 1) == 0) {                 number += 1;             }         }     }     return number; } Base Conversion

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🎯Agoda SDE Tech Internship 2024 Graduation Year: 2025 / 2026 Eligibility: Ongoing pursuit of a Bachelor’s or Master’s Degree in Computer Science or a related field. Internship period: July – Dec 2024 Interview process: Registration closes: 21st April 2024 Hacker rank test starts: 26th April 2024 In-office interview date: 3rd May 2024 Location: Gurugram, Haryana Apply Link: https://careersatagoda.com/job/5417820-tech-internship-2024-india-based-gurgaon-office/ Telegram:- @allcoding1