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allcoding1 (@allcoding1) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 22 561 obunachidan iborat bo'lib, Taʼlim toifasida 8 836-o'rinni va Hindiston mintaqasida 19 517-o'rinni egallagan.
📊 Auditoriya ko‘rsatkichlari va dinamika
невідомо sanasidan buyon loyiha tez o‘sib, 22 561 obunachiga ega bo‘ldi.
13 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -442 ga, so‘nggi 24 soatda esa -20 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.
- Tasdiqlash holati: Tasdiqlanmagan
- Jalb etish (ER): Auditoriya o‘rtacha 6.17% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.25% ini tashkil etuvchi reaksiyalarni to‘playdi.
- Post qamrovi: Har bir post o‘rtacha 1 394 marta ko‘riladi; birinchi sutkada odatda 283 ta ko‘rish yig‘iladi.
- Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 2 ta reaksiya keladi.
- Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, learning kabi asosiy mavzularga jamlangan.
📝 Tavsif va kontent siyosati
Kanal uchun tavsif kiritilmagan.
Yuqori yangilanish chastotasi (oxirgi ma’lumot 14 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.
22 561
Obunachilar
-2024 soatlar
-897 kunlar
-44230 kunlar
Postlar arxiv
22 561
#include <iostream>
#include <vector>
#include <unordered_map>
using namespace std;
const int MOD = 1e9 + 7;
vector<vector<int>> tree;
vector<int> a;
unordered_map<int, int> countMap;
bool checkPalindrome(unordered_map<int, int>& countMap) {
int oddCount = 0;
for (auto& it : countMap) {
if (it.second % 2 != 0) oddCount++;
if (oddCount > 1) return false;
}
return true;
}
int dfs(int node) {
int ans = 0;
countMap[a[node]]++;
if (checkPalindrome(countMap)) {
ans = 1;
}
for (auto& child : tree[node]) {
ans += dfs(child);
ans %= MOD;
}
countMap[a[node]]--; // Backtrack to remove the current node's count
return ans;
}
int main() {
int n;
cin >> n;
tree.resize(n + 1);
a.resize(n + 1);
vector<int> par(n + 1);
for (int i = 2; i <= n; i++) {
cin >> par[i];
tree[par[i]].push_back(i);
}
for (int i = 1; i <= n; i++) {
cin >> a[i];
}
int ans = dfs(1);
cout << ans << endl;
return 0;
}
c++
Palindromic subtrees
22 561
Repost from allcoding1
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22 561
Repost from allcoding1
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22 561
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22 561
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22 561
vector<ll> babuswiggyjayega(vector<ll> a, vector<ll> b)
{
ll n1 = a.size(), n2 = b.size();
ll i = 0, j = 0, k = 0;
vector<ll> golu(n1 + n2);
while (i < n1 && j < n2)
{
if (a[i] < b[j])
golu[k++] = a[i++];
else
golu[k++] = b[j++];
}
while (i < n1)
golu[k++] = a[i++];
while (j < n2)
golu[k++] = b[j++];
return golu;
}
Merge 2 Arrays
Telegram:- @allcoding1
22 561
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