allcoding1
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š Analytical overview of Telegram channel allcoding1
Channel allcoding1 (@allcoding1) in the English language segment is an active participant. Currently, the community unites 21 559 subscribers, ranking 9 073 in the Education category and 19 010 in the India region.
š Audience metrics and dynamics
Since its creation on Š½ŠµŠ²ŃŠ“Š¾Š¼Š¾, the project has demonstrated rapid growth, gathering an audience of 21 559 subscribers.
According to the latest data from 30 August, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -372 over the last 30 days and by -25 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 6.68%. Within the first 24 hours after publication, content typically collects N/A% reactions from the total number of subscribers.
- Post reach: On average, each post receives 1 441 views. Within the first day, a publication typically gains 0 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 0.
- Thematic interests: Content is focused on key topics such as dsa, stack, namaste, javascript, learning.
š Description and content policy
Channel description not provided.
Thanks to the high frequency of updates (latest data received on 31 August, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.
21 559
Subscribers
-2524 hours
-867 days
-37230 days
Posts Archive
21 559
int num1, num2;
cin >> num1 >> num2;
int sum = num1 + num2;
cout << num1 << " + " << num2 << " = " << sum << endl;
C++
Telegram:- @allcoding1
21 559
Accenture exam Answer 2/4/24
@allcoding1
1) I got sick, I have _
As) an
2) A) but everyone
B) government
C) an should
D) global..
As) DBAC
3) ocean : shallow
As) infinite
4) I comb my hair....
As) I used to
5) antonym word " ACCURATE "
As) invalid
6) Continue
As) prolong
7) we felt____missing the farewell party
As) didn't feel good
@allcoding1
8) horizontal bar represent
As) date input/output
9) charvi is the mother of sara...
As) sister in law
10) by the time we arrived they____ (to leave)
As) had left
11) 1) it is possible to determine....
2) no other mobile brand....
As) both conclusion follow
Telegram:- @allcoding1
21 559
Accenture exam Answer 2/4/24
Accenture exam Answer 2/4/24
1) I got sick, I have _
As) an
2) A) but everyone
B) government
C) an should
D) global..
As) DBAC
3) ocean : shallow
As) infinite
4) I comb my hair....
As) I used to
5) antonym word " ACCURATE "
As) invalid
6) Continue
As) prolong
7) we felt____missing the farewell party
As) didn't feel good
@allcoding1_official
8) horizontal bar represent
As) date input/output
9) charvi is the mother of sara...
As) sister in law
10) by the time we arrived they____ (to leave)
As) had left
11) 1) it is possible to determine....
2) no other mobile brand....
As) both conclusion follow
Telegram:- @allcoding1
1) I got sick, I have _
As) an
2) A) but everyone
B) government
C) an should
D) global..
As) DBAC
3) ocean : shallow
As) infinite
4) I comb my hair....
As) I used to
5) antonym word " ACCURATE "
As) invalid
6) Continue
As) prolong
7) we felt____missing the farewell party
As) didn't feel good
@allcoding1
8) horizontal bar represent
As) date input/output
9) charvi is the mother of sara...
As) sister in law
10) by the time we arrived they____ (to leave)
As) had left
11) 1) it is possible to determine....
2) no other mobile brand....
As) both conclusion follow
Telegram:- @allcoding1
21 559
#include<bits/stdc++.h>
using namespace std;
typedef long long LL;
#define max_v 25
bool f(double A,double B,double a,double b)
{
double d=sqrt(a*a+b*b);
double a1=asin(A/d);
double a2=asin(b/d)*2.0;
double h=cos(a1-a2)*d;
if(B>h)
return true;
else
return false;
}
int main()
{
int t;
bool flag;
cin >> t;
while(t--)
{
double A,B,a,b;
cin >> A >> B >> a >> b;
if(A<B)
swap(A,B);
if(a<b)
swap(a,b);
if(A>a&&B>b)
{
flag=true;
}
else if(A*B<=a*b||b>=B)
{
flag=false;
}else
{
flag=f(A,B,a,b);
}
if(flag)
{
cout << "Escape is possible." << endl;
}else
{
cout << "Box cannot be dropped." << endl;
}
}
return 0;
}
INFAthon 4.0
Telegram:- @allcoding1
21 559
+1
int main()
{
string text;
getline(cin, text);
int index = 0;
while (index + 13 < text.length() && (index = text.rfind(" ", index + 13)) != string::npos) {
text.replace(index, 1, "\n");
}
cout << text << endl;
return 0;
}
INFA thon 4.0
21 559
+8
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