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📈 Telegram 频道 allcoding1 的分析概览

频道 allcoding1 (@allcoding1) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 22 561 名订阅者,在 教育 类别中位列第 8 836,并在 印度 地区排名第 19 517

📊 受众指标与增长动态

невідомо 创建以来,项目保持高速增长,吸引了 22 561 名订阅者。

根据 13 六月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -442,过去 24 小时变化为 -20,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 6.17%。内容发布后 24 小时内通常能获得 1.25% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 1 394 次浏览,首日通常累积 283 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 2
  • 主题关注点: 内容集中在 dsa, stack, namaste, javascript, learning 等核心主题上。

📝 描述与内容策略

尚未提供频道描述。

凭借高频更新(最新数据采集于 14 六月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 教育 类别中的关键影响点。

22 561
订阅者
-2024 小时
-897
-44230
帖子存档
#include #include using namespace std; vector HeightProblem(int n, vector& arr) {     vector ans(n); &nbsp
#include <iostream> #include <vector> using namespace std; vector<int> HeightProblem(int n, vector<int>& arr) {     vector<int> ans(n);     for (int i = 0; i < n; ++i) {         int height = arr[i];         int closestLeftHeight = -1;         for (int j = i - 1; j >= 0; --j) {             if (arr[j] < height) {                 closestLeftHeight = arr[j];                 break;             }         }         ans[i] = closestLeftHeight;     }     return ans; } Height problem

#include <iostream> #include <vector> using namespace std; vector<int> HeightProblem(int n, vector<int>& arr) {     vector<int> ans(n);     for (int i = 0; i < n; ++i) {         int height = arr[i];         int closestLeftHeight = -1;         for (int j = i - 1; j >= 0; --j) {             if (arr[j] < height) {                 closestLeftHeight = arr[j];                 break;             }         }         ans[i] = closestLeftHeight;     }     return ans; } Height problem ✅

Case Changer
Case Changer

Money Count
Money Count

Moving Average Python 3
Moving Average Python 3

Repost from allcoding1_official
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private static double[] calculateMovingAverage(int[] array, int K) { &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; double[] smoo
private static double[] calculateMovingAverage(int[] array, int K) {         double[] smoothedArray = new double[array.length - K + 1];         double sum = 0;                for (int i = 0; i < K; i++) {             sum += array[i];         }                for (int i = 0; i <= array.length - K; i++) {             if (i > 0) {                                sum = sum - array[i - 1] + array[i + K - 1];             }             smoothedArray[i] = sum / K;         }         return smoothedArray;     } Moving Averages Telegram:-

#include using namespace std; int main(){ &nbsp;&nbsp;&nbsp; string a,b,c; cin&gt;&gt;a&gt;&gt;b&gt;&gt;c; &nbsp;&nbsp;&nbsp;
#include<bits/stdc++.h> using namespace std; int main(){     string a,b,c; cin>>a>>b>>c;     vector<int>cnt(26,0);     for(auto ele: a){         cnt[ele-'A']++;     }     for(auto ele: b){         cnt[ele-'A']++;     }     for(auto ele: c){         cnt[ele-'A']--;     }     bool flag=true;     for(auto ele: cnt){         if(ele<0) flag=false;     }     if(flag) cout<<"YES"<<endl;     else cout<<"NO"<<endl; } Magnetic Letters

#include #include using namespace std; int smallest_possible_number(const string&amp; S) { &nbsp;&nbsp;&nbsp; if (S.size() ==
#include <iostream> #include <string> using namespace std; int smallest_possible_number(const string& S) {     if (S.size() == 1 && S[0] == '0') {         return -1;     }     if (S.find('1') == string::npos) {         return -1;     }     int number = 1;     int n = S.size();     for (int i = n - 1; i >= 0; --i) {         if (S[i] == '1') {             if (number % (i + 1) != 0) {                 number *= (i + 1);             }         } else {             while (number % (i + 1) == 0) {                 number += 1;             }         }     }     return number; } Base Conversion

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def processExecution(power, minPower, maxPower): &nbsp;&nbsp;&nbsp; result = [] &nbsp;&nbsp;&nbsp; for min_p, max_p in zip(mi
def processExecution(power, minPower, maxPower):     result = []     for min_p, max_p in zip(minPower, maxPower):         count = sum(1 for p in power if min_p <= p <= max_p)         power_sum = sum(p for p in power if min_p <= p <= max_p)         result.append((count, power_sum))     return result Amazon

photo content
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#include <iostream> #include <vector> #include <string> using namespace std; int count_vowels(string str) {     int count = 0;     string vowels = "aeiou";     for (char ch : str) {         if (vowels.find(tolower(ch)) != string::npos) {             count++;         }     }     return count; } vector<string> determine_winner(vector<string> strings) {     vector<string> winners;     for (string str : strings) {         if (count_vowels(str) == 0) {             winners.push_back("Chris");         } else {             winners.push_back("Alex");         }     }     return winners; }.  System and Strings JPMC Telegram:- @allcoding1

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