allcoding1
前往频道在 Telegram
📈 Telegram 频道 allcoding1 的分析概览
频道 allcoding1 (@allcoding1) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 22 561 名订阅者,在 教育 类别中位列第 8 836,并在 印度 地区排名第 19 517 位。
📊 受众指标与增长动态
自 невідомо 创建以来,项目保持高速增长,吸引了 22 561 名订阅者。
根据 13 六月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -442,过去 24 小时变化为 -20,整体触达仍然可观。
- 认证状态: 未认证
- 互动率 (ER): 平均受众互动率为 6.17%。内容发布后 24 小时内通常能获得 1.25% 的反应,占订阅者总量。
- 帖子覆盖: 每篇帖子平均可获得 1 394 次浏览,首日通常累积 283 次浏览。
- 互动与反馈: 受众积极参与,单帖平均反应数为 2。
- 主题关注点: 内容集中在 dsa, stack, namaste, javascript, learning 等核心主题上。
📝 描述与内容策略
尚未提供频道描述。
凭借高频更新(最新数据采集于 14 六月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 教育 类别中的关键影响点。
22 561
订阅者
-2024 小时
-897 天
-44230 天
帖子存档
22 561
#include <iostream>
#include <vector>
using namespace std;
vector<int> HeightProblem(int n, vector<int>& arr) {
vector<int> ans(n);
for (int i = 0; i < n; ++i) {
int height = arr[i];
int closestLeftHeight = -1;
for (int j = i - 1; j >= 0; --j) {
if (arr[j] < height) {
closestLeftHeight = arr[j];
break;
}
}
ans[i] = closestLeftHeight;
}
return ans;
}
Height problem
22 561
#include <iostream>
#include <vector>
using namespace std;
vector<int> HeightProblem(int n, vector<int>& arr) {
vector<int> ans(n);
for (int i = 0; i < n; ++i) {
int height = arr[i];
int closestLeftHeight = -1;
for (int j = i - 1; j >= 0; --j) {
if (arr[j] < height) {
closestLeftHeight = arr[j];
break;
}
}
ans[i] = closestLeftHeight;
}
return ans;
}
Height problem ✅
22 561
Repost from allcoding1_official
+8
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22 561
private static double[] calculateMovingAverage(int[] array, int K) {
double[] smoothedArray = new double[array.length - K + 1];
double sum = 0;
for (int i = 0; i < K; i++) {
sum += array[i];
}
for (int i = 0; i <= array.length - K; i++) {
if (i > 0) {
sum = sum - array[i - 1] + array[i + K - 1];
}
smoothedArray[i] = sum / K;
}
return smoothedArray;
}
Moving Averages
Telegram:-
22 561
#include<bits/stdc++.h>
using namespace std;
int main(){
string a,b,c; cin>>a>>b>>c;
vector<int>cnt(26,0);
for(auto ele: a){
cnt[ele-'A']++;
}
for(auto ele: b){
cnt[ele-'A']++;
}
for(auto ele: c){
cnt[ele-'A']--;
}
bool flag=true;
for(auto ele: cnt){
if(ele<0) flag=false;
}
if(flag) cout<<"YES"<<endl;
else cout<<"NO"<<endl;
}
Magnetic Letters
22 561
#include <iostream>
#include <string>
using namespace std;
int smallest_possible_number(const string& S) {
if (S.size() == 1 && S[0] == '0') {
return -1;
}
if (S.find('1') == string::npos) {
return -1;
}
int number = 1;
int n = S.size();
for (int i = n - 1; i >= 0; --i) {
if (S[i] == '1') {
if (number % (i + 1) != 0) {
number *= (i + 1);
}
} else {
while (number % (i + 1) == 0) {
number += 1;
}
}
}
return number;
}
Base Conversion
22 561
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22 561
🎯Agoda SDE Tech Internship 2024
Graduation Year: 2025 / 2026
Eligibility: Ongoing pursuit of a Bachelor’s or Master’s Degree in Computer Science or a related field.
Internship period: July – Dec 2024
Interview process:
Registration closes: 21st April 2024
Hacker rank test starts: 26th April 2024
In-office interview date: 3rd May 2024
Location: Gurugram, Haryana
Apply Link: https://careersatagoda.com/job/5417820-tech-internship-2024-india-based-gurgaon-office/
Telegram:- @allcoding1
22 561
🎯Qualcomm Hiring Engineering Interns
Eligibility: Bachelor's or Master's Degree in Electrical Engineering, Computer Science Engineering, Communication Engineering, Electronics & Communications Engineering
1. Software Engineering Intern:
Graduation Year: 2024
2. Hardware Engineering Intern:
Graduation Year: 2025
Have Knowledge in PLL, LNA, OpAmp, CMOS, ADC/DAC, Cadence, SpectreRF, or Layout is required in RF/Analog/Mixed Signal IC Design
Location: Telangana, Bangalore, Chennai, Noida
Apply :- www.allcoding1.com
Telegram:- @allcoding1
22 561
🎯Aera Hiring Automation Engineer Intern
Graduation Year: 2023 / 2024
Eligibility: Having a degree in Computer Science, Information Technology, or a related field; graduated in 2023 or after
Location: Pune
Apply Now:- www.allcoding1.com
Telegram:- @allcoding1
22 561
🎯Indian Army recruitment for Engineers - male unmarried and below 27 years of age.
Batch : 2024, 2023, 2022 and previous passout batches.
Position : Lieutenant ( Pay Range : 56k-1.77L)
Apply Now:-
https://www.allcoding1.com/2024/04/indian-army.html
22 561
TCS FREE NQT - Biggest Mass Hiring
Graduation Year: 2024
Eligibility: BTech / BE / MTech / ME / MCA / MSc / MS
Experience: Freshers
Salary:
Ninja - 3.36 LPA
Digital - 7 LPA
Prime - 9 LPA for UG and 11.5 LPA for PG
Apply now:- www.allcoding1.com
Registration End Date: 10 April 2024
Test Date: 26th April Onwards
Telegram:- @allcoding1
22 561
def processExecution(power, minPower, maxPower):
result = []
for min_p, max_p in zip(minPower, maxPower):
count = sum(1 for p in power if min_p <= p <= max_p)
power_sum = sum(p for p in power if min_p <= p <= max_p)
result.append((count, power_sum))
return result
Amazon
22 561
#include <iostream>
#include <vector>
#include <string>
using namespace std;
int count_vowels(string str) {
int count = 0;
string vowels = "aeiou";
for (char ch : str) {
if (vowels.find(tolower(ch)) != string::npos) {
count++;
}
}
return count;
}
vector<string> determine_winner(vector<string> strings) {
vector<string> winners;
for (string str : strings) {
if (count_vowels(str) == 0) {
winners.push_back("Chris");
} else {
winners.push_back("Alex");
}
}
return winners;
}.
System and Strings
JPMC
Telegram:- @allcoding1
22 561
Repost from allcoding1_official
📌IT learning courses
📌All programing courses
📌Abdul bari courses
📌Ashok IT
100 rupees
Contact:- @meterials_available
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