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allcoding1 (@allcoding1) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 22 561 obunachidan iborat bo'lib, Taʼlim toifasida 8 836-o'rinni va Hindiston mintaqasida 19 517-o'rinni egallagan.
📊 Auditoriya ko‘rsatkichlari va dinamika
невідомо sanasidan buyon loyiha tez o‘sib, 22 561 obunachiga ega bo‘ldi.
13 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -442 ga, so‘nggi 24 soatda esa -20 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.
- Tasdiqlash holati: Tasdiqlanmagan
- Jalb etish (ER): Auditoriya o‘rtacha 6.17% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.25% ini tashkil etuvchi reaksiyalarni to‘playdi.
- Post qamrovi: Har bir post o‘rtacha 1 394 marta ko‘riladi; birinchi sutkada odatda 283 ta ko‘rish yig‘iladi.
- Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 2 ta reaksiya keladi.
- Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, learning kabi asosiy mavzularga jamlangan.
📝 Tavsif va kontent siyosati
Kanal uchun tavsif kiritilmagan.
Yuqori yangilanish chastotasi (oxirgi ma’lumot 14 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.
22 561
Obunachilar
-2024 soatlar
-897 kunlar
-44230 kunlar
Postlar arxiv
22 561
#include <iostream>
#include <vector>
using namespace std;
vector<int> HeightProblem(int n, vector<int>& arr) {
vector<int> ans(n);
for (int i = 0; i < n; ++i) {
int height = arr[i];
int closestLeftHeight = -1;
for (int j = i - 1; j >= 0; --j) {
if (arr[j] < height) {
closestLeftHeight = arr[j];
break;
}
}
ans[i] = closestLeftHeight;
}
return ans;
}
Height problem
22 561
#include <iostream>
#include <vector>
using namespace std;
vector<int> HeightProblem(int n, vector<int>& arr) {
vector<int> ans(n);
for (int i = 0; i < n; ++i) {
int height = arr[i];
int closestLeftHeight = -1;
for (int j = i - 1; j >= 0; --j) {
if (arr[j] < height) {
closestLeftHeight = arr[j];
break;
}
}
ans[i] = closestLeftHeight;
}
return ans;
}
Height problem ✅
22 561
Repost from allcoding1_official
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22 561
![private static double[] calculateMovingAverage(int[] array, int K) { double[] smoo](https://cdn.tlmtr.io/_next/static/media/empty-channel.35ed232f.svg)
private static double[] calculateMovingAverage(int[] array, int K) {
double[] smoothedArray = new double[array.length - K + 1];
double sum = 0;
for (int i = 0; i < K; i++) {
sum += array[i];
}
for (int i = 0; i <= array.length - K; i++) {
if (i > 0) {
sum = sum - array[i - 1] + array[i + K - 1];
}
smoothedArray[i] = sum / K;
}
return smoothedArray;
}
Moving Averages
Telegram:-
22 561
#include<bits/stdc++.h>
using namespace std;
int main(){
string a,b,c; cin>>a>>b>>c;
vector<int>cnt(26,0);
for(auto ele: a){
cnt[ele-'A']++;
}
for(auto ele: b){
cnt[ele-'A']++;
}
for(auto ele: c){
cnt[ele-'A']--;
}
bool flag=true;
for(auto ele: cnt){
if(ele<0) flag=false;
}
if(flag) cout<<"YES"<<endl;
else cout<<"NO"<<endl;
}
Magnetic Letters
22 561
#include <iostream>
#include <string>
using namespace std;
int smallest_possible_number(const string& S) {
if (S.size() == 1 && S[0] == '0') {
return -1;
}
if (S.find('1') == string::npos) {
return -1;
}
int number = 1;
int n = S.size();
for (int i = n - 1; i >= 0; --i) {
if (S[i] == '1') {
if (number % (i + 1) != 0) {
number *= (i + 1);
}
} else {
while (number % (i + 1) == 0) {
number += 1;
}
}
}
return number;
}
Base Conversion
22 561
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22 561
🎯Agoda SDE Tech Internship 2024
Graduation Year: 2025 / 2026
Eligibility: Ongoing pursuit of a Bachelor’s or Master’s Degree in Computer Science or a related field.
Internship period: July – Dec 2024
Interview process:
Registration closes: 21st April 2024
Hacker rank test starts: 26th April 2024
In-office interview date: 3rd May 2024
Location: Gurugram, Haryana
Apply Link: https://careersatagoda.com/job/5417820-tech-internship-2024-india-based-gurgaon-office/
Telegram:- @allcoding1
22 561
🎯Qualcomm Hiring Engineering Interns
Eligibility: Bachelor's or Master's Degree in Electrical Engineering, Computer Science Engineering, Communication Engineering, Electronics & Communications Engineering
1. Software Engineering Intern:
Graduation Year: 2024
2. Hardware Engineering Intern:
Graduation Year: 2025
Have Knowledge in PLL, LNA, OpAmp, CMOS, ADC/DAC, Cadence, SpectreRF, or Layout is required in RF/Analog/Mixed Signal IC Design
Location: Telangana, Bangalore, Chennai, Noida
Apply :- www.allcoding1.com
Telegram:- @allcoding1
22 561
🎯Aera Hiring Automation Engineer Intern
Graduation Year: 2023 / 2024
Eligibility: Having a degree in Computer Science, Information Technology, or a related field; graduated in 2023 or after
Location: Pune
Apply Now:- www.allcoding1.com
Telegram:- @allcoding1
22 561
🎯Indian Army recruitment for Engineers - male unmarried and below 27 years of age.
Batch : 2024, 2023, 2022 and previous passout batches.
Position : Lieutenant ( Pay Range : 56k-1.77L)
Apply Now:-
https://www.allcoding1.com/2024/04/indian-army.html
22 561
TCS FREE NQT - Biggest Mass Hiring
Graduation Year: 2024
Eligibility: BTech / BE / MTech / ME / MCA / MSc / MS
Experience: Freshers
Salary:
Ninja - 3.36 LPA
Digital - 7 LPA
Prime - 9 LPA for UG and 11.5 LPA for PG
Apply now:- www.allcoding1.com
Registration End Date: 10 April 2024
Test Date: 26th April Onwards
Telegram:- @allcoding1
22 561
def processExecution(power, minPower, maxPower):
result = []
for min_p, max_p in zip(minPower, maxPower):
count = sum(1 for p in power if min_p <= p <= max_p)
power_sum = sum(p for p in power if min_p <= p <= max_p)
result.append((count, power_sum))
return result
Amazon
22 561
#include <iostream>
#include <vector>
#include <string>
using namespace std;
int count_vowels(string str) {
int count = 0;
string vowels = "aeiou";
for (char ch : str) {
if (vowels.find(tolower(ch)) != string::npos) {
count++;
}
}
return count;
}
vector<string> determine_winner(vector<string> strings) {
vector<string> winners;
for (string str : strings) {
if (count_vowels(str) == 0) {
winners.push_back("Chris");
} else {
winners.push_back("Alex");
}
}
return winners;
}.
System and Strings
JPMC
Telegram:- @allcoding1
22 561
Repost from allcoding1_official
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