allcoding1

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proofs👇 https://t.me/+mP2YTsMihZozNWQ1

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📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources English , 🇫🇷 All courses (100 rupees) Contact:- @meterials_available

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📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources English , 🇫🇷 100 rupees Contact:- @meterials_available

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📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources English , 🇫🇷 100 rupees Contact:- @meterials_available

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Exam Ans:- @allcoding1 Jobs post:- @allcoding1_official

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Salesperson ID's - IBM

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Lexicographical smallest substring - IBM

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def max_call_executives(n, start_times, end_times): timeline = [0] * (24 * 60 + 1) for i in range(n): start = int(start_times[i][:2]) * 60 + int(start_times[i][2:]) end = int(end_times[i][:2]) * 60 + int(end_times[i][2:]) timeline[start] += 1 timeline[end] -= 1 max_executives = 0 current_executives = 0 for i in range(len(timeline)): current_executives += timeline[i] max_executives = max(max_executives, current_executives) return max_executives Call Centre

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import heapq def distance(x, y): return x*x + y*y def nearest_houses(P, T, queries): distances = [] heapq.heapify(distances) for query in queries: if query[0] == 1: x, y = query[1], query[2] heapq.heappush(distances, distance(x, y)) else: nearest = heapq.nsmallest(T, distances)[-1] print(nearest) Nearest House

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#include <iostream> #include <vector> using namespace std; const int MOD = 1e9 + 7; int F(int i, int k, int n, vector<int> &level, vector<int> &dp) { if (i == n) return 1; if (dp[i] != -1) return dp[i]; int ans = 0, odds = 0; vector<int> hash(n + 10, 0); for (int j = i; j < n; j++) { if (++hash[level[j]] % 2 == 0) odds -= 1; else odds += 1; if (odds <= k) { ans = (ans + F(j + 1, k, n, level, dp)) % MOD; } } return dp[i] = ans; } int countValidPartitions(vector<int> level, int k) { int n = level.size(); vector<int> dp(n, -1); return F(0, k, n, level, dp); } DE Shaw

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#include <iostream> #include <vector> #include <algorithm> #include <climits> using namespace std; int getMaxMedian(vector<int> lower_bound, vector<int> upper_bound, long int max_sum) { int n = lower_bound.size(); long long curr_sum = 0; for (int i = 0; i < n; ++i) { curr_sum += lower_bound[i] + upper_bound[i]; } int num_elements = 2 * n; long long target_sum = curr_sum + max_sum; sort(upper_bound.begin(), upper_bound.end()); int median_index = num_elements / 2; int left = 1, right = INT_MAX; while (left <= right) { int mid = left + (right - left) / 2; long long sum = 0; for (int i = 0; i < n; ++i) { if (upper_bound[i] <= mid) { sum += upper_bound[i]; } else { sum += mid; } } if (sum <= target_sum) { left = mid + 1; } else { right = mid - 1; } } return right; } int main() { int n; cin >> n; vector<int> lower_bound(n); vector<int> upper_bound(n); for (int i = 0; i < n; ++i) { cin >> lower_bound[i]; } for (int i = 0; i < n; ++i) { cin >> upper_bound[i]; } long int max_sum; cin >> max_sum; int max_median = getMaxMedian(lower_bound, upper_bound, max_sum); cout << max_median << endl; return 0; } DE Shaw

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+1

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#include <bits/stdc++.h> using namespace std; #define ll long long int main() { ll n; cin >> n; vector<ll> v(n); for(ll i=0; i<n; i++) cin >> v[i]; sort(v.begin(), v.end()); ll sum = 0; for(ll i=0; i<n; i++) { if(sum + v[i] < 0) return cout << -1, 0; sum += v[i]; } if(sum % 2 == 0) cout << -1; else cout << sum; return 0; } fortunejob

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#include <iostream> using namespace std; int main() { int e, d; cin >> e >> d; int mE = 0; int mN = 0; for (int i = 1; i <= d; i++) { int gE = e * i; int gN = 0; while (gE % 10 == 0) { gN++; gE /= 10; } if (gN > mN) { mN = gN; mE = e * i; } else if (gN == mN) { mE = max(mE, e * i); } } cout << mE << endl; return 0; } goodenergy

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#include<bits/stdc++.h> using namespace std; bool solve(char c) { c = tolower(c); return !(c == 'a' c == 'e' c == 'i' c == 'o' c == 'u') && c >= 'a' && c <= 'z'; } int main() { string s; cin >> s; int count = 0; for(int i = 0; i < s.length(); i += 2) { if(solve(s[i])) { count++; } } cout << count << endl; return 0; } Airtel Shecode anabellle @allcoding1

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import java.util.Scanner; public class Solution { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int energy = sc.nextInt(); int maxDrink = sc.nextInt(); int maxGoodEnergy = 0; int maxGoodNumber = 0; for (int i = 1; i <= maxDrink; i++) { int goodEnergy = energy * i; int goodNumber = 0; while (goodEnergy % 10 == 0) { goodNumber++; goodEnergy /= 10; } if (goodNumber > maxGoodNumber) { maxGoodNumber = goodNumber; maxGoodEnergy = energy * i; } else if (goodNumber == maxGoodNumber) { maxGoodEnergy = Math.max(maxGoodEnergy, energy * i); } } System.out.println(maxGoodEnergy); } } Airtel shecode @allcoding1

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📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources English , 🇫🇷 100 rupees Contact:- @meterials_available

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📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources English , 🇫🇷 100 rupees Contact:- @meterials_available

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#include<bits/stdc++.h> #define ll long long using namespace std; ll solve(vector<int>a) { set<int>s(a.begin(),a.end()); ll mex=0; while (s.count(mex)) mex++; ll ans=distance(s.lower_bound(mex),s.end()); if(ans==a.size()) return -2; return ans; } int main() { int n; cin>>n; vector<int>arr(n); for(int i=0;i<n;i++) cin>>arr[i]; cout<<solve(arr); return 0; } Mex Number @allcoding1

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