uz
Feedback
allcoding1

allcoding1

Kanalga Telegram’da o‘tish

Ko'proq ko'rsatish

📈 Telegram kanali allcoding1 analitikasi

allcoding1 (@allcoding1) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 22 561 obunachidan iborat bo'lib, Taʼlim toifasida 8 836-o'rinni va Hindiston mintaqasida 19 517-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 22 561 obunachiga ega bo‘ldi.

13 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -442 ga, so‘nggi 24 soatda esa -20 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 6.17% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.25% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 1 394 marta ko‘riladi; birinchi sutkada odatda 283 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 2 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, learning kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Kanal uchun tavsif kiritilmagan.

Yuqori yangilanish chastotasi (oxirgi ma’lumot 14 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

22 561
Obunachilar
-2024 soatlar
-897 kunlar
-44230 kunlar
Postlar arxiv

Repost from allcoding1_official
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Work
+8
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources English , 🇫🇷 All courses (100 rupees) Contact:- @meterials_available

Repost from allcoding1_official
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Work
+8
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources English , 🇫🇷 100 rupees Contact:- @meterials_available

Repost from allcoding1_official
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Work
+8
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources English , 🇫🇷 100 rupees Contact:- @meterials_available

Exam Ans:- @allcoding1 Jobs post:- @allcoding1_official

Salesperson ID's - IBM
Salesperson ID's - IBM

Lexicographical smallest substring - IBM
Lexicographical smallest substring - IBM

def max_call_executives(n, start_times, end_times): timeline = [0] * (24 * 60 + 1) for i in range(n): start = int(start_times
def max_call_executives(n, start_times, end_times):     timeline = [0] * (24 * 60 + 1)         for i in range(n):         start = int(start_times[i][:2]) * 60 + int(start_times[i][2:])         end = int(end_times[i][:2]) * 60 + int(end_times[i][2:])         timeline[start] += 1         timeline[end] -= 1         max_executives = 0     current_executives = 0     for i in range(len(timeline)):         current_executives += timeline[i]         max_executives = max(max_executives, current_executives)         return max_executives Call Centre

import heapq def distance(x, y): return x*x + y*y def nearest_houses(P, T, queries): distances = [] heapq.heapify(distances)
import heapq def distance(x, y):     return x*x + y*y def nearest_houses(P, T, queries):     distances = []     heapq.heapify(distances)     for query in queries:         if query[0] == 1:             x, y = query[1], query[2]             heapq.heappush(distances, distance(x, y))         else:             nearest = heapq.nsmallest(T, distances)[-1]             print(nearest) Nearest House

Repost from allcoding1_official
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Work
+8
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources English , 🇫🇷 100 rupees Contact:- @meterials_available

#include #include using namespace std; const int MOD = 1e9 + 7; int F(int i, int k, int n, vector &level, vector &dp)
#include <iostream> #include <vector> using namespace std; const int MOD = 1e9 + 7; int F(int i, int k, int n, vector<int> &level, vector<int> &dp) {     if (i == n) return 1;     if (dp[i] != -1) return dp[i];     int ans = 0, odds = 0;     vector<int> hash(n + 10, 0);     for (int j = i; j < n; j++) {         if (++hash[level[j]] % 2 == 0) odds -= 1;         else odds += 1;         if (odds <= k) {             ans = (ans + F(j + 1, k, n, level, dp)) % MOD;         }     }     return dp[i] = ans; } int countValidPartitions(vector<int> level, int k) {     int n = level.size();     vector<int> dp(n, -1);     return F(0, k, n, level, dp); } DE Shaw

#include <iostream> #include <vector> #include <algorithm> #include <climits> using namespace std; int getMaxMedian(vector<int> lower_bound, vector<int> upper_bound, long int max_sum) {     int n = lower_bound.size();     long long curr_sum = 0;     for (int i = 0; i < n; ++i) {         curr_sum += lower_bound[i] + upper_bound[i];     }     int num_elements = 2 * n;     long long target_sum = curr_sum + max_sum;     sort(upper_bound.begin(), upper_bound.end());     int median_index = num_elements / 2;     int left = 1, right = INT_MAX;     while (left <= right) {         int mid = left + (right - left) / 2;         long long sum = 0;         for (int i = 0; i < n; ++i) {             if (upper_bound[i] <= mid) {                 sum += upper_bound[i];             } else {                 sum += mid;             }         }         if (sum <= target_sum) {             left = mid + 1;         } else {             right = mid - 1;         }     }     return right; } int main() {     int n;     cin >> n;     vector<int> lower_bound(n);     vector<int> upper_bound(n);     for (int i = 0; i < n; ++i) {         cin >> lower_bound[i];     }     for (int i = 0; i < n; ++i) {         cin >> upper_bound[i];     }     long int max_sum;     cin >> max_sum;     int max_median = getMaxMedian(lower_bound, upper_bound, max_sum);     cout << max_median << endl;     return 0; } DE Shaw

photo content
+1

#include <bits/stdc++.h> using namespace std; #define ll long long int main() {     ll n;     cin >> n;     vector<ll> v(n);     for(ll i=0; i<n; i++)         cin >> v[i];     sort(v.begin(), v.end());     ll sum = 0;     for(ll i=0; i<n; i++) {         if(sum + v[i] < 0)             return cout << -1, 0;         sum += v[i];     }     if(sum % 2 == 0)         cout << -1;     else         cout << sum;     return 0; } fortunejob

#include <iostream> using namespace std; int main() {     int e, d;     cin >> e >> d;         int mE = 0;     int mN = 0;         for (int i = 1; i <= d; i++) {         int gE = e * i;         int gN = 0;                 while (gE % 10 == 0) {             gN++;             gE /= 10;         }                 if (gN > mN) {             mN = gN;             mE = e * i;         } else if (gN == mN) {             mE = max(mE, e * i);         }     }         cout << mE << endl;         return 0; } goodenergy

#include<bits/stdc++.h> using namespace std; bool solve(char c) {     c = tolower(c);     return !(c == 'a' c == 'e' c == 'i' c == 'o' c == 'u') && c >= 'a' && c <= 'z'; } int main() {     string s;     cin >> s;     int count = 0;     for(int i = 0; i < s.length(); i += 2) {         if(solve(s[i])) {             count++;         }     }     cout << count << endl;     return 0; } Airtel Shecode anabellle @allcoding1

import java.util.Scanner; public class Solution {     public static void main(String[] args) {         Scanner sc = new Scanner(System.in);         int energy = sc.nextInt();         int maxDrink = sc.nextInt();         int maxGoodEnergy = 0;         int maxGoodNumber = 0;         for (int i = 1; i <= maxDrink; i++) {             int goodEnergy = energy * i;             int goodNumber = 0;             while (goodEnergy % 10 == 0) {                 goodNumber++;                 goodEnergy /= 10;             }             if (goodNumber > maxGoodNumber) {                 maxGoodNumber = goodNumber;                 maxGoodEnergy = energy * i;             } else if (goodNumber == maxGoodNumber) {                 maxGoodEnergy = Math.max(maxGoodEnergy, energy * i);             }         }         System.out.println(maxGoodEnergy);     } } Airtel shecode @allcoding1

Repost from allcoding1_official
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Work
+8
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources English , 🇫🇷 100 rupees Contact:- @meterials_available

Repost from allcoding1_official
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Work
+8
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources English , 🇫🇷 100 rupees Contact:- @meterials_available

#include<bits/stdc++.h> #define ll long long using namespace std; ll solve(vector<int>a) {    set<int>s(a.begin(),a.end());    ll mex=0;     while (s.count(mex)) mex++;    ll ans=distance(s.lower_bound(mex),s.end());    if(ans==a.size()) return -2;    return ans; } int main() {     int n; cin>>n;     vector<int>arr(n);     for(int i=0;i<n;i++) cin>>arr[i];     cout<<solve(arr);     return 0; } Mex Number @allcoding1