LTM EXAM SOLUTIONS

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🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

India28 127 Education14 118...

📈 Analytical overview of Telegram channel LTM EXAM SOLUTIONS

Channel LTM EXAM SOLUTIONS (@coding_are) in the English language segment is an active participant. Currently, the community unites 14 105 subscribers, ranking 14 118 in the Education category and 28 127 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 14 105 subscribers.

According to the latest data from 04 October, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -108 over the last 30 days and by -5 over the last 24 hours, overall reach remains high.

Verification status: Not verified
Engagement rate (ER): The average audience engagement rate is 3.62%. Within the first 24 hours after publication, content typically collects 1.74% reactions from the total number of subscribers.
Post reach: On average, each post receives 511 views. Within the first day, a publication typically gains 246 views.
Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
Thematic interests: Content is focused on key topics such as placement, gaurntee, suree, capgemini, infosy.

📝 Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
“🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...”

Thanks to the high frequency of updates (latest data received on 05 October, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

14 100

Subscribers

-524 hours

-247 days

-10830 days

511

Post views

~ 24624 hours

~ 30448 hours

3.62%

Engagement rate

~ 4

Posts per day

Ads index

beta

Posts Archive

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Tech Mahindra exam successfully done by remote access ✅✅✅ All MCQ done with 💯 Correct answer ✅✅ Essays done ✅✅.. Contact for placement exam @srksvk

14 100

Tech Mahindra exam successfully done by remote access ✅✅✅ All MCQ done with 💯 Correct answer ✅✅ Essays done ✅✅.. Contact for placement exam @srksvk

14 100

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Cognizant csd exam,(python or java), Tech Mahindra ✅ All companies interview support help available 🔥 Contact fast and book your slots Contact @srksvk.. 💯% suree clearance guarantee Remote access also available

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Ibm help successfully done by remote access ✅✅ Both code fully passed🔥🔥 🔥 Contact for placement exam @srksvk

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Tech Mahindra exam help available ✅ Contact fast and book your slots Contact @srksvk

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Note: limited slot available

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Infosys pre training exam successfully done by remote access ✅✅✅✅✅

2/2 codes successfully executed with all tests caes passed ✅

✅ 25/25 MCQ done with 💯% correct answer ✅✅ Contact for placement exam @srksvk

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String shuffle done ✅✅ Infosys pre onboarding ✅

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Number from string code ✅✅✅ Infosys pre training ✅✅✅

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Final call for Infosys pre onboarding exam help available Contact fast @srksvk

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Remote access also available

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ADP exam successfully done by remote access ✅ ✅✅ 8

70/70 MCQ done with all 💯 Correct answer ✅✅

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Those who need help in Infosys pre onboarding exam help available Contact fast @srksvk 💯% clearance guarantee 🔥 Remote access available Note: one slot left only

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Goldman Sachs exam successfully done by remote access ✅✅✅✅✅

All code executed with all the tests caes passed ✅✅✅

Contact for placement exam @srksvk

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def is_modest(number): str_num = str(number) length = len(str_num) for i in range(1, length): left_part = int(str_num[:i]) right_part = int(str_num[i:]) if right_part != 0 and number % right_part == left_part: return True return False def find_modest_numbers(M, N): modest_numbers = [] for number in range(M, N + 1): if is_modest(number): modest_numbers.append(number) return modest_numbers M, N = map(int, input().split()) modest_numbers = find_modest_numbers(M, N) if modest_numbers: print(" ".join(map(str, modest_numbers))) else: print("No modest numbers found within the range")

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Card game ✅