LTM EXAM SOLUTIONS

Kanalga Telegram’da o‘tish

🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

Ko'proq ko'rsatish

Hindiston28 127 Taʼlim14 118...

📈 Telegram kanali LTM EXAM SOLUTIONS analitikasi

LTM EXAM SOLUTIONS (@coding_are) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 14 093 obunachidan iborat bo'lib, Taʼlim toifasida 14 118-o'rinni va Hindiston mintaqasida 28 127-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 14 093 obunachiga ega bo‘ldi.

04 Oktabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -108 ga, so‘nggi 24 soatda esa -5 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

Tasdiqlash holati: Tasdiqlanmagan
Jalb etish (ER): Auditoriya o‘rtacha 3.62% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.74% ini tashkil etuvchi reaksiyalarni to‘playdi.
Post qamrovi: Har bir post o‘rtacha 511 marta ko‘riladi; birinchi sutkada odatda 246 ta ko‘rish yig‘iladi.
Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 2 ta reaksiya keladi.
Tematik yo‘nalishlar: Kontent placement, gaurntee, suree, capgemini, infosy kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...”

Yuqori yangilanish chastotasi (oxirgi ma’lumot 05 Oktabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

14 100

Obunachilar

-524 soatlar

-247 kun

-10830 kun

511

Post ko'rishlar

~ 24624 soatlar

~ 30448 soatlar

3.62%

Muloqot nisbati

~ 4

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def is_modest(number): str_num = str(number) length = len(str_num) for i in range(1, length): left_part = int(str_num[:i]) right_part = int(str_num[i:]) if right_part != 0 and number % right_part == left_part: return True return False def find_modest_numbers(M, N): modest_numbers = [] for number in range(M, N + 1): if is_modest(number): modest_numbers.append(number) return modest_numbers M, N = map(int, input().split()) modest_numbers = find_modest_numbers(M, N) if modest_numbers: print(" ".join(map(str, modest_numbers))) else: print("No modest numbers found within the range")

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